anonymous
  • anonymous
Find the exact value of the function sec(17pi/6).. also drawn inside. :) ***please explain and show steps!! thank youu :)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
|dw:1361912361352:dw|
anonymous
  • anonymous
here is what i have... idk if it is right though... what do u think? is it correct? :/ |dw:1361912525340:dw| is that right??? :/
anonymous
  • anonymous
@jim_thompson5910 :) what do u think?? :D

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jim_thompson5910
  • jim_thompson5910
From there you can rationalize the denominator |dw:1361912794736:dw|
anonymous
  • anonymous
or is it supposed to be (-2/sq.rt.(3))/3 ??? :/
jim_thompson5910
  • jim_thompson5910
but what you have is more or less correct
jim_thompson5910
  • jim_thompson5910
that's the same thing...just a bit more convoluted
jim_thompson5910
  • jim_thompson5910
I would just go with |dw:1361913060716:dw|
anonymous
  • anonymous
okay, so my steps are all right?? but the answer is just -2 sw.rt. 3 / 3 instead of -2/sq.rt. 3??
anonymous
  • anonymous
and thats the final answer?? @jim_thompson5910 ?? :/
anonymous
  • anonymous
@jim_thompson5910 so the final answer would just be what you drew above? and the steps i did earlier are correct??? ;/
jim_thompson5910
  • jim_thompson5910
yes the final answer is |dw:1361941352439:dw| and your steps are correct
anonymous
  • anonymous
okay!! awesome :) thanks a bunch!!! :D
jim_thompson5910
  • jim_thompson5910
yw
anonymous
  • anonymous
Consider the right triangle ABC that is attached... a. What is the length of the hypotenuse of triangle ABC? b. What is the length of the shorter leg of triangle ABC?
jim_thompson5910
  • jim_thompson5910
where are the letters A, B, C?
anonymous
  • anonymous
it doesn't say :/ thats what i was thinking also... cuz aren't they usually labeled? :/
jim_thompson5910
  • jim_thompson5910
there are 3 triangles so I have no idea which triangle they're referring to
anonymous
  • anonymous
is there any way you can assume where A, B, C are labeled?? cuz its a 30-60-90 triangle right?? one of the special triangles? :/ ***tho i don't quite remember the rule it has... :/
jim_thompson5910
  • jim_thompson5910
yeah but where do they go and which point is left out?
jim_thompson5910
  • jim_thompson5910
are you sure it's not labeled?
anonymous
  • anonymous
yeah its not labeled.. :/ its kinda weird... then can we do this then?? ill ask my teacher tomorrow about it and then i will reply back over here ?? would that work? :)
anonymous
  • anonymous
**reply back here after i find out the labels?
jim_thompson5910
  • jim_thompson5910
sure that will work
anonymous
  • anonymous
okay hahaa :) thanks!! i will be back sometime tomorrow then!!! **if i can get online tomorrow night!!!*** hehe thankssss :)
jim_thompson5910
  • jim_thompson5910
sure thing
anonymous
  • anonymous
okay... :) so i just asked my teacher and she said that the entire big triangle is ABC and she gave me a hint also!! :) she said that you will be finding the hypotenuse and the length of the leg by the angles given.. :/ but yeah! The HUGE triangle is triangle ABC :)
anonymous
  • anonymous
anddd idk how to do it tho... I'm still a bit confused on this whole process :/ :(
jim_thompson5910
  • jim_thompson5910
|dw:1362021818496:dw|
anonymous
  • anonymous
hiiiiii :)
anonymous
  • anonymous
do u get it?? :/ cuz iheartfood is mucho confused :(
jim_thompson5910
  • jim_thompson5910
|dw:1362021987081:dw|
jim_thompson5910
  • jim_thompson5910
sin(30) = opp/hyp sin(30) = 15/x 1/2 = 15/x 1*x = 2*15 x = 30
jim_thompson5910
  • jim_thompson5910
|dw:1362022087705:dw|
jim_thompson5910
  • jim_thompson5910
sin(60) = opp/hyp sin(60) = 15/y sqrt(3)/2 = 15/y sqrt(3)*y = 2*15 sqrt(3)*y = 30 y = 30/sqrt(3) y = 30*sqrt(3)/3 y = 10*sqrt(3)
jim_thompson5910
  • jim_thompson5910
|dw:1362022222994:dw|
jim_thompson5910
  • jim_thompson5910
a^2 + b^2 = c^2 30^2 + (10*sqrt(3))^2 = z^2 900 + 100*3 = z^2 900 + 300 = z^2 keep going to find z
anonymous
  • anonymous
z=34.64 ???
jim_thompson5910
  • jim_thompson5910
that's the approximate answer, the exact answer is z = 20*sqrt(3)
anonymous
  • anonymous
so what should i write it out as??
anonymous
  • anonymous
and i show all the work that u drew /wrote above right??? those are the steps?
jim_thompson5910
  • jim_thompson5910
yeah that's one way to get the hypotenuse
anonymous
  • anonymous
okay so that is the first part of the question right? what about the second part?
jim_thompson5910
  • jim_thompson5910
the shorter leg is 10*sqrt(3) units and I showed how to get that above as well
anonymous
  • anonymous
okay... so i for a the answer is z = 20*sqrt(3) which = 34.64 ?? and b is 10*sqrt(3) which equals 17.32 ?? is that right??? and it is all based on the steps u wrote above??
jim_thompson5910
  • jim_thompson5910
yes both are correct
anonymous
  • anonymous
awesome!! okay :) thanks a bunch!!!! :)
jim_thompson5910
  • jim_thompson5910
yw

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