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Brunette
 one year ago
According to the rational root theorem, which is not a possible rational root of x^3 + 8x^2  x  6 = 0?
1
4
2
6
Brunette
 one year ago
According to the rational root theorem, which is not a possible rational root of x^3 + 8x^2  x  6 = 0? 1 4 2 6

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Mertsj
 one year ago
Best ResponseYou've already chosen the best response.0The possible rational roots are the factors of the constant term divided by the factors of the coefficient of the leading term.

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.0The constant term is 6 The leading term is x^3 and its coefficient is 1

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.0So the possible rational roots are the factors of 6 divided by the factors of 1

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.0So what are the possible rational roots?

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.0What are the factors of 6?

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.0Let me give you an example: The factors of 12 are 4 and 3 because 4 x 3 = 12

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.0Also 2 and 6 are factors of 12 because 2 x 6 = 12

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.0Also 1 and 12 are factors of 12 because 1 x 12 = 12

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.0Now you tell me some factors of 6

gojani91
 one year ago
Best ResponseYou've already chosen the best response.0what two numbers when multiplied equal 6

Mertsj
 one year ago
Best ResponseYou've already chosen the best response.0ok. Now gojani91 wants to help you. Good bye

gojani91
 one year ago
Best ResponseYou've already chosen the best response.0damn you dont have to be rude mertsj

Brunette
 one year ago
Best ResponseYou've already chosen the best response.0lol its fine dont worry about it :)

Brunette
 one year ago
Best ResponseYou've already chosen the best response.0forget it, it's cool ill figure it out but thanks for trying to help i can be quite difficult...

gojani91
 one year ago
Best ResponseYou've already chosen the best response.0what are the factors of 6

gojani91
 one year ago
Best ResponseYou've already chosen the best response.01 x 6 1 x 6 2 x 3 3 x 2

gojani91
 one year ago
Best ResponseYou've already chosen the best response.0yes those are all roots

Brunette
 one year ago
Best ResponseYou've already chosen the best response.0k so which do I choose from 1 and 2?

gojani91
 one year ago
Best ResponseYou've already chosen the best response.0this is an easy problem because the leading coefficient is 1 from x^3 so all those numbers can be divided by 1

gojani91
 one year ago
Best ResponseYou've already chosen the best response.0your question ask which is not a possible root number

gojani91
 one year ago
Best ResponseYou've already chosen the best response.0so what numbers is not a factor of 6

Brunette
 one year ago
Best ResponseYou've already chosen the best response.0thank you so much really appreciate it :)
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