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ETIM

  • 3 years ago

find the dy/dx of y=10^logx

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  1. wintry
    • 3 years ago
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    \[\log x = \log_{10} x\], is it true? If so, y=x, then dy\dx=1, for x>0

  2. wio
    • 3 years ago
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    Take natural log of both sides. Implicitly differentiate \((\ln(y))' = y'/y\). Substitute back in \(y=10^{\log(x)}\)

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