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marsxtc Group Title

Need help on Vectors ( Resultant, magnitude direction , was not here for lesson)

  • one year ago
  • one year ago

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  1. Leiaza Group Title
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    I would probably contact your teacher or a fellow student for help

    • one year ago
  2. marsxtc Group Title
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    |dw:1362001343487:dw|

    • one year ago
  3. marsxtc Group Title
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    I dont understand the question, it asks for me to use a graphing utility to graph it and find the resultant , and magnitude / direction?

    • one year ago
  4. Leiaza Group Title
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    there is a free graphing program online that is pretty helpful what does the actual problem say

    • one year ago
  5. marsxtc Group Title
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    says that ^

    • one year ago
  6. amistre64 Group Title
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    the resultant is vector is simliar to an average of the 2 vectors|dw:1362001906941:dw|

    • one year ago
  7. marsxtc Group Title
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    I know its similar, but I'm more of it being xi+xj, at this point I don't understand

    • one year ago
  8. Leiaza Group Title
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    don't you multiply all 3 numbers it's been awhile since I've done this kind of stuff

    • one year ago
  9. amistre64 Group Title
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    the ij parts are notations that are rather pointless in my opinion. the just stand for the xy compnent parts

    • one year ago
  10. amistre64 Group Title
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    the magnitude can be found using law of cosines, but youll have to add 180 one of the vectors to use it

    • one year ago
  11. amistre64 Group Title
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    is that 82 and 12 degrees? with 12 and 8 magnitudes?

    • one year ago
  12. marsxtc Group Title
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    Its 82 and 12 degrees, and the magnitude of the above is 12 and the below is 8

    • one year ago
  13. amistre64 Group Title
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    |dw:1362002125432:dw|

    • one year ago
  14. amistre64 Group Title
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    the component parts of the individual vectors uses sin and cos of their angles times their length <12cos(82),12sin(82)> and <8cos(360-12),8sin(360-12)>

    • one year ago
  15. amistre64 Group Title
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    you can subtract the components parts to get the resultant components

    • one year ago
  16. marsxtc Group Title
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    To find direction isn't the equation tan-1)= b/a?

    • one year ago
  17. amistre64 Group Title
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    it can be i spose. that would be the inverse tangent of the resultant vector components

    • one year ago
  18. amistre64 Group Title
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    say your vectors are something more readable like: <3,4> and <1,1> the resultant is just the subtraction of one from the other <3,4> - <1,1> ------- <2,3> the direction is then that tan^-1 (3/2)

    • one year ago
  19. amistre64 Group Title
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    or am i confusing things again?

    • one year ago
  20. amistre64 Group Title
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    |dw:1362002809662:dw|

    • one year ago
  21. amistre64 Group Title
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    ok, resultant is a+b, not a-b :)

    • one year ago
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