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s3a
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Why does it matter what c is equal in problem #3a to if it disappears thanks to elimination? (Sorry if that's a dumb question.):
http://ocw.mit.edu/courses/mathematics/1806sclinearalgebrafall2011/axbandthefoursubspaces/exam1/MIT18_06SCF11_ex1s.pdf
Any input would be greatly appreciated!
 one year ago
 one year ago
s3a Group Title
Why does it matter what c is equal in problem #3a to if it disappears thanks to elimination? (Sorry if that's a dumb question.): http://ocw.mit.edu/courses/mathematics/1806sclinearalgebrafall2011/axbandthefoursubspaces/exam1/MIT18_06SCF11_ex1s.pdf Any input would be greatly appreciated!
 one year ago
 one year ago

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ingenuus Group TitleBest ResponseYou've already chosen the best response.1
if c=3, you cannot divide a number by (c3)
 one year ago

ingenuus Group TitleBest ResponseYou've already chosen the best response.1
it is zero.. so they have seperated two cases, one when c=3 and the other when c !=3
 one year ago

s3a Group TitleBest ResponseYou've already chosen the best response.0
Oh. I see; it's all about the pivot being nonzero.
 one year ago

ingenuus Group TitleBest ResponseYou've already chosen the best response.1
no no no it matters because you can't divide a number by 0
 one year ago

ingenuus Group TitleBest ResponseYou've already chosen the best response.1
if c=3 a thing such as 4/(c3) doesn't exist!!
 one year ago

ingenuus Group TitleBest ResponseYou've already chosen the best response.1
so you can't make the arguments as those cases for c !=3
 one year ago

s3a Group TitleBest ResponseYou've already chosen the best response.0
Ya, that too BUT if we do not divide by (c3) = 0, there is nothing illegal and we get what would be a pivot to be a 0.
 one year ago

ingenuus Group TitleBest ResponseYou've already chosen the best response.1
what i am saying is the only reason for seperating the cases
 one year ago

ingenuus Group TitleBest ResponseYou've already chosen the best response.1
pivot to be 0 doesn't make any sense because the first appearing 1s are called pivots
 one year ago

ingenuus Group TitleBest ResponseYou've already chosen the best response.1
you can do your elimination process because c!=3(the one you did previously) you can't argue something like 'Why does it matter what c is equal in problem #3a to if it disappears thanks to elimination' since it's not the case! for c=3 you need to make a whole new different arguments
 one year ago

ingenuus Group TitleBest ResponseYou've already chosen the best response.1
i mean look at the basis for C(A) they are different!! it matters!!
 one year ago

ingenuus Group TitleBest ResponseYou've already chosen the best response.1
two different case, two different logics, two different consequences
 one year ago

s3a Group TitleBest ResponseYou've already chosen the best response.0
if c = 3, then it's a simple plugging in of c = 3, and then you have 3  3 = 0 and then you have a matrix with only regular numbers. I think we're miscommunicating again, lol.
 one year ago

s3a Group TitleBest ResponseYou've already chosen the best response.0
I know that the bases are different. That's because the pivot from c!=3 is no longer a pivot; it's now a 0.
 one year ago

ingenuus Group TitleBest ResponseYou've already chosen the best response.1
what you just said is right well what is it then that you don't understand?
 one year ago

s3a Group TitleBest ResponseYou've already chosen the best response.0
I now do understand this problem. :)
 one year ago
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