A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
At the head table at a banquet are seated two senators, two governors, and three mayors. Find the number of ways in which these seven people can be seated under the conditions described: A mayor is at each end and the senators are in consecutive seats
anonymous
 3 years ago
At the head table at a banquet are seated two senators, two governors, and three mayors. Find the number of ways in which these seven people can be seated under the conditions described: A mayor is at each end and the senators are in consecutive seats

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1361848754746:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0lots of applications of the counting principle two choices for mayor

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0ok so how will u do the senators?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh i read it wrong, sorry

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0label the seats 1 to 7 then senators can be in seats 2, 3 3, 4 4, 5 5, 6 and they can switch chairs between them, so there are 8 possibilities for the senators

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0seat number 1 and 7 must contain mayors, so there are \(3\times 2=6\) choices for seat 1 and 7

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0then you have 3 chairs left to fill , and 3 people left to sit, so they are \(3\times 2=6\) choices for the remaining 3 chairs

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0multiply all these choices together, and unless i screwed up you get the right answer

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.1I do not see how the answer can only be 12.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0well i guess order doesn't matter i nthnis case

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yea its 12... hey can u just help me on this question? how many committees of four can be chosen from twelve students? how many of these will include a given student? how many will exclude a given student?

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.1It's a comination problem so 12 choose 4

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes what about the last two questions?

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.1If we want to include a given student, we have already made one choice so we now must choose3 students from the remaining 11

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.1So I think it would be 11 choose 3

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.1I'm not really very good with probability.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you have to multiply all the choices together, as i wrote above

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0unless i screwed up, it should be \(8\times 6\times 6\)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.