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PaulinePar
 2 years ago
Can you guys identify the quadric surface using completing the squares of this equation. x^2+4y^26x+8y+4z=0? Thankyou :))
PaulinePar
 2 years ago
Can you guys identify the quadric surface using completing the squares of this equation. x^2+4y^26x+8y+4z=0? Thankyou :))

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sirm3d
 2 years ago
Best ResponseYou've already chosen the best response.0x^2 6x +y^2 + 8y = 4z x^26x+9 + y^2+8y+16=4z+25 (x3)^2 + (y+4)^2=4(z25/4) it is a paraboloid of revolution, with vertex at (3,4,25/4)

PaulinePar
 2 years ago
Best ResponseYou've already chosen the best response.0where is 4y^2 in the first equation?

PaulinePar
 2 years ago
Best ResponseYou've already chosen the best response.0its ok hehe .. but where did you get 9 and 16 in the 2nd equation?

PaulinePar
 2 years ago
Best ResponseYou've already chosen the best response.0sir how can i sketch the level curve z=k for the specified values of k. this is the equation z=x^2+y; k=2, 1, 0, 1, 2

sirm3d
 2 years ago
Best ResponseYou've already chosen the best response.0completing squares, my dear. \[x^2+4y^26x+8y+4z=0\\(x^26x+9)+4(y^2+2y+1)=4z+9+4\\(x3)^2+4(y+1)^2=4(z\tfrac{13}{4})\\\frac{(x3)^2}{4}+\frac{(y+1)^2}{1}=\frac{z\tfrac{13}{4}}{1}\]

PaulinePar
 2 years ago
Best ResponseYou've already chosen the best response.0Thank you so much :)) nakalimutan ko na po kc hehehe .. Yung another question ko po help naman po.

PaulinePar
 2 years ago
Best ResponseYou've already chosen the best response.0Sir thank you so much po sa lahat ng response nyo. sa lahat ng help nyo :))

sirm3d
 2 years ago
Best ResponseYou've already chosen the best response.0it is not a paraboloid of revolution as i said in my previous post. it is an elliptic paraboloid
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