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Find the derivative with and without using the chain rule. f(x) = (x^3 - 1)^2

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Do you know how to expand it? \[ (x^3-1)^2 = (x^3-1)(x^3-1) \]
is that with the chain rule or?

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Other answers:

This is what is called "multiplication"
you factor it right?
let me try to expand it
Now we will use distributive property of multiplication. \[ (x^3-1)(x^3-1) = x^3(x^3-1)-1(x^3-1)=x^6-x^3-x^2+1=x^6-2x^3+1 \]
Now take the derivative.
ok hold on
the derivative of x^6 - 2x^3 + 1 right?
i got 6x^2 (x^3 - 1)
What is the derivative of \(x^6\)?
What is the derivative of \(-2x^3\)?
its 6x^5
and -6x^2 for -2x^3
so it will be 6x^5 - 6x^2 ?
Yeah. You don't need to factor it.
so that's it?
okay can did we use the chain rule on this one or? no chain rule?
are u there?
chain rule was not used
okay thanks

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