## anonymous 3 years ago find the dy/dx of y=10^logx

• This Question is Open
1. anonymous

$\log x = \log_{10} x$, is it true? If so, y=x, then dy\dx=1, for x>0

2. anonymous

Take natural log of both sides. Implicitly differentiate $$(\ln(y))' = y'/y$$. Substitute back in $$y=10^{\log(x)}$$