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If \(x^a = y^b = z^c\) and \(y^2 = zx\), then the value of \(\dfrac{1}{a} + \dfrac{1}{c}\) is?
 one year ago
 one year ago
If \(x^a = y^b = z^c\) and \(y^2 = zx\), then the value of \(\dfrac{1}{a} + \dfrac{1}{c}\) is?
 one year ago
 one year ago

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ParthKohliBest ResponseYou've already chosen the best response.1
\[\dfrac{1}{a} + \dfrac{1}{c} = \dfrac{a + c}{ac}\]Any substitution?
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.1
x^2a = z^b . x^b = z^2c x^(2ab) = z^b and z^(2cb) = x^b or (2ab) logx = b logz and b logx = (2cb)log z => (2ab)/b = b/(2cb)
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
The choices are: 1. \(\dfrac{2}{b}\) and, 2. \(2a\)
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
I have eliminated two more because they definitely are not the answers.
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.1
(2ab)(2cb) = b^2 4ac  2ab  2bc =0
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
Yeah, it's \(2/b\) by hitandtrial
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.1
yep, just divide both sides by 2abc
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
HOW DID THAT NOT COME TO MY MIND?!
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.1
you must be busy with some of your research :)
 one year ago

shubhamsrgBest ResponseYou've already chosen the best response.1
dw:1361955141551:dw
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
dw:1361955168936:dw
 one year ago

goformit100Best ResponseYou've already chosen the best response.0
dw:1361971686406:dw
 one year ago
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