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Brunette

  • one year ago

According to the rational root theorem, which is not a possible rational root of x^3 + 8x^2 - x - 6 = 0? 1 4 2 6

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  1. Mertsj
    • one year ago
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    The possible rational roots are the factors of the constant term divided by the factors of the coefficient of the leading term.

  2. Mertsj
    • one year ago
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    The constant term is -6 The leading term is x^3 and its coefficient is 1

  3. Mertsj
    • one year ago
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    So the possible rational roots are the factors of -6 divided by the factors of 1

  4. Mertsj
    • one year ago
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    So what are the possible rational roots?

  5. Brunette
    • one year ago
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    6

  6. Mertsj
    • one year ago
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    What are the factors of -6?

  7. Brunette
    • one year ago
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    no clue???

  8. Mertsj
    • one year ago
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    Let me give you an example: The factors of 12 are 4 and 3 because 4 x 3 = 12

  9. Mertsj
    • one year ago
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    Also 2 and 6 are factors of 12 because 2 x 6 = 12

  10. Mertsj
    • one year ago
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    Also -1 and -12 are factors of 12 because -1 x -12 = 12

  11. Mertsj
    • one year ago
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    Now you tell me some factors of -6

  12. gojani91
    • one year ago
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    what two numbers when multiplied equal 6

  13. gojani91
    • one year ago
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    -6

  14. Brunette
    • one year ago
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    1

  15. Mertsj
    • one year ago
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    ok. Now gojani91 wants to help you. Good bye

  16. Brunette
    • one year ago
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    lol ok then

  17. gojani91
    • one year ago
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    damn you dont have to be rude mertsj

  18. Brunette
    • one year ago
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    lol its fine dont worry about it :)

  19. Brunette
    • one year ago
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    forget it, it's cool ill figure it out but thanks for trying to help i can be quite difficult...

  20. gojani91
    • one year ago
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    what are the factors of -6

  21. gojani91
    • one year ago
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    -1 x 6 1 x -6 2 x -3 3 x -2

  22. Brunette
    • one year ago
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    1?

  23. Brunette
    • one year ago
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    and 2

  24. Brunette
    • one year ago
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    -3 am i right?

  25. gojani91
    • one year ago
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    yes those are all roots

  26. Brunette
    • one year ago
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    k so which do I choose from 1 and 2?

  27. gojani91
    • one year ago
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    this is an easy problem because the leading coefficient is 1 from x^3 so all those numbers can be divided by 1

  28. gojani91
    • one year ago
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    your question ask which is not a possible root number

  29. Brunette
    • one year ago
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    oh ok so 4

  30. gojani91
    • one year ago
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    so what numbers is not a factor of 6

  31. gojani91
    • one year ago
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    yes you got it

  32. Brunette
    • one year ago
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    thank you so much really appreciate it :)

  33. gojani91
    • one year ago
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    no problem

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