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Find the derivative with and without using the chain rule. f(x) = (x^3  1)^2
 one year ago
 one year ago
Find the derivative with and without using the chain rule. f(x) = (x^3  1)^2
 one year ago
 one year ago

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wioBest ResponseYou've already chosen the best response.0
Do you know how to expand it? \[ (x^31)^2 = (x^31)(x^31) \]
 one year ago

onegirlBest ResponseYou've already chosen the best response.0
is that with the chain rule or?
 one year ago

wioBest ResponseYou've already chosen the best response.0
This is what is called "multiplication"
 one year ago

onegirlBest ResponseYou've already chosen the best response.0
let me try to expand it
 one year ago

wioBest ResponseYou've already chosen the best response.0
Now we will use distributive property of multiplication. \[ (x^31)(x^31) = x^3(x^31)1(x^31)=x^6x^3x^2+1=x^62x^3+1 \]
 one year ago

onegirlBest ResponseYou've already chosen the best response.0
the derivative of x^6  2x^3 + 1 right?
 one year ago

wioBest ResponseYou've already chosen the best response.0
What is the derivative of \(x^6\)?
 one year ago

wioBest ResponseYou've already chosen the best response.0
What is the derivative of \(2x^3\)?
 one year ago

onegirlBest ResponseYou've already chosen the best response.0
so it will be 6x^5  6x^2 ?
 one year ago

wioBest ResponseYou've already chosen the best response.0
Yeah. You don't need to factor it.
 one year ago

onegirlBest ResponseYou've already chosen the best response.0
okay can did we use the chain rule on this one or? no chain rule?
 one year ago

sirm3dBest ResponseYou've already chosen the best response.1
chain rule was not used
 one year ago
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