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  • 3 years ago

Solve each system of equations by substitution -5a+c=-30 4a-5c=24

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  1. zpupster
    • 3 years ago
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    take the 1sr equation and solve for c --add 5a to both sides c= 5a-30 after rearranging now we know c replace c with 5a-30 4a-5(5a-30)=24 4a-25a + 150 = 24 you should have it from here

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