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JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
Let's start with Keplers laws
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
Let's see what I remember without looking at my cheat sheet
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
Something about \[T^2=R^3\]
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
seems like I forgot Kepler laws ... let's see
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
The period of an object orbital around the sun is proportional to the radius?
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
whose radius? or perhaps some distance? The distance between that object and the sun?
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
http://en.wikipedia.org/wiki/Kepler's_laws_of_planetary_motion ellipse ... semi major axis.
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
no cheating haha
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
draw it with medw:1361862577312:dw
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
dw:1361862616815:dw
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
Let's see what I remember about the semi major axis.......
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
\[\LARGE (\frac{T_1}{T_2})^2=(\frac{R_1}{R_2})^3\]
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
\[\LARGE \frac{dA}{dT}=\frac{L}{2M}\]
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
why do we have two semi major axis?
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
what ratio is that?
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
it doesn't matter which side you take ... lol
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
dw:1361862832161:dw
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
dw:1361862878591:dw Where is \(R_2\)
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
http://en.wikipedia.org/wiki/Semimajor_axis
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
>:O
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
wiki didn't explain the ratio though
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
LOL I'm tired. ok I get it
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
Let's talk about escape speed
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
\[\LARGE \sqrt{2gR}\]
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
dw:1361863110279:dw sweetheart, I have all the formulas staring at me from my notebook. I'm trying to have a discussion about those wonderful formulas
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
something about when the kinetic energy reaches \(\frac{GMm}{r^2}\)?
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
dw:1361863195805:dw
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
THanks! When do we know we have reached escape speed? \[U_f+K_f=U_i+K_i\] Let's derive escape speed. we don't have a final kinetic energy when we've reached escape speed correct?
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{GMm}{R}+\frac{mv^2}{2}=0\]
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
put the total energy=0 find V
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
Why what's the logic behind it? WHy is the total energy zero?
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
If a body's total net mec. energy=0,it will escape from the earth's gravitational field
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
find the total work done when bringing object from infinity to position 'r'
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
oh ok, so when the kinetic energy equals the potential energy?
 one year ago

DLS Group TitleBest ResponseYou've already chosen the best response.0
have u heard of binding energy
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
Let's see if I remember. When E<0 or =0
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
parabolic and hyperbolic orbits?
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
that's when they're unbound correct?
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
nope when E>0 is unbound
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
when E is less than zero is the only time when it's bound
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
So when the potential is greater than the kinetic energy the energy is bound?
 one year ago

JenniferSmart1 Group TitleBest ResponseYou've already chosen the best response.0
gotta sleep =) Thanks for the discussion everyone. I look forward to hear more about bounded and unbounded Energy when I wake up. See ya :)
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
sorry ... was kinda busy not paying attention
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
this way you can do it ... for escape velocity. dw:1361863974972:dw
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
You can equate those two, and hence get the result ...
 one year ago

experimentX Group TitleBest ResponseYou've already chosen the best response.1
I think ... if the velocity is less than esc velocity, the orbit will be elliptical or circular at escape velocity, the orbit is parabolic, and beyond that .... it's hyperbolic.
 one year ago
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