ETIM Group Title find the dy/dx of y=10^logx one year ago one year ago

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1. wintry

$\log x = \log_{10} x$, is it true? If so, y=x, then dy\dx=1, for x>0

2. wio

Take natural log of both sides. Implicitly differentiate $$(\ln(y))' = y'/y$$. Substitute back in $$y=10^{\log(x)}$$