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  • s3a

Basis for the column space of A problem: For #3(a) [ http://ocw.mit.edu/courses/mathematics/18-06sc-linear-algebra-fall-2011/ax-b-and-the-four-subspaces/exam-1/MIT18_06SCF11_ex1s.pdf ], how did the solution go from U to R? when c != 3

Linear Algebra
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  • s3a
It seems c was chosen to be 4 but why?
divide the second row by (c-3)
subtract row2 from row1

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Other answers:

and so on..
c was not chosen to be 4
  • s3a
I get this: http://i.imgur.com/RIZgXlJ.jpg
  • s3a
with what you said
good :)
  • s3a
Wait, I think we're miscommunicating. I meant that as in I did what you said and there are still "c"s floating around.
well subtract (-4/(c-3))(row3) from row2 and subtract (2+4/(c-3))(row3) from row1
i think you should look again row reduced echelon form
  • s3a
but wouldn't that have the position which currently has the leading ones' with "c"s?
  • s3a
Also, sorry for being slow right now, my brain is being overworked and I can't take a break because I have exams.
no it won't
look at the picture you uploaded
row 3 is 1 1
  • s3a
OH!
to get the row reduced echelon form, you will make everything zero above pivots right?
  • s3a
Yes, I see it. :D Let me just confirm, I get the same answer.
well since row3 is 1 1 it will remove same things above ok i see you got it
  • s3a
I've confirmed that I got it. :D Thanks a lot.
  • s3a
!
  • s3a
"row 3 is 1 1" is what made me see it instantly.
  • s3a
(Just saying.)
good luck on your exam! :)
  • s3a
Thanks. :)
  • s3a
(Also, good luck on yours if you have any.)
  • s3a
Actually, I have another question. Why does it matter what c is equal to if it dissapears thanks to elimination? (Sorry if that's a dumb question.)

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