Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

ksaimouli

  • 3 years ago

by partial frac

  • This Question is Closed
  1. ksaimouli
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    \[\int\limits_{}\frac{ 2x^3 }{ x^2-4 }\]

  2. ksaimouli
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i should do the long division right

  3. ksaimouli
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i got \[x^2-4+\frac{ 8x }{ 2x }\]

  4. ksaimouli
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    @zepdrix

  5. SithsAndGiggles
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    You're right about doing long division first, but it doesn't look like you did it right.

  6. ksaimouli
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |dw:1361917090294:dw|

  7. SithsAndGiggles
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    |dw:1361917028271:dw|

  8. SithsAndGiggles
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Right, so by long division you get \[2x+\frac{8x}{x^2-4}\]

  9. ksaimouli
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so should i make the whole function as|dw:1361917417172:dw|

  10. SithsAndGiggles
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    You can, but that doesn't mean you should. Your integral has changed from \[\int\frac{2x^3}{x^2-4}dx\] to \[\int\left(2x+\frac{8x}{x^2-4}\right)\;dx\] Integrate term by term, with partial fraction decomp on the second term.

  11. ksaimouli
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    right here i could use u substitution right

  12. SithsAndGiggles
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Or that, yes. A sub might actually shorten the work, so I'd suggest that.

  13. ksaimouli
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    i got \[x^2+4\ln(x^2-4)\]

  14. ksaimouli
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    +C

  15. ksaimouli
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    is this right @SithsAndGiggles

  16. SithsAndGiggles
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Yes that's right, though I would replace the parentheses with absolute value bars.

  17. ksaimouli
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ya i dont know how to use that in equation so put the ()

  18. ksaimouli
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    thx

  19. SithsAndGiggles
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    You're welcome. By the way, absolute value bars are above the Enter/Return key. Hold shift and click the backslash (\) button to get (|)

  20. ksaimouli
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    |2x+1|

  21. ksaimouli
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    ya i got that thx

  22. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy