## David.Butler Group Title \int _{ 0 }^{ pi }{ \frac { sin\theta }{ \sqrt { pi\quad -\quad \theta } } } using\quad \frac { 1 }{ \sqrt { pi\quad -\quad \theta } } \quad as\quad comparison one year ago one year ago

1. ChelseaSweets Group Title

what???

2. David.Butler Group Title

$\int\limits _{ 0 }^{ \pi }{ \frac { \sin\theta }{ \sqrt { \pi\quad -\quad \theta } } } using\quad \frac { 1 }{ \sqrt { \pi\quad -\quad \theta } } \quad as\quad comparison$

3. ChelseaSweets Group Title

sorry idk how to do it, good luck though!

4. David.Butler Group Title

Hahaha, thanks.

5. sirm3d Group Title

you're asking if the integral is convergent or divergent?

6. David.Butler Group Title

Yeah

7. sirm3d Group Title

if $\int_0^{\pi}\frac{d\theta}{\sqrt{\pi-\theta}}$ is convergent, you can conclude that the integral in question is also convergent.

8. David.Butler Group Title

How do I know that integral you stated above is convergent? That's the part that is troubling me.

9. sirm3d Group Title

why don't you evaluate the definite integral? if it is a value, then the integral is convergent.

10. David.Butler Group Title

Oh okay, I thought it was improper. I just realized that it was definite. Thanks!

11. sirm3d Group Title

it is an improper integral, but after integration, the function is continuous in that interval, so you can treat it like an ordinary definite integral.