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anonymous
 3 years ago
(1+cos3t)/(sin3t)+(sin3t)/(1+cos3t)=2csc3t
anonymous
 3 years ago
(1+cos3t)/(sin3t)+(sin3t)/(1+cos3t)=2csc3t

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 1+\cos3t }{ \sin3t }+\frac{ \sin3t }{ 1+\cos3t }= 2\csc3t\] what do you want? prove it?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes please, im having the hardest time with these questions...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I give you idea, you do the rest. the first part \[\frac{ 1+\cos3t }{ \sin3t }= \frac{ 1 }{ \sin3t }+ \frac{ \cos3t }{ \sin3t }= \csc 3t + \cot 3t\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no go, have no idea what is next

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0That is pretty much it. You know what cot(x) is equal to? Also what is csc(x) equal to.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what else for cotx? there should be one more

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0now look at the first step, do you see something similar to what you said

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you said cotx = cosx/sinx and you said cscx=1/sinx right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes and that is what we converted into part of the original problem

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok I give you mine : from yours , right side = 2/ sin3t. write it out

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0now I just prove that left side * sin 2t =2, right? it is easy to do

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\sin 3t \left[ \frac{ 1 + cost 3t }{ \sin3t } +\frac{ \sin3t }{ 1 + \cos 3t } \right]\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[= \frac{ \sin 3t + \cos 3t }{ \sin3t }+ \frac{ \sin^2 3t }{ 1 + \cos 3t }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok, how did we get from csc3t+cot3t+sin3t/1+cos3t to what you writing now?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[= (\frac{ sint }{ \sin3t }+ \frac{ \sin3tcos3t }{ \sin3t }+ \frac{ 1\cos^2 3t }{1+\cos 3t })\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[=1+ \cos 3t + \frac{ (1+\cos3t)(1\cos3t) }{ 1+\cos 3t }\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and then you have 1+1 =2. the proof done. is it clear?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I make the right side2 csc 3t = 2/ sin3t. and then time both sides to sin 3t

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0do you get mine? think of it. write out and it will make sense to you.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok let me look at it and see, im still not sure why we did the very first step as we ended up working out the original set up

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0our goal is prove the original equation is true, that means you must prove the left side = right side. some equation is not true at all, for example : how can you prove 1+1 =3? fortunately, your problem is prove it true, that means it is true already, just explain in which logic, it is true. done

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok, let me work it out on paper and see what I come up with. Thanks for your help.
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