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\[\large x=\frac{5}{4}y-2\]Oh like this? :) That would make more sense lol

no it isn't. it's like the second one you just put up.

oh i had put a -4/5

but yes other than that i get it so far

-4/5 correct? that would be the reciprocal

oh okay

So plug \(\large (4,-2)\) into our equation \(\large y_p=-\dfrac{5}{4}x+b\).

okay

i think im messing up so where

for som reason im getting y=-4/5x+6/5

i mean -5/4x+6/5

yeah i did

i was doing it wrong

so y=4/5x+8/5 is correct?

so the answer is y=-5/4x+3

ya :)