Why does it matter what c is equal in problem #3a to if it disappears thanks to elimination? (Sorry if that's a dumb question.): http://ocw.mit.edu/courses/mathematics/18-06sc-linear-algebra-fall-2011/ax-b-and-the-four-subspaces/exam-1/MIT18_06SCF11_ex1s.pdf Any input would be greatly appreciated!

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if c=3, you cannot divide a number by (c-3)

it is zero.. so they have seperated two cases, one when c=3 and the other when c !=3

Oh. I see; it's all about the pivot being non-zero.

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