Brunette
According to the rational root theorem, which is not a possible rational root of x^3 + 8x^2  x  6 = 0?
1
4
2
6



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Mertsj
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The possible rational roots are the factors of the constant term divided by the factors of the coefficient of the leading term.

Mertsj
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The constant term is 6
The leading term is x^3 and its coefficient is 1

Mertsj
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So the possible rational roots are the factors of 6 divided by the factors of 1

Mertsj
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So what are the possible rational roots?

Brunette
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6

Mertsj
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What are the factors of 6?

Brunette
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no clue???

Mertsj
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Let me give you an example: The factors of 12 are 4 and 3 because 4 x 3 = 12

Mertsj
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Also 2 and 6 are factors of 12 because 2 x 6 = 12

Mertsj
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Also 1 and 12 are factors of 12 because 1 x 12 = 12

Mertsj
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Now you tell me some factors of 6

gojani91
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what two numbers when multiplied equal 6

gojani91
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6

Brunette
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1

Mertsj
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ok. Now gojani91 wants to help you.
Good bye

Brunette
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lol ok then

gojani91
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damn you dont have to be rude mertsj

Brunette
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lol its fine dont worry about it :)

Brunette
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forget it, it's cool ill figure it out but thanks for trying to help i can be quite difficult...

gojani91
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what are the factors of 6

gojani91
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1 x 6
1 x 6
2 x 3
3 x 2

Brunette
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1?

Brunette
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and 2

Brunette
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3 am i right?

gojani91
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yes those are all roots

Brunette
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k so which do I choose from 1 and 2?

gojani91
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this is an easy problem because the leading coefficient is 1 from x^3 so all those numbers can be divided by 1

gojani91
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your question ask which is not a possible root number

Brunette
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oh ok so 4

gojani91
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so what numbers is not a factor of 6

gojani91
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yes you got it

Brunette
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thank you so much really appreciate it :)

gojani91
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no problem