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iheartfood

  • one year ago

Find the exact value of the function sec(17pi/6).. also drawn inside. :) ***please explain and show steps!! thank youu :)

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  1. iheartfood
    • one year ago
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    |dw:1361912361352:dw|

  2. iheartfood
    • one year ago
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    here is what i have... idk if it is right though... what do u think? is it correct? :/ |dw:1361912525340:dw| is that right??? :/

  3. iheartfood
    • one year ago
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    @jim_thompson5910 :) what do u think?? :D

  4. jim_thompson5910
    • one year ago
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    From there you can rationalize the denominator |dw:1361912794736:dw|

  5. iheartfood
    • one year ago
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    or is it supposed to be (-2/sq.rt.(3))/3 ??? :/

  6. jim_thompson5910
    • one year ago
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    but what you have is more or less correct

  7. jim_thompson5910
    • one year ago
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    that's the same thing...just a bit more convoluted

  8. jim_thompson5910
    • one year ago
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    I would just go with |dw:1361913060716:dw|

  9. iheartfood
    • one year ago
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    okay, so my steps are all right?? but the answer is just -2 sw.rt. 3 / 3 instead of -2/sq.rt. 3??

  10. iheartfood
    • one year ago
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    and thats the final answer?? @jim_thompson5910 ?? :/

  11. iheartfood
    • one year ago
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    @jim_thompson5910 so the final answer would just be what you drew above? and the steps i did earlier are correct??? ;/

  12. jim_thompson5910
    • one year ago
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    yes the final answer is |dw:1361941352439:dw| and your steps are correct

  13. iheartfood
    • one year ago
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    okay!! awesome :) thanks a bunch!!! :D

  14. jim_thompson5910
    • one year ago
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    yw

  15. iheartfood
    • one year ago
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    Consider the right triangle ABC that is attached... a. What is the length of the hypotenuse of triangle ABC? b. What is the length of the shorter leg of triangle ABC?

  16. jim_thompson5910
    • one year ago
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    where are the letters A, B, C?

  17. iheartfood
    • one year ago
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    it doesn't say :/ thats what i was thinking also... cuz aren't they usually labeled? :/

  18. jim_thompson5910
    • one year ago
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    there are 3 triangles so I have no idea which triangle they're referring to

  19. iheartfood
    • one year ago
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    is there any way you can assume where A, B, C are labeled?? cuz its a 30-60-90 triangle right?? one of the special triangles? :/ ***tho i don't quite remember the rule it has... :/

  20. jim_thompson5910
    • one year ago
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    yeah but where do they go and which point is left out?

  21. jim_thompson5910
    • one year ago
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    are you sure it's not labeled?

  22. iheartfood
    • one year ago
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    yeah its not labeled.. :/ its kinda weird... then can we do this then?? ill ask my teacher tomorrow about it and then i will reply back over here ?? would that work? :)

  23. iheartfood
    • one year ago
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    **reply back here after i find out the labels?

  24. jim_thompson5910
    • one year ago
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    sure that will work

  25. iheartfood
    • one year ago
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    okay hahaa :) thanks!! i will be back sometime tomorrow then!!! **if i can get online tomorrow night!!!*** hehe thankssss :)

  26. jim_thompson5910
    • one year ago
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    sure thing

  27. iheartfood
    • one year ago
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    okay... :) so i just asked my teacher and she said that the entire big triangle is ABC and she gave me a hint also!! :) she said that you will be finding the hypotenuse and the length of the leg by the angles given.. :/ but yeah! The HUGE triangle is triangle ABC :)

  28. iheartfood
    • one year ago
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    anddd idk how to do it tho... I'm still a bit confused on this whole process :/ :(

  29. jim_thompson5910
    • one year ago
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    |dw:1362021818496:dw|

  30. iheartfood
    • one year ago
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    hiiiiii :)

  31. iheartfood
    • one year ago
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    do u get it?? :/ cuz iheartfood is mucho confused :(

  32. jim_thompson5910
    • one year ago
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    |dw:1362021987081:dw|

  33. jim_thompson5910
    • one year ago
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    sin(30) = opp/hyp sin(30) = 15/x 1/2 = 15/x 1*x = 2*15 x = 30

  34. jim_thompson5910
    • one year ago
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    |dw:1362022087705:dw|

  35. jim_thompson5910
    • one year ago
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    sin(60) = opp/hyp sin(60) = 15/y sqrt(3)/2 = 15/y sqrt(3)*y = 2*15 sqrt(3)*y = 30 y = 30/sqrt(3) y = 30*sqrt(3)/3 y = 10*sqrt(3)

  36. jim_thompson5910
    • one year ago
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    |dw:1362022222994:dw|

  37. jim_thompson5910
    • one year ago
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    a^2 + b^2 = c^2 30^2 + (10*sqrt(3))^2 = z^2 900 + 100*3 = z^2 900 + 300 = z^2 keep going to find z

  38. iheartfood
    • one year ago
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    z=34.64 ???

  39. jim_thompson5910
    • one year ago
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    that's the approximate answer, the exact answer is z = 20*sqrt(3)

  40. iheartfood
    • one year ago
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    so what should i write it out as??

  41. iheartfood
    • one year ago
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    and i show all the work that u drew /wrote above right??? those are the steps?

  42. jim_thompson5910
    • one year ago
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    yeah that's one way to get the hypotenuse

  43. iheartfood
    • one year ago
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    okay so that is the first part of the question right? what about the second part?

  44. jim_thompson5910
    • one year ago
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    the shorter leg is 10*sqrt(3) units and I showed how to get that above as well

  45. iheartfood
    • one year ago
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    okay... so i for a the answer is z = 20*sqrt(3) which = 34.64 ?? and b is 10*sqrt(3) which equals 17.32 ?? is that right??? and it is all based on the steps u wrote above??

  46. jim_thompson5910
    • one year ago
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    yes both are correct

  47. iheartfood
    • one year ago
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    awesome!! okay :) thanks a bunch!!!! :)

  48. jim_thompson5910
    • one year ago
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    yw

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