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marsxtc
Need help on Vectors ( Resultant, magnitude direction , was not here for lesson)
I would probably contact your teacher or a fellow student for help
I dont understand the question, it asks for me to use a graphing utility to graph it and find the resultant , and magnitude / direction?
there is a free graphing program online that is pretty helpful what does the actual problem say
the resultant is vector is simliar to an average of the 2 vectors|dw:1362001906941:dw|
I know its similar, but I'm more of it being xi+xj, at this point I don't understand
don't you multiply all 3 numbers it's been awhile since I've done this kind of stuff
the ij parts are notations that are rather pointless in my opinion. the just stand for the xy compnent parts
the magnitude can be found using law of cosines, but youll have to add 180 one of the vectors to use it
is that 82 and 12 degrees? with 12 and 8 magnitudes?
Its 82 and 12 degrees, and the magnitude of the above is 12 and the below is 8
|dw:1362002125432:dw|
the component parts of the individual vectors uses sin and cos of their angles times their length <12cos(82),12sin(82)> and <8cos(360-12),8sin(360-12)>
you can subtract the components parts to get the resultant components
To find direction isn't the equation tan-1)= b/a?
it can be i spose. that would be the inverse tangent of the resultant vector components
say your vectors are something more readable like: <3,4> and <1,1> the resultant is just the subtraction of one from the other <3,4> - <1,1> ------- <2,3> the direction is then that tan^-1 (3/2)
or am i confusing things again?
|dw:1362002809662:dw|
ok, resultant is a+b, not a-b :)