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iheartfood

Find the exact value of the function sec(17pi/6).. also drawn inside. :) ***please explain and show steps!! thank youu :)

  • one year ago
  • one year ago

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  1. iheartfood
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    |dw:1361912361352:dw|

    • one year ago
  2. iheartfood
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    here is what i have... idk if it is right though... what do u think? is it correct? :/ |dw:1361912525340:dw| is that right??? :/

    • one year ago
  3. iheartfood
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    @jim_thompson5910 :) what do u think?? :D

    • one year ago
  4. jim_thompson5910
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    From there you can rationalize the denominator |dw:1361912794736:dw|

    • one year ago
  5. iheartfood
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    or is it supposed to be (-2/sq.rt.(3))/3 ??? :/

    • one year ago
  6. jim_thompson5910
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    but what you have is more or less correct

    • one year ago
  7. jim_thompson5910
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    that's the same thing...just a bit more convoluted

    • one year ago
  8. jim_thompson5910
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    I would just go with |dw:1361913060716:dw|

    • one year ago
  9. iheartfood
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    okay, so my steps are all right?? but the answer is just -2 sw.rt. 3 / 3 instead of -2/sq.rt. 3??

    • one year ago
  10. iheartfood
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    and thats the final answer?? @jim_thompson5910 ?? :/

    • one year ago
  11. iheartfood
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    @jim_thompson5910 so the final answer would just be what you drew above? and the steps i did earlier are correct??? ;/

    • one year ago
  12. jim_thompson5910
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    yes the final answer is |dw:1361941352439:dw| and your steps are correct

    • one year ago
  13. iheartfood
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    okay!! awesome :) thanks a bunch!!! :D

    • one year ago
  14. jim_thompson5910
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    yw

    • one year ago
  15. iheartfood
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    Consider the right triangle ABC that is attached... a. What is the length of the hypotenuse of triangle ABC? b. What is the length of the shorter leg of triangle ABC?

    • one year ago
  16. jim_thompson5910
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    where are the letters A, B, C?

    • one year ago
  17. iheartfood
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    it doesn't say :/ thats what i was thinking also... cuz aren't they usually labeled? :/

    • one year ago
  18. jim_thompson5910
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    there are 3 triangles so I have no idea which triangle they're referring to

    • one year ago
  19. iheartfood
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    is there any way you can assume where A, B, C are labeled?? cuz its a 30-60-90 triangle right?? one of the special triangles? :/ ***tho i don't quite remember the rule it has... :/

    • one year ago
  20. jim_thompson5910
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    yeah but where do they go and which point is left out?

    • one year ago
  21. jim_thompson5910
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    are you sure it's not labeled?

    • one year ago
  22. iheartfood
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    yeah its not labeled.. :/ its kinda weird... then can we do this then?? ill ask my teacher tomorrow about it and then i will reply back over here ?? would that work? :)

    • one year ago
  23. iheartfood
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    **reply back here after i find out the labels?

    • one year ago
  24. jim_thompson5910
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    sure that will work

    • one year ago
  25. iheartfood
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    okay hahaa :) thanks!! i will be back sometime tomorrow then!!! **if i can get online tomorrow night!!!*** hehe thankssss :)

    • one year ago
  26. jim_thompson5910
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    sure thing

    • one year ago
  27. iheartfood
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    okay... :) so i just asked my teacher and she said that the entire big triangle is ABC and she gave me a hint also!! :) she said that you will be finding the hypotenuse and the length of the leg by the angles given.. :/ but yeah! The HUGE triangle is triangle ABC :)

    • one year ago
  28. iheartfood
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    anddd idk how to do it tho... I'm still a bit confused on this whole process :/ :(

    • one year ago
  29. jim_thompson5910
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    |dw:1362021818496:dw|

    • one year ago
  30. iheartfood
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    hiiiiii :)

    • one year ago
  31. iheartfood
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    do u get it?? :/ cuz iheartfood is mucho confused :(

    • one year ago
  32. jim_thompson5910
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    |dw:1362021987081:dw|

    • one year ago
  33. jim_thompson5910
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    sin(30) = opp/hyp sin(30) = 15/x 1/2 = 15/x 1*x = 2*15 x = 30

    • one year ago
  34. jim_thompson5910
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    |dw:1362022087705:dw|

    • one year ago
  35. jim_thompson5910
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    sin(60) = opp/hyp sin(60) = 15/y sqrt(3)/2 = 15/y sqrt(3)*y = 2*15 sqrt(3)*y = 30 y = 30/sqrt(3) y = 30*sqrt(3)/3 y = 10*sqrt(3)

    • one year ago
  36. jim_thompson5910
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    |dw:1362022222994:dw|

    • one year ago
  37. jim_thompson5910
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    a^2 + b^2 = c^2 30^2 + (10*sqrt(3))^2 = z^2 900 + 100*3 = z^2 900 + 300 = z^2 keep going to find z

    • one year ago
  38. iheartfood
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    z=34.64 ???

    • one year ago
  39. jim_thompson5910
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    that's the approximate answer, the exact answer is z = 20*sqrt(3)

    • one year ago
  40. iheartfood
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    so what should i write it out as??

    • one year ago
  41. iheartfood
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    and i show all the work that u drew /wrote above right??? those are the steps?

    • one year ago
  42. jim_thompson5910
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    yeah that's one way to get the hypotenuse

    • one year ago
  43. iheartfood
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    okay so that is the first part of the question right? what about the second part?

    • one year ago
  44. jim_thompson5910
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    the shorter leg is 10*sqrt(3) units and I showed how to get that above as well

    • one year ago
  45. iheartfood
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    okay... so i for a the answer is z = 20*sqrt(3) which = 34.64 ?? and b is 10*sqrt(3) which equals 17.32 ?? is that right??? and it is all based on the steps u wrote above??

    • one year ago
  46. jim_thompson5910
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    yes both are correct

    • one year ago
  47. iheartfood
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    awesome!! okay :) thanks a bunch!!!! :)

    • one year ago
  48. jim_thompson5910
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    yw

    • one year ago
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