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Misty92

  • one year ago

True lengths of 5 cut pieces of string having these length in inches: 2.9, 9.5,5.7,4.2,7.6 A subject measure each length twice by eye. Make up a set of results from this activity that matches each of the description below. For simplicity, assume that bias means the same fixed error every time rather than an "on average" error in many measurements. Q: The subject has a bias of 0.5 inches too long is perfectly reliable

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  1. Misty92
    • one year ago
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    [measure length= true length + bias + random error]

  2. UnkleRhaukus
    • one year ago
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    measuring length by eye is strange

  3. Misty92
    • one year ago
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    not sure but would it just be measure value= 2.9+0.5+0 thus solving for measure value it would be 2.4 the set of new results then would be 2.9,9.0, 5.7, 3.7, 7.1?

  4. UnkleRhaukus
    • one year ago
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    i dont really understand the wording of the question,

  5. Misty92
    • one year ago
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    using the true value of the 5 pieces of cut string 2.9, 9.5, 5.7, 4.2, 7.6 which are all in inches it says create a new set of numbers if the subject has a bias of 0.5 inch too long and is perfectly reliable

  6. Misty92
    • one year ago
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    1. A student cuts five pieces of string having the following lengths in inches: 2.9, 9.5, 5.7, 4.2, 7.6 Then the students showed the pieces to another student one at a time, asking the subject to estimate the length to the nearest tenth of an inch by eye. The error made by the subject is measured value minus true value and can be either positive or negative. What will be the results obtained from the subject, if the subject has a bias of 0.5 inch too long and is perfectly reliable? Choose one: A. 3.4, 10.0, 6.2, 4.7, 8.1 B. 3.4, 10.1, 6.3, 4.6, 8.6 C.2.4, 9.0, 5.2, 3.7, 7.1

  7. UnkleRhaukus
    • one year ago
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    ah , so the bias is 0.5 too long you have to add 0.5 to each measurement 2.9, 9.5, 5.7, 4.2, 7.6 \(\to\)2.9+0.5, 9.5+0.5, 5.7+0.5, 4.2+0.5, 7.6+0.5

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