Basis for the column space of A problem:
For #3(a) [ http://ocw.mit.edu/courses/mathematics/18-06sc-linear-algebra-fall-2011/ax-b-and-the-four-subspaces/exam-1/MIT18_06SCF11_ex1s.pdf ], how did the solution go from U to R? when c != 3

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It seems c was chosen to be 4 but why?

divide the second row by (c-3)

subtract row2 from row1

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