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Brunette
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According to the rational root theorem, which is not a possible rational root of x^3 + 8x^2  x  6 = 0?
1
4
2
6
 one year ago
 one year ago
Brunette Group Title
According to the rational root theorem, which is not a possible rational root of x^3 + 8x^2  x  6 = 0? 1 4 2 6
 one year ago
 one year ago

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Mertsj Group TitleBest ResponseYou've already chosen the best response.0
The possible rational roots are the factors of the constant term divided by the factors of the coefficient of the leading term.
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
The constant term is 6 The leading term is x^3 and its coefficient is 1
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
So the possible rational roots are the factors of 6 divided by the factors of 1
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
So what are the possible rational roots?
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
What are the factors of 6?
 one year ago

Brunette Group TitleBest ResponseYou've already chosen the best response.0
no clue???
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Let me give you an example: The factors of 12 are 4 and 3 because 4 x 3 = 12
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Also 2 and 6 are factors of 12 because 2 x 6 = 12
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Also 1 and 12 are factors of 12 because 1 x 12 = 12
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Now you tell me some factors of 6
 one year ago

gojani91 Group TitleBest ResponseYou've already chosen the best response.0
what two numbers when multiplied equal 6
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
ok. Now gojani91 wants to help you. Good bye
 one year ago

Brunette Group TitleBest ResponseYou've already chosen the best response.0
lol ok then
 one year ago

gojani91 Group TitleBest ResponseYou've already chosen the best response.0
damn you dont have to be rude mertsj
 one year ago

Brunette Group TitleBest ResponseYou've already chosen the best response.0
lol its fine dont worry about it :)
 one year ago

Brunette Group TitleBest ResponseYou've already chosen the best response.0
forget it, it's cool ill figure it out but thanks for trying to help i can be quite difficult...
 one year ago

gojani91 Group TitleBest ResponseYou've already chosen the best response.0
what are the factors of 6
 one year ago

gojani91 Group TitleBest ResponseYou've already chosen the best response.0
1 x 6 1 x 6 2 x 3 3 x 2
 one year ago

Brunette Group TitleBest ResponseYou've already chosen the best response.0
3 am i right?
 one year ago

gojani91 Group TitleBest ResponseYou've already chosen the best response.0
yes those are all roots
 one year ago

Brunette Group TitleBest ResponseYou've already chosen the best response.0
k so which do I choose from 1 and 2?
 one year ago

gojani91 Group TitleBest ResponseYou've already chosen the best response.0
this is an easy problem because the leading coefficient is 1 from x^3 so all those numbers can be divided by 1
 one year ago

gojani91 Group TitleBest ResponseYou've already chosen the best response.0
your question ask which is not a possible root number
 one year ago

Brunette Group TitleBest ResponseYou've already chosen the best response.0
oh ok so 4
 one year ago

gojani91 Group TitleBest ResponseYou've already chosen the best response.0
so what numbers is not a factor of 6
 one year ago

gojani91 Group TitleBest ResponseYou've already chosen the best response.0
yes you got it
 one year ago

Brunette Group TitleBest ResponseYou've already chosen the best response.0
thank you so much really appreciate it :)
 one year ago

gojani91 Group TitleBest ResponseYou've already chosen the best response.0
no problem
 one year ago
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