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I have an opposite leg of a right triangle that is 40mm long, I have an adjacent leg of 165mm what is the measure of angle a which is the angle in between the hypotenuse and the adjacent leg
what is the sine, cosine, and tangent ratios for ∠ A.
i wont give u the answer but i will help you

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Other answers:

ok that is what I wanted
first of all we need to use cosine since were dealing with adjacent/hypotenuse
what we first want to do tho is use tangent to find the length of the hypotenuse
actually for the hypotenuse we could do a^2=b^2=c^2
the length is about 170
But he need to find the angle
not the hypotenuse
begzat
to find the angle you need to find the hypotenuse
no
yep
169.78 is the length of the hypotenuse
the hypotenuse is 170 so we dont need to find it
do you know what is Trigonometric Ratios
alright then from there is pretty simple
i rounded
if you know Trigonometric Ratios formula you can find very easy the angle
ok but what are the steps i forgot
okay i will post the formulas and you will find wich one you need to use
ok
sin=opposite leg/ hypotenuse cos=adjacent leg/hypotenuse tan=opposite leg/ adjacent leg
know which one you need to use
now***
so I need to use cosine
no because you know opposite and adjacent leg
i also know hypotenuse it is 170
but on the question it said that you know opp. and adj.
you can use tan if you want
I forgot to post the hypotenuse
okay so you can use all
but which one helps me find my angle
all
you can use tan=opp./adjacent leg
well can you help me with the steps for cos
>well can you help me with the steps for cos The cosine of an acute angle of a right triangle is the ratio of the length of the leg adjacent to the hypotenuse to the hypotenuse length. cos(A) = 165/169.78 cos(A) = 0.9718459 approx A = ? |dw:1362220656246:dw|

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