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ParthKohli
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If \(x^a = y^b = z^c\) and \(y^2 = zx\), then the value of \(\dfrac{1}{a} + \dfrac{1}{c}\) is?
 one year ago
 one year ago
ParthKohli Group Title
If \(x^a = y^b = z^c\) and \(y^2 = zx\), then the value of \(\dfrac{1}{a} + \dfrac{1}{c}\) is?
 one year ago
 one year ago

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ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
\[\dfrac{1}{a} + \dfrac{1}{c} = \dfrac{a + c}{ac}\]Any substitution?
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
x^2a = z^b . x^b = z^2c x^(2ab) = z^b and z^(2cb) = x^b or (2ab) logx = b logz and b logx = (2cb)log z => (2ab)/b = b/(2cb)
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
The choices are: 1. \(\dfrac{2}{b}\) and, 2. \(2a\)
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
I have eliminated two more because they definitely are not the answers.
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
(2ab)(2cb) = b^2 4ac  2ab  2bc =0
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
Yeah, it's \(2/b\) by hitandtrial
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
yep, just divide both sides by 2abc
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
HOW DID THAT NOT COME TO MY MIND?!
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
you must be busy with some of your research :)
 one year ago

shubhamsrg Group TitleBest ResponseYou've already chosen the best response.1
dw:1361955141551:dw
 one year ago

ParthKohli Group TitleBest ResponseYou've already chosen the best response.1
dw:1361955168936:dw
 one year ago

goformit100 Group TitleBest ResponseYou've already chosen the best response.0
dw:1361971686406:dw
 one year ago
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