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Can you guys identify the quadric surface using completing the squares of this equation. x^2+4y^26x+8y+4z=0? Thankyou :))
 one year ago
 one year ago
Can you guys identify the quadric surface using completing the squares of this equation. x^2+4y^26x+8y+4z=0? Thankyou :))
 one year ago
 one year ago

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sirm3dBest ResponseYou've already chosen the best response.0
x^2 6x +y^2 + 8y = 4z x^26x+9 + y^2+8y+16=4z+25 (x3)^2 + (y+4)^2=4(z25/4) it is a paraboloid of revolution, with vertex at (3,4,25/4)
 one year ago

PaulineParBest ResponseYou've already chosen the best response.0
where is 4y^2 in the first equation?
 one year ago

PaulineParBest ResponseYou've already chosen the best response.0
its ok hehe .. but where did you get 9 and 16 in the 2nd equation?
 one year ago

PaulineParBest ResponseYou've already chosen the best response.0
sir how can i sketch the level curve z=k for the specified values of k. this is the equation z=x^2+y; k=2, 1, 0, 1, 2
 one year ago

sirm3dBest ResponseYou've already chosen the best response.0
completing squares, my dear. \[x^2+4y^26x+8y+4z=0\\(x^26x+9)+4(y^2+2y+1)=4z+9+4\\(x3)^2+4(y+1)^2=4(z\tfrac{13}{4})\\\frac{(x3)^2}{4}+\frac{(y+1)^2}{1}=\frac{z\tfrac{13}{4}}{1}\]
 one year ago

PaulineParBest ResponseYou've already chosen the best response.0
Thank you so much :)) nakalimutan ko na po kc hehehe .. Yung another question ko po help naman po.
 one year ago

PaulineParBest ResponseYou've already chosen the best response.0
Sir thank you so much po sa lahat ng response nyo. sa lahat ng help nyo :))
 one year ago

sirm3dBest ResponseYou've already chosen the best response.0
it is not a paraboloid of revolution as i said in my previous post. it is an elliptic paraboloid
 one year ago
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