A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 3 years ago
Please anyone help me!!
anonymous
 3 years ago
Please anyone help me!!

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0When a cold drink is taken from a refrigerator, its temperature is 5°C. After 25 minutes in a 20°C room its temperature has increased to 10°C. (a) What is the temperature of the drink after 50C minutes? (b) When will its temperature be 15°C?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0http://answers.yahoo.com/question/index?qid=20090326150117AA7jVrX :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@Cha1234 That question is asking for different values.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but this site has really confused answer

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0can anyone explain this to me here?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I learned this in basic physics, I assume solving the same way. Have you been taught Newton's Law of Cooling?\[\frac{ dT }{ dt }=k(T20)\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0can anyone explain this to me that how I m getting this answer ln[(20  T)/(20  5)] =  0.01622

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0when I m calculating it I m getting 1.10623

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0don't make it so hard it is easier than you think

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0When a cold drink is taken from a refrigerator, its temperature is 5°C. After 25 minutes in a 20°C room its temperature has increased to 10°C. (a) What is the temperature of the drink after 50C minutes? (b) When will its temperature be 15°C?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0work with the differences in the temperature, that is what decays to zero initial difference is \(205=15\) degrees, after 25 minutes the difference is \(1020=10\) degrees so the difference has decreased by \(\frac{10}{15}=\frac{2}{3}\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i.e. every 25 minutes, the difference in the temperature decreases by \(\frac{2}{3}\) starting with an initial difference of \(15\) you can model this by \[15\left(\frac{2}{3}\right)^{\frac{t}{25}}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0after another 25 minutes, at 50 minutes, it will decrease by another \(\frac{2}{3}\) from \(10\) to \(10\times \frac{2}{3}=\frac{20}{3}=6\tfrac{2}{3}\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0that of course means it is \(6\tfrac{2}{3}\) colder than the 20 degree room, so its temperature is \(206\tfrac{2}{3}=13\tfrac{1}{3}\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0b) when will it be 15 degrees? that means b) when will it be 5 degrees colder than the room set \[15\left(\frac{2}{3}\right)^{\frac{t}{25}}=5\] and solve for \(t\)
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.