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s3a
 3 years ago
Why does it matter what c is equal in problem #3a to if it disappears thanks to elimination? (Sorry if that's a dumb question.):
http://ocw.mit.edu/courses/mathematics/1806sclinearalgebrafall2011/axbandthefoursubspaces/exam1/MIT18_06SCF11_ex1s.pdf
Any input would be greatly appreciated!
s3a
 3 years ago
Why does it matter what c is equal in problem #3a to if it disappears thanks to elimination? (Sorry if that's a dumb question.): http://ocw.mit.edu/courses/mathematics/1806sclinearalgebrafall2011/axbandthefoursubspaces/exam1/MIT18_06SCF11_ex1s.pdf Any input would be greatly appreciated!

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if c=3, you cannot divide a number by (c3)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it is zero.. so they have seperated two cases, one when c=3 and the other when c !=3

s3a
 3 years ago
Best ResponseYou've already chosen the best response.0Oh. I see; it's all about the pivot being nonzero.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0no no no it matters because you can't divide a number by 0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if c=3 a thing such as 4/(c3) doesn't exist!!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so you can't make the arguments as those cases for c !=3

s3a
 3 years ago
Best ResponseYou've already chosen the best response.0Ya, that too BUT if we do not divide by (c3) = 0, there is nothing illegal and we get what would be a pivot to be a 0.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what i am saying is the only reason for seperating the cases

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0pivot to be 0 doesn't make any sense because the first appearing 1s are called pivots

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0you can do your elimination process because c!=3(the one you did previously) you can't argue something like 'Why does it matter what c is equal in problem #3a to if it disappears thanks to elimination' since it's not the case! for c=3 you need to make a whole new different arguments

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i mean look at the basis for C(A) they are different!! it matters!!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0two different case, two different logics, two different consequences

s3a
 3 years ago
Best ResponseYou've already chosen the best response.0if c = 3, then it's a simple plugging in of c = 3, and then you have 3  3 = 0 and then you have a matrix with only regular numbers. I think we're miscommunicating again, lol.

s3a
 3 years ago
Best ResponseYou've already chosen the best response.0I know that the bases are different. That's because the pivot from c!=3 is no longer a pivot; it's now a 0.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0what you just said is right well what is it then that you don't understand?

s3a
 3 years ago
Best ResponseYou've already chosen the best response.0I now do understand this problem. :)
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