## rajathsbhat 2 years ago A point charge Q1=−2 μC is located at x=0, and a point charge Q2=+8 μC is placed at x=−0.5 m on the x-axis of a cartesian coordinate system.

1. rajathsbhat

|dw:1361994032659:dw| What is E(x) (in N/C) for x=-43.5 m Just want a quick conformation of whether or not it's 29.428 N/C @Mashy

2. Mashy

this is the first homework right?? just check the answer.. duh!!

3. Mashy

i mean in that. you can click on CHECK ANSWER

4. rajathsbhat

I says it's wrong :P I've checked it a million times

5. yrelhan4

whats the question?

6. Mashy

i remember getting the answer right :D

7. rajathsbhat

dang it, mashy :P

8. Mashy

do the calculation man... it needs calci.. i dunno where my calci is..

9. Mashy

10. rajathsbhat

haha and i only did the calculation for a couple thousand times so......

11. Mashy

12. Mashy

wait wait.. wait arrr

13. rajathsbhat

the numbers are not the same for everybody. they're randomly generated.

14. Mashy

oh is it.. cause i remember the same numbers for me too :P

15. rajathsbhat

oh

16. Mashy

wait hold on laa!

17. Mashy

thats how TV TALKS :D hahaha

18. rajathsbhat

bahahaaha

19. Mashy

ok the first one right??

20. rajathsbhat

uh huh

21. Mashy

oh yea.. the main question is same.. but the number is differnt lol sorry :D

22. rajathsbhat

lol toldja :P

23. Mashy

good luck :D.. you must be doing something wrong.. show your work here!

24. rajathsbhat

$\Large9 \times 10^{9} * 2 \times 10^{-6} (\frac{4}{43^{2}}-\frac{1}{43.5^{2}})$ that gives me 29.428

25. johann079

this is from edx ryt?

26. rajathsbhat

yes

27. rajathsbhat

yup