Basis for the column space of A problem:
For #3(a) [ http://ocw.mit.edu/courses/mathematics/18-06sc-linear-algebra-fall-2011/ax-b-and-the-four-subspaces/exam-1/MIT18_06SCF11_ex1s.pdf ], how did the solution go from U to R? when c != 3

- s3a

- chestercat

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- s3a

It seems c was chosen to be 4 but why?

- anonymous

divide the second row by (c-3)

- anonymous

subtract row2 from row1

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## More answers

- anonymous

and so on..

- anonymous

c was not chosen to be 4

- s3a

I get this: http://i.imgur.com/RIZgXlJ.jpg

- s3a

with what you said

- anonymous

good :)

- s3a

Wait, I think we're miscommunicating. I meant that as in I did what you said and there are still "c"s floating around.

- anonymous

well subtract (-4/(c-3))(row3) from row2
and subtract (2+4/(c-3))(row3) from row1

- anonymous

i think you should look again row reduced echelon form

- s3a

but wouldn't that have the position which currently has the leading ones' with "c"s?

- s3a

Also, sorry for being slow right now, my brain is being overworked and I can't take a break because I have exams.

- anonymous

no it won't

- anonymous

look at the picture you uploaded

- anonymous

row 3 is 1 1

- s3a

OH!

- anonymous

to get the row reduced echelon form, you will make everything zero above pivots right?

- s3a

Yes, I see it. :D Let me just confirm, I get the same answer.

- anonymous

well since row3 is 1 1
it will remove same things above
ok i see you got it

- s3a

I've confirmed that I got it. :D
Thanks a lot.

- s3a

!

- s3a

"row 3 is 1 1" is what made me see it instantly.

- s3a

(Just saying.)

- anonymous

good luck on your exam! :)

- s3a

Thanks. :)

- s3a

(Also, good luck on yours if you have any.)

- s3a

Actually, I have another question.
Why does it matter what c is equal to if it dissapears thanks to elimination? (Sorry if that's a dumb question.)

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