Find the exact value of the function sec(17pi/6).. also drawn inside. :)
***please explain and show steps!! thank youu :)

- anonymous

- schrodinger

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- anonymous

|dw:1361912361352:dw|

- anonymous

here is what i have... idk if it is right though... what do u think? is it correct? :/ |dw:1361912525340:dw| is that right??? :/

- anonymous

@jim_thompson5910 :) what do u think?? :D

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## More answers

- jim_thompson5910

From there you can rationalize the denominator
|dw:1361912794736:dw|

- anonymous

or is it supposed to be (-2/sq.rt.(3))/3 ??? :/

- jim_thompson5910

but what you have is more or less correct

- jim_thompson5910

that's the same thing...just a bit more convoluted

- jim_thompson5910

I would just go with
|dw:1361913060716:dw|

- anonymous

okay, so my steps are all right?? but the answer is just -2 sw.rt. 3 / 3 instead of -2/sq.rt. 3??

- anonymous

and thats the final answer?? @jim_thompson5910 ?? :/

- anonymous

@jim_thompson5910 so the final answer would just be what you drew above? and the steps i did earlier are correct??? ;/

- jim_thompson5910

yes the final answer is
|dw:1361941352439:dw|
and your steps are correct

- anonymous

okay!! awesome :) thanks a bunch!!! :D

- jim_thompson5910

yw

- anonymous

Consider the right triangle ABC that is attached...
a. What is the length of the hypotenuse of triangle ABC?
b. What is the length of the shorter leg of triangle ABC?

##### 1 Attachment

- jim_thompson5910

where are the letters A, B, C?

- anonymous

it doesn't say :/ thats what i was thinking also... cuz aren't they usually labeled? :/

- jim_thompson5910

there are 3 triangles so I have no idea which triangle they're referring to

- anonymous

is there any way you can assume where A, B, C are labeled?? cuz its a 30-60-90 triangle right?? one of the special triangles? :/ ***tho i don't quite remember the rule it has... :/

- jim_thompson5910

yeah but where do they go and which point is left out?

- jim_thompson5910

are you sure it's not labeled?

- anonymous

yeah its not labeled.. :/ its kinda weird... then can we do this then?? ill ask my teacher tomorrow about it and then i will reply back over here ?? would that work? :)

- anonymous

**reply back here after i find out the labels?

- jim_thompson5910

sure that will work

- anonymous

okay hahaa :) thanks!! i will be back sometime tomorrow then!!! **if i can get online tomorrow night!!!*** hehe thankssss :)

- jim_thompson5910

sure thing

- anonymous

okay... :) so i just asked my teacher and she said that the entire big triangle is ABC and she gave me a hint also!! :)
she said that you will be finding the hypotenuse and the length of the leg by the angles given.. :/ but yeah! The HUGE triangle is triangle ABC :)

- anonymous

anddd idk how to do it tho... I'm still a bit confused on this whole process :/ :(

- jim_thompson5910

|dw:1362021818496:dw|

- anonymous

hiiiiii :)

- anonymous

do u get it?? :/ cuz iheartfood is mucho confused :(

- jim_thompson5910

|dw:1362021987081:dw|

- jim_thompson5910

sin(30) = opp/hyp
sin(30) = 15/x
1/2 = 15/x
1*x = 2*15
x = 30

- jim_thompson5910

|dw:1362022087705:dw|

- jim_thompson5910

sin(60) = opp/hyp
sin(60) = 15/y
sqrt(3)/2 = 15/y
sqrt(3)*y = 2*15
sqrt(3)*y = 30
y = 30/sqrt(3)
y = 30*sqrt(3)/3
y = 10*sqrt(3)

- jim_thompson5910

|dw:1362022222994:dw|

- jim_thompson5910

a^2 + b^2 = c^2
30^2 + (10*sqrt(3))^2 = z^2
900 + 100*3 = z^2
900 + 300 = z^2
keep going to find z

- anonymous

z=34.64 ???

- jim_thompson5910

that's the approximate answer, the exact answer is z = 20*sqrt(3)

- anonymous

so what should i write it out as??

- anonymous

and i show all the work that u drew /wrote above right??? those are the steps?

- jim_thompson5910

yeah that's one way to get the hypotenuse

- anonymous

okay so that is the first part of the question right? what about the second part?

- jim_thompson5910

the shorter leg is 10*sqrt(3) units and I showed how to get that above as well

- anonymous

okay... so i for a the answer is z = 20*sqrt(3) which = 34.64 ??
and b is 10*sqrt(3) which equals 17.32 ??
is that right??? and it is all based on the steps u wrote above??

- jim_thompson5910

yes both are correct

- anonymous

awesome!! okay :) thanks a bunch!!!! :)

- jim_thompson5910

yw

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