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iiamentertainment

  • one year ago

What is an equation of a parabola with the given vertex and focus? vertex: (–2, 5); focus: (–2, 6) Walk Me Through Please !

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  1. iiamentertainment
    • one year ago
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    @ParthKohli

  2. amistre64
    • one year ago
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    it always helps me to start drawing a picture with the information.

  3. amistre64
    • one year ago
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    |dw:1361894247395:dw|

  4. amistre64
    • one year ago
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    so the distance from focus to vertex is 1 and i know that this will take the form (y-5)= n(x+2^2 to solve for n, we can calibrate it with the extra point that is located to the side of the focus

  5. amistre64
    • one year ago
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    |dw:1361894396088:dw|

  6. amistre64
    • one year ago
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    since a = 1, -2+2a = 0 n = (y-5)/(x+2)^2 n = (6-5)/(0+2)^2 n = 1/4

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