A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 one year ago
When asked to calculate the energy required to launch a satellite into orbit, do I have to solve for E (E=K+U) or just potential U?
 one year ago
When asked to calculate the energy required to launch a satellite into orbit, do I have to solve for E (E=K+U) or just potential U?

This Question is Closed

JenniferSmart1
 one year ago
Best ResponseYou've already chosen the best response.0I think it's E=K+U \[K=\frac 12 mv^2\] \[U=\frac{GMm}{r}\] \[F=ma\] \[a=\frac{v^2}r\] \[F=m\frac{v^2}{r}\] \[F=\frac{GMm}{r^2}\] \[\frac{GMm}{r^2}=m\frac{v^2}{r}\] \[\frac{GM\cancel m}{r^2}=\cancel m\frac{v^2}{r}\] \[\frac{GM}{r}=v^2\] E=K+U \[E=\frac 12mv^2\frac{GMm}{r}\] \[E=\frac 12m\frac{GM}{r}\frac{GMm}{r}\]

JenniferSmart1
 one year ago
Best ResponseYou've already chosen the best response.0@satellite73 @phi How does the above simplify to \[=\frac{GMm}{2r}\]?

JenniferSmart1
 one year ago
Best ResponseYou've already chosen the best response.0I'm soo silly...nevermind

wio
 one year ago
Best ResponseYou've already chosen the best response.1Orbits are elliptical so the potential energy is going to be changing, likewise kinetic energy is going to change. Clearly the amount of energy it took is constant.
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.