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Sceptre12 Group Title

an = an−1 + 3an−2, a0 = 1, a1 = 2

  • one year ago
  • one year ago

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  1. ZeHanz Group Title
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    What do you have to do with this sequence?

    • one year ago
  2. ZeHanz Group Title
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    Maybe it's clearer to write it as: \[a_n=a_{n-1}+3a_{n-2}\]\[a_0=1,a_1=2\]

    • one year ago
  3. Sceptre12 Group Title
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    its a recursive sequence

    • one year ago
  4. Sceptre12 Group Title
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    Yeah sorry

    • one year ago
  5. Sceptre12 Group Title
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    im trying to figure it out because the way i keep solving it is apparently wrong by the book

    • one year ago
  6. ZeHanz Group Title
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    Yes, I see that, but what is your question about it? Do you need terms of this sequence?

    • one year ago
  7. Sceptre12 Group Title
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    yes how do you solve it

    • one year ago
  8. ZeHanz Group Title
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    It says: If you want to know a certain number of this sequence, you need the two numbers before it. Take the last number and add 3 times the number before it to get the new one. That is why there are two start numbers given.\[a_2=a_1+3a_0\]\[a_3=a_2+3a_1\]So you can calculate every number in the sequence. I don't understand what you mean by solve it.

    • one year ago
  9. Sceptre12 Group Title
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    Okay so if i was to do it like that then .. a2 = 2 + 3(1) = 5 right?

    • one year ago
  10. ZeHanz Group Title
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    OK

    • one year ago
  11. Sceptre12 Group Title
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    and a3 = 5 + 2 = 7

    • one year ago
  12. Sceptre12 Group Title
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    is that right or wrong because my book says im wrong

    • one year ago
  13. ZeHanz Group Title
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    You are, because it is 5 + 3*2 = 11

    • one year ago
  14. Sceptre12 Group Title
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    ohh true

    • one year ago
  15. Sceptre12 Group Title
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    sorry about that last part but the book says

    • one year ago
  16. Sceptre12 Group Title
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    dont worry i see the mistake

    • one year ago
  17. Sceptre12 Group Title
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    lol i never took into consideration a0 and a1 as being apart of the answer so i was so confused as to how they got 1,2,5, then 11 lol

    • one year ago
  18. ZeHanz Group Title
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    So a4 = 11 + 3*5 = 26 a5= 26 + 3*11 = 59 etc.

    • one year ago
  19. Sceptre12 Group Title
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    thank you lol

    • one year ago
  20. ZeHanz Group Title
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    YW! a0 and a1 are needed to give you a way to "start up"..

    • one year ago
  21. Sceptre12 Group Title
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    yea

    • one year ago
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