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onegirl
Group Title
Find an equation of the tangent line to h(x) = f(x)g(x) at x = 1
 one year ago
 one year ago
onegirl Group Title
Find an equation of the tangent line to h(x) = f(x)g(x) at x = 1
 one year ago
 one year ago

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ingenuus Group TitleBest ResponseYou've already chosen the best response.0
\[y=[f'(1)g(1) + f(1)g'(1)](x1) + f(1)g(1)\]
 one year ago

campbell_st Group TitleBest ResponseYou've already chosen the best response.0
well you need the point of the curve which will be (1, h(1)) you need to find the slope... but 1st you need to differentiate the function using the product rule h'(x) = f(x)g'(x) + g(x)f'(x) the slope at x = 1 is found by substituting x = 1 into the 1st derivative(above) h'(1) = f(1)g'(1) + g(1)f'(1) now you have a slope h'(1) and point (1, h(1)) use the point slope formula to find the equation of the tangent.
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
so i got y = g(1)f'(1) + f(1)x g'(1)  f(1) g'(1) + f(1)g(1) is it correct?
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
@campell_st ?
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
@campbell_st
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
@ingenuus did i get it right?
 one year ago

ingenuus Group TitleBest ResponseYou've already chosen the best response.0
no the answer is above
 one year ago

ingenuus Group TitleBest ResponseYou've already chosen the best response.0
do you understand the equation y=m(xa) +b ?
 one year ago

ingenuus Group TitleBest ResponseYou've already chosen the best response.0
what is the slope m in your case
 one year ago

ingenuus Group TitleBest ResponseYou've already chosen the best response.0
why is it 1?
 one year ago
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