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 one year ago
Why does it matter what c is equal in problem #3a to if it disappears thanks to elimination? (Sorry if that's a dumb question.):
http://ocw.mit.edu/courses/mathematics/1806sclinearalgebrafall2011/axbandthefoursubspaces/exam1/MIT18_06SCF11_ex1s.pdf
Any input would be greatly appreciated!
 one year ago
Why does it matter what c is equal in problem #3a to if it disappears thanks to elimination? (Sorry if that's a dumb question.): http://ocw.mit.edu/courses/mathematics/1806sclinearalgebrafall2011/axbandthefoursubspaces/exam1/MIT18_06SCF11_ex1s.pdf Any input would be greatly appreciated!

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ingenuus
 one year ago
Best ResponseYou've already chosen the best response.1if c=3, you cannot divide a number by (c3)

ingenuus
 one year ago
Best ResponseYou've already chosen the best response.1it is zero.. so they have seperated two cases, one when c=3 and the other when c !=3

s3a
 one year ago
Best ResponseYou've already chosen the best response.0Oh. I see; it's all about the pivot being nonzero.

ingenuus
 one year ago
Best ResponseYou've already chosen the best response.1no no no it matters because you can't divide a number by 0

ingenuus
 one year ago
Best ResponseYou've already chosen the best response.1if c=3 a thing such as 4/(c3) doesn't exist!!

ingenuus
 one year ago
Best ResponseYou've already chosen the best response.1so you can't make the arguments as those cases for c !=3

s3a
 one year ago
Best ResponseYou've already chosen the best response.0Ya, that too BUT if we do not divide by (c3) = 0, there is nothing illegal and we get what would be a pivot to be a 0.

ingenuus
 one year ago
Best ResponseYou've already chosen the best response.1what i am saying is the only reason for seperating the cases

ingenuus
 one year ago
Best ResponseYou've already chosen the best response.1pivot to be 0 doesn't make any sense because the first appearing 1s are called pivots

ingenuus
 one year ago
Best ResponseYou've already chosen the best response.1you can do your elimination process because c!=3(the one you did previously) you can't argue something like 'Why does it matter what c is equal in problem #3a to if it disappears thanks to elimination' since it's not the case! for c=3 you need to make a whole new different arguments

ingenuus
 one year ago
Best ResponseYou've already chosen the best response.1i mean look at the basis for C(A) they are different!! it matters!!

ingenuus
 one year ago
Best ResponseYou've already chosen the best response.1two different case, two different logics, two different consequences

s3a
 one year ago
Best ResponseYou've already chosen the best response.0if c = 3, then it's a simple plugging in of c = 3, and then you have 3  3 = 0 and then you have a matrix with only regular numbers. I think we're miscommunicating again, lol.

s3a
 one year ago
Best ResponseYou've already chosen the best response.0I know that the bases are different. That's because the pivot from c!=3 is no longer a pivot; it's now a 0.

ingenuus
 one year ago
Best ResponseYou've already chosen the best response.1what you just said is right well what is it then that you don't understand?

s3a
 one year ago
Best ResponseYou've already chosen the best response.0I now do understand this problem. :)
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