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\[\dfrac{1}{a} + \dfrac{1}{c} = \dfrac{a + c}{ac}\]Any substitution?

The choices are:
1. \(\dfrac{2}{b}\) and, 2. \(2a\)

I have eliminated two more because they definitely are not the answers.

Ohhh!!

(2a-b)(2c-b) = b^2
4ac - 2ab - 2bc =0

Yeah, it's \(2/b\) by hit-and-trial

yep, just divide both sides by 2abc

HOW DID THAT NOT COME TO MY MIND?!

you must be busy with some of your research :)

-_-

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