According to the rational root theorem, which is not a possible rational root of x^3 + 8x^2 - x - 6 = 0?
1
4
2
6

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- anonymous

- jamiebookeater

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- Mertsj

The possible rational roots are the factors of the constant term divided by the factors of the coefficient of the leading term.

- Mertsj

The constant term is -6
The leading term is x^3 and its coefficient is 1

- Mertsj

So the possible rational roots are the factors of -6 divided by the factors of 1

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- Mertsj

So what are the possible rational roots?

- anonymous

6

- Mertsj

What are the factors of -6?

- anonymous

no clue???

- Mertsj

Let me give you an example: The factors of 12 are 4 and 3 because 4 x 3 = 12

- Mertsj

Also 2 and 6 are factors of 12 because 2 x 6 = 12

- Mertsj

Also -1 and -12 are factors of 12 because -1 x -12 = 12

- Mertsj

Now you tell me some factors of -6

- anonymous

what two numbers when multiplied equal 6

- anonymous

-6

- anonymous

1

- Mertsj

ok. Now gojani91 wants to help you.
Good bye

- anonymous

lol ok then

- anonymous

damn you dont have to be rude mertsj

- anonymous

lol its fine dont worry about it :)

- anonymous

forget it, it's cool ill figure it out but thanks for trying to help i can be quite difficult...

- anonymous

what are the factors of -6

- anonymous

-1 x 6
1 x -6
2 x -3
3 x -2

- anonymous

1?

- anonymous

and 2

- anonymous

-3 am i right?

- anonymous

yes those are all roots

- anonymous

k so which do I choose from 1 and 2?

- anonymous

this is an easy problem because the leading coefficient is 1 from x^3 so all those numbers can be divided by 1

- anonymous

your question ask which is not a possible root number

- anonymous

oh ok so 4

- anonymous

so what numbers is not a factor of 6

- anonymous

yes you got it

- anonymous

thank you so much really appreciate it :)

- anonymous

no problem

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