anonymous
  • anonymous
A point charge Q1=−2 μC is located at x=0, and a point charge Q2=+8 μC is placed at x=−0.5 m on the x-axis of a cartesian coordinate system.
Physics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
|dw:1361994032659:dw| What is E(x) (in N/C) for x=-43.5 m Just want a quick conformation of whether or not it's 29.428 N/C @Mashy
anonymous
  • anonymous
this is the first homework right?? just check the answer.. duh!!
anonymous
  • anonymous
i mean in that. you can click on CHECK ANSWER

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More answers

anonymous
  • anonymous
I says it's wrong :P I've checked it a million times
yrelhan4
  • yrelhan4
whats the question?
anonymous
  • anonymous
i remember getting the answer right :D
anonymous
  • anonymous
dang it, mashy :P
anonymous
  • anonymous
do the calculation man... it needs calci.. i dunno where my calci is..
anonymous
  • anonymous
wait.. lemme login and see the answers
anonymous
  • anonymous
haha and i only did the calculation for a couple thousand times so......
anonymous
  • anonymous
my net is slow..!! it not loading :(
anonymous
  • anonymous
wait wait.. wait arrr
anonymous
  • anonymous
the numbers are not the same for everybody. they're randomly generated.
anonymous
  • anonymous
oh is it.. cause i remember the same numbers for me too :P
anonymous
  • anonymous
oh
anonymous
  • anonymous
wait hold on laa!
anonymous
  • anonymous
thats how TV TALKS :D hahaha
anonymous
  • anonymous
bahahaaha
anonymous
  • anonymous
ok the first one right??
anonymous
  • anonymous
uh huh
anonymous
  • anonymous
oh yea.. the main question is same.. but the number is differnt lol sorry :D
anonymous
  • anonymous
lol toldja :P
anonymous
  • anonymous
good luck :D.. you must be doing something wrong.. show your work here!
anonymous
  • anonymous
\[\Large9 \times 10^{9} * 2 \times 10^{-6} (\frac{4}{43^{2}}-\frac{1}{43.5^{2}})\] that gives me 29.428
anonymous
  • anonymous
this is from edx ryt?
anonymous
  • anonymous
yes
anonymous
  • anonymous
yup

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