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rajathsbhat

  • one year ago

A point charge Q1=−2 μC is located at x=0, and a point charge Q2=+8 μC is placed at x=−0.5 m on the x-axis of a cartesian coordinate system.

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  1. rajathsbhat
    • one year ago
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    |dw:1361994032659:dw| What is E(x) (in N/C) for x=-43.5 m Just want a quick conformation of whether or not it's 29.428 N/C @Mashy

  2. Mashy
    • one year ago
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    this is the first homework right?? just check the answer.. duh!!

  3. Mashy
    • one year ago
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    i mean in that. you can click on CHECK ANSWER

  4. rajathsbhat
    • one year ago
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    I says it's wrong :P I've checked it a million times

  5. yrelhan4
    • one year ago
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    whats the question?

  6. Mashy
    • one year ago
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    i remember getting the answer right :D

  7. rajathsbhat
    • one year ago
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    dang it, mashy :P

  8. Mashy
    • one year ago
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    do the calculation man... it needs calci.. i dunno where my calci is..

  9. Mashy
    • one year ago
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    wait.. lemme login and see the answers

  10. rajathsbhat
    • one year ago
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    haha and i only did the calculation for a couple thousand times so......

  11. Mashy
    • one year ago
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    my net is slow..!! it not loading :(

  12. Mashy
    • one year ago
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    wait wait.. wait arrr

  13. rajathsbhat
    • one year ago
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    the numbers are not the same for everybody. they're randomly generated.

  14. Mashy
    • one year ago
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    oh is it.. cause i remember the same numbers for me too :P

  15. rajathsbhat
    • one year ago
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    oh

  16. Mashy
    • one year ago
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    wait hold on laa!

  17. Mashy
    • one year ago
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    thats how TV TALKS :D hahaha

  18. rajathsbhat
    • one year ago
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    bahahaaha

  19. Mashy
    • one year ago
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    ok the first one right??

  20. rajathsbhat
    • one year ago
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    uh huh

  21. Mashy
    • one year ago
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    oh yea.. the main question is same.. but the number is differnt lol sorry :D

  22. rajathsbhat
    • one year ago
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    lol toldja :P

  23. Mashy
    • one year ago
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    good luck :D.. you must be doing something wrong.. show your work here!

  24. rajathsbhat
    • one year ago
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    \[\Large9 \times 10^{9} * 2 \times 10^{-6} (\frac{4}{43^{2}}-\frac{1}{43.5^{2}})\] that gives me 29.428

  25. johann079
    • one year ago
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    this is from edx ryt?

  26. rajathsbhat
    • one year ago
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    yes

  27. rajathsbhat
    • one year ago
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    yup

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