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anonymous
 3 years ago
Find the derivative with and without using the chain rule. f(x) = (x^3  1)^2
anonymous
 3 years ago
Find the derivative with and without using the chain rule. f(x) = (x^3  1)^2

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Do you know how to expand it? \[ (x^31)^2 = (x^31)(x^31) \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is that with the chain rule or?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0This is what is called "multiplication"

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0let me try to expand it

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Now we will use distributive property of multiplication. \[ (x^31)(x^31) = x^3(x^31)1(x^31)=x^6x^3x^2+1=x^62x^3+1 \]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Now take the derivative.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the derivative of x^6  2x^3 + 1 right?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What is the derivative of \(x^6\)?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0What is the derivative of \(2x^3\)?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so it will be 6x^5  6x^2 ?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yeah. You don't need to factor it.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0okay can did we use the chain rule on this one or? no chain rule?
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