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 one year ago
cansomeone show me how to solve this? Use the quadratic formula to find the zeros of the function. y = 16x2 + 40x + 25
{1.25, 1.25}
{1.25}
{4, 5}
{0.8
 one year ago
cansomeone show me how to solve this? Use the quadratic formula to find the zeros of the function. y = 16x2 + 40x + 25 {1.25, 1.25} {1.25} {4, 5} {0.8

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amistre64
 one year ago
Best ResponseYou've already chosen the best response.1do you recall the setup of the quadratic formula?

EmmaH
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ b \pm \sqrt{b ^{2}4ac} }{ 2a }\]

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1good, and the general form of a quadratic is: \[ax^2 + bx + c\] pull the numbers from the problem that relate to the abc parts and what do you get worked out?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1good, i notice that there are no  signs to worry about so that looks good so far

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1plug in those numbers into their abc parts in the formula, the rest is just math for maths sake

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1\[x=\frac{ b \pm \sqrt{b ^{2}4ac} }{ 2a }\] \[x=\frac{ 40 \pm \sqrt{40^{2}4(16)(25)} }{ 2(16) }\]

EmmaH
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 40\pm \sqrt{40^{2}4(16)(25)} }{ 2(16) }\] is that right?

EmmaH
 one year ago
Best ResponseYou've already chosen the best response.0ok then i get 40 pm 1696/32?

EmmaH
 one year ago
Best ResponseYou've already chosen the best response.0but i would end up eith a negative number....

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ 40\pm \sqrt{40^{2}4(16)(25)} }{ 2(16) }\] \[\frac{ 40\pm \sqrt{4^2(10)^24(4^2)(25)} }{ 2(16) }\] \[\frac{ 40\pm 4\sqrt{10^24(25)} }{ 2(16) }\] \[\frac{ 40\pm 4\sqrt{25(4)4(25)} }{ 2(16) }\] \[\frac{ 40}{ 2(16) }\] \[\frac{ 40}{ 2(4.4) }\] \[\frac{ 10}{ 2(4) }\] \[\frac{ 5}{ 4 }\]

EmmaH
 one year ago
Best ResponseYou've already chosen the best response.0you lost me at the second one you did how did you get all the the ^2?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.140^2 = (4*10)^2 = 4*10 * 4*10 = 4^2 * 10^2 but you dont have to do exactly what i did

EmmaH
 one year ago
Best ResponseYou've already chosen the best response.0uuuuh.....im sorry you lost me all i know is im suppose to square 40 is that what you were doin?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1i was doing some manipulations so that i didnt have to worry about computing large numbers and such; i simplified it down to where i recognized the sqrt part goes to zero.

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1but 40^2  4(16)(25) = 0

EmmaH
 one year ago
Best ResponseYou've already chosen the best response.0ui havent learned taht i think im suppose to just use the big numbers

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1then math it out for maths sake, youll get big numbers that finally reduce and simplify

EmmaH
 one year ago
Best ResponseYou've already chosen the best response.0i tried but i keep getting teh wrong number when i have 40^24(16)(5) i get 0 right? i get 1,600 1,600 and i cant square thaty

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1what does 1600  1600 equal?

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1sure you can, 0*0 = 0

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1\[\frac{ 40\pm \sqrt{40^{2}4(16)(25)} }{ 2(16) }\] \[\frac{ 40\pm \sqrt{16001600} }{ 2(16) }\] \[\frac{ 40\pm \sqrt{0} }{ 2(16) }\] \[\frac{ 40\pm 0 }{ 2(16) }\] \[\frac{ 40}{ 2(16) }\]

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1yes /32 is fine as well

amistre64
 one year ago
Best ResponseYou've already chosen the best response.1yes, which a calculator should be able to put into decimals for you
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