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anonymous
 3 years ago
According to the rational root theorem, which is not a possible rational root of x^3 + 8x^2  x  6 = 0?
1
4
2
6
anonymous
 3 years ago
According to the rational root theorem, which is not a possible rational root of x^3 + 8x^2  x  6 = 0? 1 4 2 6

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Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.0The possible rational roots are the factors of the constant term divided by the factors of the coefficient of the leading term.

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.0The constant term is 6 The leading term is x^3 and its coefficient is 1

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.0So the possible rational roots are the factors of 6 divided by the factors of 1

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.0So what are the possible rational roots?

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.0What are the factors of 6?

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.0Let me give you an example: The factors of 12 are 4 and 3 because 4 x 3 = 12

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.0Also 2 and 6 are factors of 12 because 2 x 6 = 12

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.0Also 1 and 12 are factors of 12 because 1 x 12 = 12

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.0Now you tell me some factors of 6

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what two numbers when multiplied equal 6

Mertsj
 3 years ago
Best ResponseYou've already chosen the best response.0ok. Now gojani91 wants to help you. Good bye

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0damn you dont have to be rude mertsj

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0lol its fine dont worry about it :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0forget it, it's cool ill figure it out but thanks for trying to help i can be quite difficult...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what are the factors of 6

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.01 x 6 1 x 6 2 x 3 3 x 2

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yes those are all roots

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0k so which do I choose from 1 and 2?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0this is an easy problem because the leading coefficient is 1 from x^3 so all those numbers can be divided by 1

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0your question ask which is not a possible root number

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so what numbers is not a factor of 6

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0thank you so much really appreciate it :)
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