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 one year ago
Find an equation of the tangent line to y = f(x) at x = a. f(x) = sqrt(x^2 + 16), x = 13
 one year ago
Find an equation of the tangent line to y = f(x) at x = a. f(x) = sqrt(x^2 + 16), x = 13

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SithsAndGiggles
 one year ago
Best ResponseYou've already chosen the best response.1\[f(x)=\sqrt{x^2+16}\Rightarrow f(13)=\sqrt{185}\\ f'(x)=\frac{2x}{\sqrt{x^2+16}}\Rightarrow f'(13)=\frac{26}{\sqrt{185}}\] The tangent line is given by the pointslope formula using the point (13, √185) and the slope 26/√185: \[y\sqrt{185}=\frac{26}{\sqrt{185}}(x13)\]

onegirl
 one year ago
Best ResponseYou've already chosen the best response.0so thats the equation? @SithAndGiggles

myko
 one year ago
Best ResponseYou've already chosen the best response.1the derivative is wrong. The nominator should be just x

myko
 one year ago
Best ResponseYou've already chosen the best response.1rest looks right, just change 26 for 13 and that's it

SithsAndGiggles
 one year ago
Best ResponseYou've already chosen the best response.1Thanks for catching the mistake
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