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According to the rational root theorem, which is not a possible rational root of x^3 + 8x^2 - x - 6 = 0? 1 4 2 6

Mathematics
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The possible rational roots are the factors of the constant term divided by the factors of the coefficient of the leading term.
The constant term is -6 The leading term is x^3 and its coefficient is 1
So the possible rational roots are the factors of -6 divided by the factors of 1

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Other answers:

So what are the possible rational roots?
6
What are the factors of -6?
no clue???
Let me give you an example: The factors of 12 are 4 and 3 because 4 x 3 = 12
Also 2 and 6 are factors of 12 because 2 x 6 = 12
Also -1 and -12 are factors of 12 because -1 x -12 = 12
Now you tell me some factors of -6
what two numbers when multiplied equal 6
-6
1
ok. Now gojani91 wants to help you. Good bye
lol ok then
damn you dont have to be rude mertsj
lol its fine dont worry about it :)
forget it, it's cool ill figure it out but thanks for trying to help i can be quite difficult...
what are the factors of -6
-1 x 6 1 x -6 2 x -3 3 x -2
1?
and 2
-3 am i right?
yes those are all roots
k so which do I choose from 1 and 2?
this is an easy problem because the leading coefficient is 1 from x^3 so all those numbers can be divided by 1
your question ask which is not a possible root number
oh ok so 4
so what numbers is not a factor of 6
yes you got it
thank you so much really appreciate it :)
no problem

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