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 2 years ago
cansomeone show me how to solve this? Use the quadratic formula to find the zeros of the function. y = 16x2 + 40x + 25
{1.25, 1.25}
{1.25}
{4, 5}
{0.8
 2 years ago
cansomeone show me how to solve this? Use the quadratic formula to find the zeros of the function. y = 16x2 + 40x + 25 {1.25, 1.25} {1.25} {4, 5} {0.8

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amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1do you recall the setup of the quadratic formula?

EmmaH
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ b \pm \sqrt{b ^{2}4ac} }{ 2a }\]

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1good, and the general form of a quadratic is: \[ax^2 + bx + c\] pull the numbers from the problem that relate to the abc parts and what do you get worked out?

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1good, i notice that there are no  signs to worry about so that looks good so far

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1plug in those numbers into their abc parts in the formula, the rest is just math for maths sake

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1\[x=\frac{ b \pm \sqrt{b ^{2}4ac} }{ 2a }\] \[x=\frac{ 40 \pm \sqrt{40^{2}4(16)(25)} }{ 2(16) }\]

EmmaH
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 40\pm \sqrt{40^{2}4(16)(25)} }{ 2(16) }\] is that right?

EmmaH
 2 years ago
Best ResponseYou've already chosen the best response.0ok then i get 40 pm 1696/32?

EmmaH
 2 years ago
Best ResponseYou've already chosen the best response.0but i would end up eith a negative number....

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1\[\frac{ 40\pm \sqrt{40^{2}4(16)(25)} }{ 2(16) }\] \[\frac{ 40\pm \sqrt{4^2(10)^24(4^2)(25)} }{ 2(16) }\] \[\frac{ 40\pm 4\sqrt{10^24(25)} }{ 2(16) }\] \[\frac{ 40\pm 4\sqrt{25(4)4(25)} }{ 2(16) }\] \[\frac{ 40}{ 2(16) }\] \[\frac{ 40}{ 2(4.4) }\] \[\frac{ 10}{ 2(4) }\] \[\frac{ 5}{ 4 }\]

EmmaH
 2 years ago
Best ResponseYou've already chosen the best response.0you lost me at the second one you did how did you get all the the ^2?

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.140^2 = (4*10)^2 = 4*10 * 4*10 = 4^2 * 10^2 but you dont have to do exactly what i did

EmmaH
 2 years ago
Best ResponseYou've already chosen the best response.0uuuuh.....im sorry you lost me all i know is im suppose to square 40 is that what you were doin?

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1i was doing some manipulations so that i didnt have to worry about computing large numbers and such; i simplified it down to where i recognized the sqrt part goes to zero.

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1but 40^2  4(16)(25) = 0

EmmaH
 2 years ago
Best ResponseYou've already chosen the best response.0ui havent learned taht i think im suppose to just use the big numbers

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1then math it out for maths sake, youll get big numbers that finally reduce and simplify

EmmaH
 2 years ago
Best ResponseYou've already chosen the best response.0i tried but i keep getting teh wrong number when i have 40^24(16)(5) i get 0 right? i get 1,600 1,600 and i cant square thaty

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1what does 1600  1600 equal?

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1sure you can, 0*0 = 0

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1\[\frac{ 40\pm \sqrt{40^{2}4(16)(25)} }{ 2(16) }\] \[\frac{ 40\pm \sqrt{16001600} }{ 2(16) }\] \[\frac{ 40\pm \sqrt{0} }{ 2(16) }\] \[\frac{ 40\pm 0 }{ 2(16) }\] \[\frac{ 40}{ 2(16) }\]

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1yes /32 is fine as well

amistre64
 2 years ago
Best ResponseYou've already chosen the best response.1yes, which a calculator should be able to put into decimals for you
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