anonymous
  • anonymous
(1+cos3t)/(sin3t)+(sin3t)/(1+cos3t)=2csc3t
Trigonometry
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
\[\frac{ 1+\cos3t }{ \sin3t }+\frac{ \sin3t }{ 1+\cos3t }= 2\csc3t\] what do you want? prove it?
anonymous
  • anonymous
yes please, im having the hardest time with these questions...
anonymous
  • anonymous
I give you idea, you do the rest. the first part \[\frac{ 1+\cos3t }{ \sin3t }= \frac{ 1 }{ \sin3t }+ \frac{ \cos3t }{ \sin3t }= \csc 3t + \cot 3t\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
ok let me look at it
anonymous
  • anonymous
no go, have no idea what is next
anonymous
  • anonymous
That is pretty much it. You know what cot(x) is equal to? Also what is csc(x) equal to.
anonymous
  • anonymous
cotx=1/tanx
anonymous
  • anonymous
cscx=1/sinx
anonymous
  • anonymous
what else for cotx? there should be one more
anonymous
  • anonymous
cosx/sinx
anonymous
  • anonymous
now look at the first step, do you see something similar to what you said
anonymous
  • anonymous
sorry you lost me...
anonymous
  • anonymous
you said cotx = cosx/sinx and you said cscx=1/sinx right?
anonymous
  • anonymous
yes and that is what we converted into part of the original problem
anonymous
  • anonymous
ok I give you mine : from yours , right side = 2/ sin3t. write it out
anonymous
  • anonymous
now I just prove that left side * sin 2t =2, right? it is easy to do
anonymous
  • anonymous
\[\sin 3t \left[ \frac{ 1 + cost 3t }{ \sin3t } +\frac{ \sin3t }{ 1 + \cos 3t } \right]\]
anonymous
  • anonymous
\[= \frac{ \sin 3t + \cos 3t }{ \sin3t }+ \frac{ \sin^2 3t }{ 1 + \cos 3t }\]
anonymous
  • anonymous
ok, how did we get from csc3t+cot3t+sin3t/1+cos3t to what you writing now?
anonymous
  • anonymous
\[= (\frac{ sint }{ \sin3t }+ \frac{ \sin3tcos3t }{ \sin3t }+ \frac{ 1-\cos^2 3t }{1+\cos 3t })\]
anonymous
  • anonymous
\[=1+ \cos 3t + \frac{ (1+\cos3t)(1-\cos3t) }{ 1+\cos 3t }\]
anonymous
  • anonymous
and then you have 1+1 =2. the proof done. is it clear?
anonymous
  • anonymous
I make the right side2 csc 3t = 2/ sin3t. and then time both sides to sin 3t
anonymous
  • anonymous
do you get mine? think of it. write out and it will make sense to you.
anonymous
  • anonymous
ok let me look at it and see, im still not sure why we did the very first step as we ended up working out the original set up
anonymous
  • anonymous
our goal is prove the original equation is true, that means you must prove the left side = right side. some equation is not true at all, for example : how can you prove 1+1 =3? fortunately, your problem is prove it true, that means it is true already, just explain in which logic, it is true. done
anonymous
  • anonymous
ok, let me work it out on paper and see what I come up with. Thanks for your help.
anonymous
  • anonymous
you are welcome

Looking for something else?

Not the answer you are looking for? Search for more explanations.