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rajathsbhat

A point charge Q1=−2 μC is located at x=0, and a point charge Q2=+8 μC is placed at x=−0.5 m on the x-axis of a cartesian coordinate system.

  • one year ago
  • one year ago

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  1. rajathsbhat
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    |dw:1361994032659:dw| What is E(x) (in N/C) for x=-43.5 m Just want a quick conformation of whether or not it's 29.428 N/C @Mashy

    • one year ago
  2. Mashy
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    this is the first homework right?? just check the answer.. duh!!

    • one year ago
  3. Mashy
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    i mean in that. you can click on CHECK ANSWER

    • one year ago
  4. rajathsbhat
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    I says it's wrong :P I've checked it a million times

    • one year ago
  5. yrelhan4
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    whats the question?

    • one year ago
  6. Mashy
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    i remember getting the answer right :D

    • one year ago
  7. rajathsbhat
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    dang it, mashy :P

    • one year ago
  8. Mashy
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    do the calculation man... it needs calci.. i dunno where my calci is..

    • one year ago
  9. Mashy
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    wait.. lemme login and see the answers

    • one year ago
  10. rajathsbhat
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    haha and i only did the calculation for a couple thousand times so......

    • one year ago
  11. Mashy
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    my net is slow..!! it not loading :(

    • one year ago
  12. Mashy
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    wait wait.. wait arrr

    • one year ago
  13. rajathsbhat
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    the numbers are not the same for everybody. they're randomly generated.

    • one year ago
  14. Mashy
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    oh is it.. cause i remember the same numbers for me too :P

    • one year ago
  15. rajathsbhat
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    oh

    • one year ago
  16. Mashy
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    wait hold on laa!

    • one year ago
  17. Mashy
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    thats how TV TALKS :D hahaha

    • one year ago
  18. rajathsbhat
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    bahahaaha

    • one year ago
  19. Mashy
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    ok the first one right??

    • one year ago
  20. rajathsbhat
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    uh huh

    • one year ago
  21. Mashy
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    oh yea.. the main question is same.. but the number is differnt lol sorry :D

    • one year ago
  22. rajathsbhat
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    lol toldja :P

    • one year ago
  23. Mashy
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    good luck :D.. you must be doing something wrong.. show your work here!

    • one year ago
  24. rajathsbhat
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    \[\Large9 \times 10^{9} * 2 \times 10^{-6} (\frac{4}{43^{2}}-\frac{1}{43.5^{2}})\] that gives me 29.428

    • one year ago
  25. johann079
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    this is from edx ryt?

    • one year ago
  26. rajathsbhat
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    yes

    • one year ago
  27. rajathsbhat
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    yup

    • one year ago
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