## Brunette 2 years ago According to the rational root theorem, which is not a possible rational root of x^3 + 8x^2 - x - 6 = 0? 1 4 2 6

1. Mertsj

The possible rational roots are the factors of the constant term divided by the factors of the coefficient of the leading term.

2. Mertsj

The constant term is -6 The leading term is x^3 and its coefficient is 1

3. Mertsj

So the possible rational roots are the factors of -6 divided by the factors of 1

4. Mertsj

So what are the possible rational roots?

5. Brunette

6

6. Mertsj

What are the factors of -6?

7. Brunette

no clue???

8. Mertsj

Let me give you an example: The factors of 12 are 4 and 3 because 4 x 3 = 12

9. Mertsj

Also 2 and 6 are factors of 12 because 2 x 6 = 12

10. Mertsj

Also -1 and -12 are factors of 12 because -1 x -12 = 12

11. Mertsj

Now you tell me some factors of -6

12. gojani91

what two numbers when multiplied equal 6

13. gojani91

-6

14. Brunette

1

15. Mertsj

16. Brunette

lol ok then

17. gojani91

damn you dont have to be rude mertsj

18. Brunette

lol its fine dont worry about it :)

19. Brunette

forget it, it's cool ill figure it out but thanks for trying to help i can be quite difficult...

20. gojani91

what are the factors of -6

21. gojani91

-1 x 6 1 x -6 2 x -3 3 x -2

22. Brunette

1?

23. Brunette

and 2

24. Brunette

-3 am i right?

25. gojani91

yes those are all roots

26. Brunette

k so which do I choose from 1 and 2?

27. gojani91

this is an easy problem because the leading coefficient is 1 from x^3 so all those numbers can be divided by 1

28. gojani91

29. Brunette

oh ok so 4

30. gojani91

so what numbers is not a factor of 6

31. gojani91

yes you got it

32. Brunette

thank you so much really appreciate it :)

33. gojani91

no problem