Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

See more answers at brainly.com

if c=3, you cannot divide a number by (c-3)

it is zero..
so they have seperated two cases, one when c=3 and the other when c !=3

Oh. I see; it's all about the pivot being non-zero.

no no no
it matters because you can't divide a number by 0

if c=3
a thing such as -4/(c-3) doesn't exist!!

so you can't make the arguments as those cases for c !=3

what i am saying is the only reason for seperating the cases

pivot to be 0 doesn't make any sense because the first appearing 1s are called pivots

i mean look at the basis for C(A)
they are different!!
it matters!!

two different case, two different logics, two different consequences

what you just said is right
well what is it then that you don't understand?

I now do understand this problem. :)