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 one year ago
Can you guys identify the quadric surface using completing the squares of this equation. x^2+4y^26x+8y+4z=0? Thankyou :))
 one year ago
Can you guys identify the quadric surface using completing the squares of this equation. x^2+4y^26x+8y+4z=0? Thankyou :))

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sirm3d
 one year ago
Best ResponseYou've already chosen the best response.0x^2 6x +y^2 + 8y = 4z x^26x+9 + y^2+8y+16=4z+25 (x3)^2 + (y+4)^2=4(z25/4) it is a paraboloid of revolution, with vertex at (3,4,25/4)

PaulinePar
 one year ago
Best ResponseYou've already chosen the best response.0where is 4y^2 in the first equation?

PaulinePar
 one year ago
Best ResponseYou've already chosen the best response.0its ok hehe .. but where did you get 9 and 16 in the 2nd equation?

PaulinePar
 one year ago
Best ResponseYou've already chosen the best response.0sir how can i sketch the level curve z=k for the specified values of k. this is the equation z=x^2+y; k=2, 1, 0, 1, 2

sirm3d
 one year ago
Best ResponseYou've already chosen the best response.0completing squares, my dear. \[x^2+4y^26x+8y+4z=0\\(x^26x+9)+4(y^2+2y+1)=4z+9+4\\(x3)^2+4(y+1)^2=4(z\tfrac{13}{4})\\\frac{(x3)^2}{4}+\frac{(y+1)^2}{1}=\frac{z\tfrac{13}{4}}{1}\]

PaulinePar
 one year ago
Best ResponseYou've already chosen the best response.0Thank you so much :)) nakalimutan ko na po kc hehehe .. Yung another question ko po help naman po.

PaulinePar
 one year ago
Best ResponseYou've already chosen the best response.0Sir thank you so much po sa lahat ng response nyo. sa lahat ng help nyo :))

sirm3d
 one year ago
Best ResponseYou've already chosen the best response.0it is not a paraboloid of revolution as i said in my previous post. it is an elliptic paraboloid
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