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wintryBest ResponseYou've already chosen the best response.0
\[\log x = \log_{10} x\], is it true? If so, y=x, then dy\dx=1, for x>0
 one year ago

wioBest ResponseYou've already chosen the best response.0
Take natural log of both sides. Implicitly differentiate \((\ln(y))' = y'/y\). Substitute back in \(y=10^{\log(x)}\)
 one year ago
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