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It seems c was chosen to be 4 but why?
divide the second row by (c-3)
subtract row2 from row1
and so on..
c was not chosen to be 4
I get this: http://i.imgur.com/RIZgXlJ.jpg
with what you said
Wait, I think we're miscommunicating. I meant that as in I did what you said and there are still "c"s floating around.
well subtract (-4/(c-3))(row3) from row2 and subtract (2+4/(c-3))(row3) from row1
i think you should look again row reduced echelon form
but wouldn't that have the position which currently has the leading ones' with "c"s?
Also, sorry for being slow right now, my brain is being overworked and I can't take a break because I have exams.
no it won't
look at the picture you uploaded
row 3 is 1 1
to get the row reduced echelon form, you will make everything zero above pivots right?
Yes, I see it. :D Let me just confirm, I get the same answer.
well since row3 is 1 1 it will remove same things above ok i see you got it
I've confirmed that I got it. :D Thanks a lot.
"row 3 is 1 1" is what made me see it instantly.
good luck on your exam! :)
(Also, good luck on yours if you have any.)
Actually, I have another question. Why does it matter what c is equal to if it dissapears thanks to elimination? (Sorry if that's a dumb question.)