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look at this diagram

|dw:1361876285295:dw|

I dunno if that is right.

I don't know Physics. Can anyone help @abc9837?

or it would be h (max) the top point of projectile

what u all think about this!!..

It means exactly what it says.

Oh sorry : R = \(\large{\frac{u^2 \sin 2\theta}{g}}\)

OK, we are assuming \(g = 9.8 ~m/s^2\)

No, \(9.81\)

ok

|dw:1361877650810:dw|

\[500 = \dfrac{u^2 }{9.81}\]

\[u = \sqrt{500 \cdot 9.81}\]

that will come approx. u = 50 root 2 or 70.7 [ i took g = 10 m/s^2 ]

and if we take g = 9.81 then it is u = 70.03 m/s

I think you two are making this way more complicated

Answer is zero.

I get it as 125 ft. (aprox.)

and exactly it is 124.9

one unit is in meter and the other is in ft
can you reconcile this?

38.069 meters

oh fishy
what else i wrote in my first reply man!!!
@parthkohli

but, seriously,
|dw:1367318591146:dw|

lulz

hey now...