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ksaimouliBest ResponseYou've already chosen the best response.0
\[\int\limits_{}\frac{ 2x^3 }{ x^24 }\]
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
i should do the long division right
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
i got \[x^24+\frac{ 8x }{ 2x }\]
 one year ago

SithsAndGigglesBest ResponseYou've already chosen the best response.1
You're right about doing long division first, but it doesn't look like you did it right.
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
dw:1361917090294:dw
 one year ago

SithsAndGigglesBest ResponseYou've already chosen the best response.1
dw:1361917028271:dw
 one year ago

SithsAndGigglesBest ResponseYou've already chosen the best response.1
Right, so by long division you get \[2x+\frac{8x}{x^24}\]
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
so should i make the whole function asdw:1361917417172:dw
 one year ago

SithsAndGigglesBest ResponseYou've already chosen the best response.1
You can, but that doesn't mean you should. Your integral has changed from \[\int\frac{2x^3}{x^24}dx\] to \[\int\left(2x+\frac{8x}{x^24}\right)\;dx\] Integrate term by term, with partial fraction decomp on the second term.
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
right here i could use u substitution right
 one year ago

SithsAndGigglesBest ResponseYou've already chosen the best response.1
Or that, yes. A sub might actually shorten the work, so I'd suggest that.
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
i got \[x^2+4\ln(x^24)\]
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
is this right @SithsAndGiggles
 one year ago

SithsAndGigglesBest ResponseYou've already chosen the best response.1
Yes that's right, though I would replace the parentheses with absolute value bars.
 one year ago

ksaimouliBest ResponseYou've already chosen the best response.0
ya i dont know how to use that in equation so put the ()
 one year ago

SithsAndGigglesBest ResponseYou've already chosen the best response.1
You're welcome. By the way, absolute value bars are above the Enter/Return key. Hold shift and click the backslash (\) button to get ()
 one year ago
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