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\[0\le \theta<360\]
\[4\sin \theta=\csc \theta\]

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\[\csc \theta = \dfrac{1}{\sin \theta}\] So you can multiply both sides by \(sin\theta\) to get \(4\sin^2\theta = 1\)
Can you handle it now?

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Yep.

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So what is your answer?

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one sec...

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theta is 30,150 degrees

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Yup.

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By the way, it was 30,150,210,330 because\[x ^{2}=\pm x\]

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Yeah, you're right.