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ingenuus
 2 years ago
Best ResponseYou've already chosen the best response.0\[y=[f'(1)g(1) + f(1)g'(1)](x1) + f(1)g(1)\]

campbell_st
 2 years ago
Best ResponseYou've already chosen the best response.0well you need the point of the curve which will be (1, h(1)) you need to find the slope... but 1st you need to differentiate the function using the product rule h'(x) = f(x)g'(x) + g(x)f'(x) the slope at x = 1 is found by substituting x = 1 into the 1st derivative(above) h'(1) = f(1)g'(1) + g(1)f'(1) now you have a slope h'(1) and point (1, h(1)) use the point slope formula to find the equation of the tangent.

onegirl
 2 years ago
Best ResponseYou've already chosen the best response.0so i got y = g(1)f'(1) + f(1)x g'(1)  f(1) g'(1) + f(1)g(1) is it correct?

onegirl
 2 years ago
Best ResponseYou've already chosen the best response.0@ingenuus did i get it right?

ingenuus
 2 years ago
Best ResponseYou've already chosen the best response.0no the answer is above

ingenuus
 2 years ago
Best ResponseYou've already chosen the best response.0do you understand the equation y=m(xa) +b ?

ingenuus
 2 years ago
Best ResponseYou've already chosen the best response.0what is the slope m in your case
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