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TrashMan914 Group TitleBest ResponseYou've already chosen the best response.0
If you say so.
 one year ago

TrashMan914 Group TitleBest ResponseYou've already chosen the best response.0
You're welcome.
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
\[w=\frac{ \sqrt(x) }{ 2^2+t3^t } \]
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
sorry it should be sart (t)
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
and find dw/dt
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
that is simple
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
do u want the answer or do u want a step by step solution?
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
when u answer my question i sill proceed
 one year ago

TrashMan914 Group TitleBest ResponseYou've already chosen the best response.0
Math, you can't simply give them the answer. It's against CoC. Guide them to it, so they can answer it themselves.
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
step by step pleae!
 one year ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.0
Quotient rule with respect to (t)..
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
g(x)f(x)'f(x)g(x)'/g(x)^2
 one year ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.0
This right\[w=\frac{\sqrt{x}}{3^t t+2^2}\]
 one year ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.0
You can use chain rule as well
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
therefore, (2t62+t3^t)d/dx(sqrt(t)sqrt(t)(2t^2+t3^t)/(2t^2+t3^t)^2
 one year ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.0
Followed by product rule
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
I dont how how to caculate the root.
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
and how to do (2t62+3t^3) to derivative?
 one year ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.0
The root "x" is just acted like constant, ignore it
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
my teacher told me to do something like 1/2x^1/2? is it wrong
 one year ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.0
is the question this?\[\Large w=\frac{\sqrt{x}}{3^t t+2^2}\]
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
no \[w=\frac{ Sqrt(t) }{ 2t^2+t3^t }\]
 one year ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.0
You sure? the answer is \[\Large \frac{dw}{dt}=\frac{3^t+t \left(3^t (9 \log )+6\right)}{2 t^{3/2} \left(2 t+3^t\right)^2}\]
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
no you dont use log. i have not learnt that yet
 one year ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.0
\[\Large \frac{dw}{dt}=\frac{3^t+t \left(3^t ( \ln(9) )+6\right)}{2 t^{3/2} \left(2 t+3^t\right)^2}\] This?
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
mm maybe but is it possible to go simpler than this?
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
is it not possible?
 one year ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.0
no its not possible, other results are
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
I only have learned power rule, exponential rule and product rule. ( chain rule)
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
step one use the quotient rule..
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
the only trick u have here is 3^t, u may use the table or Doperator...
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
yes I did! its above. I dont know how to break down and power rules.
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
please show me step by step.
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
let me show u how to solve 3^t
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
is that the part ur are struggling with right
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
i will show u step by step but let's break this down
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
thank you so much. I want to cry right now
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
stop crying and fight for the answer
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
ok, i wil! thanks
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
trust me i will let u solve this problem
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
you wont help me?
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
so far i have got
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
damn i wrote the answer on another post hehehe
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
\[\[u = 3^t, \space du = 3^t \ln(3)\]\]
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ (2t^2+t3^t)(\sqrt(x)'\sqrt(x)(2t^2+t3^t) }{ (2t^2+t3^t)^2 }\]
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
\[u = 3^t, \space du = 3^t \ln(3)\]
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
now do u know how this happend
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
but its t3^t?
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
forget the t for now because i want to show u bit by bit
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
because with the t we will get into the product rule
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
ok, I got it. i am taking note hold on
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
du_3^t why its In(3)?
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
good question, now u r starting to listen and that is a good sign of learning...
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
u= 3^t what happens if you take the natural log of both sides?
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
mm im not sure, , negative numbers?
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
ln(u) = ln(3^t)
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
now do u know how to differentiate both sides?
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
No I am not sure.
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
ok no problem, first of all we need some log rules
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
ln(u) = tln(3)
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
did u see what happend to t?
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
power of t went outside of 3 and In?
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
yes this is a primitive ln rule
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
Do i use this everytime i do product?
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
now if y=ln(x) what is y'?
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
u mean every time u have a log of a power?
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
ok, I got it.
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
sorry power of a log
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
now if y=ln(x) what is y'?
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
power of a log, ok !
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
mmm.. y=In/(x)?
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
no y=ln(x) >y'=1/x
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
wow, thats new to me!
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
this is basic differentiation of natural log
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
so now back to our question ln(u) = tln(3) differentiate both sides...
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
ok let me make this even simple
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
so u don't get confused
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
thanks for taking your time.
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{d}{dt}a^t=a^tln(a)\]
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
can u memorize this for now and take it for granted
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
ok use this formula and tell me what is 3^t?
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
hint: a=3
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
mmm.... 3^tIn(3)?
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
well done so memorize that please take a note and keep it in ur mind the same way u know ur name...
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
whats the next step?
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
sorry i was replying to another post on set theory ok
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
now tell me how would u differentiate? \[ 2^2+t3^t \]
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
you mean 2t^2?
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
2^tIn(2)+3tIn(3)?
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
no 2^2 is a constant
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
look at it again
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
trust me by solving this part we are more than half way of solving the problem
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
\[2^2+t3^t\]
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
2^2=4 so when u differentiate a constant u get zero right!?
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
Oh! so its (4t)?
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
ok listen let me solve it
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
can u see how this happened?
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
using the product rule
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
No, wheres 2 go? theres no 2 in the answer
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
\[u=2^2+t3^t \rightarrow du=(3^t+t3^tln3))dt\]
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
listen y=4, what is y'?
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
zero? beacuse its constant
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
zero well done, so y=2^2, y'=?
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
yes well done
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
so differentiate now t3^t
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
no its 3 ^tIn(3)?
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
\[u=2^2+t3^t \rightarrow du=(3^t+t3^tln3))dt\]
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
do u know the product rule?
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
I am not sure
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
uv'+u'v???
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
do u know that rule?
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
yes I do qutiotinent rule?
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
no i said product rule..
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
do u want me to solve the whole thing then u may go and think about it?
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
the whole thing and if i have a question can i ask?
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
then how come u are solving such a problem when u need the fundamentals?
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
I have rules here but im confused how i am apply to . I am able to solve the basic problems
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
i have test next week and I want to do good :(
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
please help me with this question.
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
I am and i will i promised
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
Thank you so much.
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
can u memorize the followings for me ...!
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
if u have u x v then when u want to differentiate it we use something called the product rule...
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
Ok thank you for the fact.
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
example :
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
if u= x^2 and v = e^x, and we were asked to find the derivative of(uv)
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
we apply this rule u v' + u' v
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
so what u do is u=x^2, u'=2x, v=e^x, u=e^x
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
now can u put the above in the following u v' + u' v
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
mm for my question?
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
no for my question
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
if u= x^2 and v = e^x, and we were asked to find the derivative of(uv) so what u do is u=x^2, u'=2x, v=e^x, u=e^x u v' + u' v
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
ok, x^2(e^x)+2x(ve^x)
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
well done but without the v
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
without v in the end?
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
look at what u wrote
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
what is the v doing in the equation and u got rid of it by subbing the functions in terms of x
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
Oh! sorry yes.
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
ok good now solve for ur question t3^t
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
using the product rule then one u just solved above
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
so use the same steps i showed u
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
\[f(x)(2t^2+t3^t)(sqrtx)(sqrtx)(2t^2+t3^t)\] from the producet rule?
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
no i said solve this one t2^t, please follow what i am asking u to do...not ur own rules or derrieres
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
but thats what i have told in the class something like that. or maybe I was wrong. could you show me everything and the answer?
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
right now, I am very confused. ;/ sorry
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
yes but don't forget we decided to break it a part then when we join everything together u'll see the final answer
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
O. I see sorry i was misleading
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
ok then lead now, so wat is diff of t3^t?
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
(t)(3^t)"+t?
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
use the u v' + u' v rule that i just showed u
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
(t)(3^t)+(3^t)(t)?
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
i just told u how to find u' of 3^t
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
i told u to memorize or take a not of it
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
\Large w=\frac{\sqrt{t}}{3^t t+2^2}
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
\[\Large w=\frac{\sqrt{t}}{3^t t+2^2}\]
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
this is ur equation right?
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
its 2t^2+t3^t
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
\[\Large w=\frac{\sqrt{t}}{3^t t+2t^2}\]
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
ok let's us apply the quotient rule
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
so let u =t^(1/2) and v=2t^2+t3^t, so what would u', and v' be?
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
or what would du=? and dv=?
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
(t^1/2)(2t^2+t3^t)+(2t^2+t3^t)
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
u = t^(1/2) that mean u'=(1/2)t^((1/2))
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
yes, i got it
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
good girl now tell me
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
if v=2t^2+t3^t what is v'?
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
how did you guess that i was a girl. 3^2in(3)?
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
why do u think i am wrong?
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
\[v=2t^2+t3^t \rightarrow v'=4t+3^t+t(3^tln(3))\]
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
are u there or surprise?
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
sorry i was looking above to recall again.
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
i told u to write
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
write on a piece of paper
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
\[\frac{g(x)f(x)'f(x)g(x)'}{g(x)^2}\]
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
\[g(x)=\sqrt{t} \space and \space f(x)=2t^2+t3^t\]
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
plug into the equation right?
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
but f'(x) and g"(x) needs to be calculated differently
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
g(x) =t^(1/2), what is g'(x)?
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
nope try again
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
recall \[nt^{(n1)}\]
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
hint n=(1/2)
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
r u there?
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
(1/2) t^(1/2)
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
well done
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
if u solve this one the ur almost done with the question
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
\[ f(t)=2t^2+t3^t \space f'(t)?\]
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
are u there?
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
what happened to the 2t^2 and the product rule, if u look up i solved this for like 23084920384 times
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
4t+2^t+t3^t(In3)
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
good now plug the whole thing in the quotient rule
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
Oh I see thank you! i got it~
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
ya but that is not the end
 one year ago

mathsmind Group TitleBest ResponseYou've already chosen the best response.1
u still have more to the problem
 one year ago

Dodo1 Group TitleBest ResponseYou've already chosen the best response.0
sorry could you wait for 5 mins? im going back to my room and change to my comp?
 one year ago
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