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Dodo1 Group Title

Please help me math talent!

  • one year ago
  • one year ago

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  1. TrashMan914 Group Title
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    If you say so.

    • one year ago
  2. Dodo1 Group Title
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    Thank you!

    • one year ago
  3. TrashMan914 Group Title
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    You're welcome.

    • one year ago
  4. Dodo1 Group Title
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    \[w=\frac{ \sqrt(x) }{ 2^2+t3^t } \]

    • one year ago
  5. Dodo1 Group Title
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    sorry it should be sart (t)

    • one year ago
  6. Dodo1 Group Title
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    and find dw/dt

    • one year ago
  7. mathsmind Group Title
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    that is simple

    • one year ago
  8. mathsmind Group Title
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    do u want the answer or do u want a step by step solution?

    • one year ago
  9. mathsmind Group Title
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    when u answer my question i sill proceed

    • one year ago
  10. TrashMan914 Group Title
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    Math, you can't simply give them the answer. It's against CoC. Guide them to it, so they can answer it themselves.

    • one year ago
  11. Dodo1 Group Title
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    step by step pleae!

    • one year ago
  12. Dodo1 Group Title
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    *please

    • one year ago
  13. .Sam. Group Title
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    Quotient rule with respect to (t)..

    • one year ago
  14. Dodo1 Group Title
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    g(x)f(x)'-f(x)g(x)'/g(x)^2

    • one year ago
  15. .Sam. Group Title
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    This right\[w=\frac{\sqrt{x}}{3^t t+2^2}\]

    • one year ago
  16. .Sam. Group Title
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    You can use chain rule as well

    • one year ago
  17. Dodo1 Group Title
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    therefore, (2t62+t3^t)d/dx(sqrt(t)-sqrt(t)(2t^2+t3^t)/(2t^2+t3^t)^2

    • one year ago
  18. .Sam. Group Title
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    Followed by product rule

    • one year ago
  19. Dodo1 Group Title
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    I dont how how to caculate the root.

    • one year ago
  20. Dodo1 Group Title
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    and how to do (2t62+3t^3) to derivative?

    • one year ago
  21. .Sam. Group Title
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    The root "x" is just acted like constant, ignore it

    • one year ago
  22. Dodo1 Group Title
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    my teacher told me to do something like 1/2x^-1/2? is it wrong

    • one year ago
  23. .Sam. Group Title
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    is the question this?\[\Large w=\frac{\sqrt{x}}{3^t t+2^2}\]

    • one year ago
  24. Dodo1 Group Title
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    no \[w=\frac{ Sqrt(t) }{ 2t^2+t3^t }\]

    • one year ago
  25. .Sam. Group Title
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    You sure? the answer is \[\Large \frac{dw}{dt}=-\frac{3^t+t \left(3^t (9 \log )+6\right)}{2 t^{3/2} \left(2 t+3^t\right)^2}\]

    • one year ago
  26. Dodo1 Group Title
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    no you dont use log. i have not learnt that yet

    • one year ago
  27. .Sam. Group Title
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    \[\Large \frac{dw}{dt}=-\frac{3^t+t \left(3^t ( \ln(9) )+6\right)}{2 t^{3/2} \left(2 t+3^t\right)^2}\] This?

    • one year ago
  28. Dodo1 Group Title
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    mm maybe but is it possible to go simpler than this?

    • one year ago
  29. Dodo1 Group Title
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    is it not possible?

    • one year ago
  30. .Sam. Group Title
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    no its not possible, other results are

    • one year ago
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  31. Dodo1 Group Title
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    I only have learned power rule, exponential rule and product rule. ( chain rule)

    • one year ago
  32. mathsmind Group Title
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    step one use the quotient rule..

    • one year ago
  33. mathsmind Group Title
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    the only trick u have here is 3^t, u may use the table or D-operator...

    • one year ago
  34. Dodo1 Group Title
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    yes I did! its above. I dont know how to break down and power rules.

    • one year ago
  35. Dodo1 Group Title
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    please show me step by step.

    • one year ago
  36. mathsmind Group Title
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    let me show u how to solve 3^t

    • one year ago
  37. mathsmind Group Title
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    is that the part ur are struggling with right

    • one year ago
  38. mathsmind Group Title
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    i will show u step by step but let's break this down

    • one year ago
  39. Dodo1 Group Title
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    Yes :( t3^t

    • one year ago
  40. Dodo1 Group Title
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    thank you so much. I want to cry right now

    • one year ago
  41. mathsmind Group Title
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    stop crying and fight for the answer

    • one year ago
  42. Dodo1 Group Title
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    ok, i wil! thanks

    • one year ago
  43. mathsmind Group Title
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    trust me i will let u solve this problem

    • one year ago
  44. Dodo1 Group Title
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    you wont help me?

    • one year ago
  45. Dodo1 Group Title
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    so far i have got

    • one year ago
  46. mathsmind Group Title
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    damn i wrote the answer on another post hehehe

    • one year ago
  47. mathsmind Group Title
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    \[\[u = 3^t, \space du = 3^t \ln(3)\]\]

    • one year ago
  48. Dodo1 Group Title
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    \[\frac{ (2t^2+t3^t)(\sqrt(x)'-\sqrt(x)(2t^2+t3^t) }{ (2t^2+t3^t)^2 }\]

    • one year ago
  49. mathsmind Group Title
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    \[u = 3^t, \space du = 3^t \ln(3)\]

    • one year ago
  50. mathsmind Group Title
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    now do u know how this happend

    • one year ago
  51. Dodo1 Group Title
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    but its t3^t?

    • one year ago
  52. mathsmind Group Title
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    forget the t for now because i want to show u bit by bit

    • one year ago
  53. mathsmind Group Title
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    because with the t we will get into the product rule

    • one year ago
  54. Dodo1 Group Title
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    ok, I got it. i am taking note hold on

    • one year ago
  55. Dodo1 Group Title
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    du_3^t why its In(3)?

    • one year ago
  56. mathsmind Group Title
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    good question, now u r starting to listen and that is a good sign of learning...

    • one year ago
  57. mathsmind Group Title
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    u= 3^t what happens if you take the natural log of both sides?

    • one year ago
  58. Dodo1 Group Title
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    mm im not sure, , negative numbers?

    • one year ago
  59. mathsmind Group Title
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    ln(u) = ln(3^t)

    • one year ago
  60. mathsmind Group Title
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    now do u know how to differentiate both sides?

    • one year ago
  61. Dodo1 Group Title
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    No I am not sure.

    • one year ago
  62. Dodo1 Group Title
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    mutiply?

    • one year ago
  63. mathsmind Group Title
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    ok no problem, first of all we need some log rules

    • one year ago
  64. mathsmind Group Title
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    ln(u) = tln(3)

    • one year ago
  65. mathsmind Group Title
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    did u see what happend to t?

    • one year ago
  66. Dodo1 Group Title
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    power of t went outside of 3 and In?

    • one year ago
  67. mathsmind Group Title
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    yes this is a primitive ln rule

    • one year ago
  68. Dodo1 Group Title
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    Oh I see.

    • one year ago
  69. Dodo1 Group Title
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    Do i use this everytime i do product?

    • one year ago
  70. mathsmind Group Title
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    now if y=ln(x) what is y'?

    • one year ago
  71. mathsmind Group Title
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    u mean every time u have a log of a power?

    • one year ago
  72. Dodo1 Group Title
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    ok, I got it.

    • one year ago
  73. mathsmind Group Title
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    sorry power of a log

    • one year ago
  74. mathsmind Group Title
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    now if y=ln(x) what is y'?

    • one year ago
  75. Dodo1 Group Title
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    power of a log, ok !

    • one year ago
  76. Dodo1 Group Title
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    mmm.. y=In/(x)?

    • one year ago
  77. mathsmind Group Title
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    no y=ln(x) ->y'=1/x

    • one year ago
  78. Dodo1 Group Title
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    wow, thats new to me!

    • one year ago
  79. mathsmind Group Title
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    this is basic differentiation of natural log

    • one year ago
  80. mathsmind Group Title
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    so now back to our question ln(u) = tln(3) differentiate both sides...

    • one year ago
  81. Dodo1 Group Title
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    tIn(3)/x

    • one year ago
  82. mathsmind Group Title
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    ok let me make this even simple

    • one year ago
  83. mathsmind Group Title
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    so u don't get confused

    • one year ago
  84. Dodo1 Group Title
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    thanks for taking your time.

    • one year ago
  85. mathsmind Group Title
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    \[\frac{d}{dt}a^t=a^tln(a)\]

    • one year ago
  86. mathsmind Group Title
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    can u memorize this for now and take it for granted

    • one year ago
  87. Dodo1 Group Title
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    Ok,

    • one year ago
  88. mathsmind Group Title
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    ok use this formula and tell me what is 3^t?

    • one year ago
  89. mathsmind Group Title
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    hint: a=3

    • one year ago
  90. Dodo1 Group Title
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    mmm.... 3^tIn(3)?

    • one year ago
  91. mathsmind Group Title
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    well done so memorize that please take a note and keep it in ur mind the same way u know ur name...

    • one year ago
  92. Dodo1 Group Title
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    Ok I will.

    • one year ago
  93. Dodo1 Group Title
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    whats the next step?

    • one year ago
  94. mathsmind Group Title
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    sorry i was replying to another post on set theory ok

    • one year ago
  95. Dodo1 Group Title
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    its okay.

    • one year ago
  96. mathsmind Group Title
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    now tell me how would u differentiate? \[ 2^2+t3^t \]

    • one year ago
  97. Dodo1 Group Title
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    you mean 2t^2?

    • one year ago
  98. Dodo1 Group Title
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    2^tIn(2)+3tIn(3)?

    • one year ago
  99. mathsmind Group Title
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    no 2^2 is a constant

    • one year ago
  100. mathsmind Group Title
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    look at it again

    • one year ago
  101. mathsmind Group Title
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    trust me by solving this part we are more than half way of solving the problem

    • one year ago
  102. mathsmind Group Title
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    \[2^2+t3^t\]

    • one year ago
  103. mathsmind Group Title
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    2^2=4 so when u differentiate a constant u get zero right!?

    • one year ago
  104. Dodo1 Group Title
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    Oh! so its (4t)?

    • one year ago
  105. mathsmind Group Title
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    ok listen let me solve it

    • one year ago
  106. mathsmind Group Title
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    can u see how this happened?

    • one year ago
  107. mathsmind Group Title
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    using the product rule

    • one year ago
  108. Dodo1 Group Title
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    No, wheres 2 go? theres no 2 in the answer

    • one year ago
  109. mathsmind Group Title
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    \[u=2^2+t3^t \rightarrow du=(3^t+t3^tln3))dt\]

    • one year ago
  110. mathsmind Group Title
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    listen y=4, what is y'?

    • one year ago
  111. Dodo1 Group Title
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    y=-4?

    • one year ago
  112. Dodo1 Group Title
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    zero? beacuse its constant

    • one year ago
  113. mathsmind Group Title
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    zero well done, so y=2^2, y'=?

    • one year ago
  114. Dodo1 Group Title
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    zero?

    • one year ago
  115. mathsmind Group Title
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    yes well done

    • one year ago
  116. mathsmind Group Title
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    so differentiate now t3^t

    • one year ago
  117. Dodo1 Group Title
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    3^3In(t)?

    • one year ago
  118. Dodo1 Group Title
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    no its 3 ^tIn(3)?

    • one year ago
  119. mathsmind Group Title
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    \[u=2^2+t3^t \rightarrow du=(3^t+t3^tln3))dt\]

    • one year ago
  120. mathsmind Group Title
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    do u know the product rule?

    • one year ago
  121. Dodo1 Group Title
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    I am not sure

    • one year ago
  122. mathsmind Group Title
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    uv'+u'v???

    • one year ago
  123. mathsmind Group Title
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    do u know that rule?

    • one year ago
  124. Dodo1 Group Title
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    yes I do qutiotinent rule?

    • one year ago
  125. mathsmind Group Title
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    no i said product rule..

    • one year ago
  126. mathsmind Group Title
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    do u want me to solve the whole thing then u may go and think about it?

    • one year ago
  127. Dodo1 Group Title
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    sorry no.

    • one year ago
  128. Dodo1 Group Title
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    Yes please,

    • one year ago
  129. Dodo1 Group Title
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    the whole thing and if i have a question can i ask?

    • one year ago
  130. mathsmind Group Title
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    then how come u are solving such a problem when u need the fundamentals?

    • one year ago
  131. Dodo1 Group Title
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    I have rules here but im confused how i am apply to . I am able to solve the basic problems

    • one year ago
  132. Dodo1 Group Title
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    i have test next week and I want to do good :(

    • one year ago
  133. Dodo1 Group Title
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    please help me with this question.

    • one year ago
  134. mathsmind Group Title
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    I am and i will i promised

    • one year ago
  135. Dodo1 Group Title
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    Thank you so much.

    • one year ago
  136. mathsmind Group Title
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    can u memorize the followings for me ...!

    • one year ago
  137. mathsmind Group Title
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    if u have u x v then when u want to differentiate it we use something called the product rule...

    • one year ago
  138. Dodo1 Group Title
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    Ok thank you for the fact.

    • one year ago
  139. mathsmind Group Title
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    example :

    • one year ago
  140. mathsmind Group Title
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    if u= x^2 and v = e^x, and we were asked to find the derivative of(uv)

    • one year ago
  141. mathsmind Group Title
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    we apply this rule u v' + u' v

    • one year ago
  142. Dodo1 Group Title
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    ok!

    • one year ago
  143. mathsmind Group Title
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    so what u do is u=x^2, u'=2x, v=e^x, u=e^x

    • one year ago
  144. mathsmind Group Title
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    now can u put the above in the following u v' + u' v

    • one year ago
  145. Dodo1 Group Title
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    mm for my question?

    • one year ago
  146. mathsmind Group Title
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    no for my question

    • one year ago
  147. mathsmind Group Title
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    if u= x^2 and v = e^x, and we were asked to find the derivative of(uv) so what u do is u=x^2, u'=2x, v=e^x, u=e^x u v' + u' v

    • one year ago
  148. Dodo1 Group Title
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    ok, x^2(e^x)+2x(ve^x)

    • one year ago
  149. mathsmind Group Title
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    well done but without the v

    • one year ago
  150. Dodo1 Group Title
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    without v in the end?

    • one year ago
  151. mathsmind Group Title
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    look at what u wrote

    • one year ago
  152. Dodo1 Group Title
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    yes,

    • one year ago
  153. mathsmind Group Title
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    what is the v doing in the equation and u got rid of it by subbing the functions in terms of x

    • one year ago
  154. Dodo1 Group Title
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    Oh! sorry yes.

    • one year ago
  155. mathsmind Group Title
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    ok good now solve for ur question t3^t

    • one year ago
  156. Dodo1 Group Title
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    how?

    • one year ago
  157. mathsmind Group Title
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    using the product rule then one u just solved above

    • one year ago
  158. mathsmind Group Title
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    so use the same steps i showed u

    • one year ago
  159. Dodo1 Group Title
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    \[f(x)(2t^2+t3^t)(sqrtx)-(sqrtx)(2t^2+t3^t)\] from the producet rule?

    • one year ago
  160. mathsmind Group Title
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    no i said solve this one t2^t, please follow what i am asking u to do...not ur own rules or derrieres

    • one year ago
  161. Dodo1 Group Title
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    but thats what i have told in the class something like that. or maybe I was wrong. could you show me everything and the answer?

    • one year ago
  162. Dodo1 Group Title
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    right now, I am very confused. ;/ sorry

    • one year ago
  163. mathsmind Group Title
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    yes but don't forget we decided to break it a part then when we join everything together u'll see the final answer

    • one year ago
  164. Dodo1 Group Title
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    O. I see sorry i was misleading

    • one year ago
  165. mathsmind Group Title
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    ok then lead now, so wat is diff of t3^t?

    • one year ago
  166. Dodo1 Group Title
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    (t)(3^t)"+t?

    • one year ago
  167. mathsmind Group Title
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    use the u v' + u' v rule that i just showed u

    • one year ago
  168. Dodo1 Group Title
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    (t)(3^t)+(3^t)(t)?

    • one year ago
  169. mathsmind Group Title
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    i just told u how to find u' of 3^t

    • one year ago
  170. mathsmind Group Title
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    i told u to memorize or take a not of it

    • one year ago
  171. mathsmind Group Title
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    \Large w=\frac{\sqrt{t}}{3^t t+2^2}

    • one year ago
  172. mathsmind Group Title
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    \[\Large w=\frac{\sqrt{t}}{3^t t+2^2}\]

    • one year ago
  173. mathsmind Group Title
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    this is ur equation right?

    • one year ago
  174. Dodo1 Group Title
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    no.

    • one year ago
  175. Dodo1 Group Title
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    its 2t^2+t3^t

    • one year ago
  176. mathsmind Group Title
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    oh ok

    • one year ago
  177. mathsmind Group Title
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    \[\Large w=\frac{\sqrt{t}}{3^t t+2t^2}\]

    • one year ago
  178. mathsmind Group Title
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    ok let's us apply the quotient rule

    • one year ago
  179. mathsmind Group Title
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    so let u =t^(1/2) and v=2t^2+t3^t, so what would u', and v' be?

    • one year ago
  180. mathsmind Group Title
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    or what would du=? and dv=?

    • one year ago
  181. Dodo1 Group Title
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    uv'=vu"

    • one year ago
  182. Dodo1 Group Title
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    (t^1/2)(2t^2+t3^t)+(2t^2+t3^t)

    • one year ago
  183. mathsmind Group Title
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    u = t^(1/2) that mean u'=(1/2)t^(-(1/2))

    • one year ago
  184. Dodo1 Group Title
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    yes, i got it

    • one year ago
  185. Dodo1 Group Title
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    ops sorry

    • one year ago
  186. mathsmind Group Title
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    good girl now tell me

    • one year ago
  187. mathsmind Group Title
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    if v=2t^2+t3^t what is v'?

    • one year ago
  188. Dodo1 Group Title
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    how did you guess that i was a girl. 3^2in(3)?

    • one year ago
  189. mathsmind Group Title
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    why do u think i am wrong?

    • one year ago
  190. Dodo1 Group Title
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    ?

    • one year ago
  191. mathsmind Group Title
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    \[v=2t^2+t3^t \rightarrow v'=4t+3^t+t(3^tln(3))\]

    • one year ago
  192. mathsmind Group Title
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    are u there or surprise?

    • one year ago
  193. Dodo1 Group Title
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    sorry i was looking above to recall again.

    • one year ago
  194. mathsmind Group Title
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    i told u to write

    • one year ago
  195. mathsmind Group Title
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    write on a piece of paper

    • one year ago
  196. Dodo1 Group Title
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    I am.

    • one year ago
  197. mathsmind Group Title
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    \[\frac{g(x)f(x)'-f(x)g(x)'}{g(x)^2}\]

    • one year ago
  198. Dodo1 Group Title
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    yes,

    • one year ago
  199. mathsmind Group Title
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    \[g(x)=\sqrt{t} \space and \space f(x)=2t^2+t3^t\]

    • one year ago
  200. Dodo1 Group Title
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    plug into the equation right?

    • one year ago
  201. mathsmind Group Title
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    yes

    • one year ago
  202. Dodo1 Group Title
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    but f'(x) and g"(x) needs to be calculated differently

    • one year ago
  203. mathsmind Group Title
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    yes

    • one year ago
  204. mathsmind Group Title
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    g(x) =t^(1/2), what is g'(x)?

    • one year ago
  205. Dodo1 Group Title
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    1/2t^-(1/2)

    • one year ago
  206. mathsmind Group Title
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    how?

    • one year ago
  207. mathsmind Group Title
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    nope try again

    • one year ago
  208. mathsmind Group Title
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    recall \[nt^{(n-1)}\]

    • one year ago
  209. mathsmind Group Title
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    Medals 1

    hint n=(1/2)

    • one year ago
  210. mathsmind Group Title
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    r u there?

    • one year ago
  211. Dodo1 Group Title
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    (1/2) t^-(1/2)

    • one year ago
  212. mathsmind Group Title
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    well done

    • one year ago
  213. mathsmind Group Title
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    if u solve this one the ur almost done with the question

    • one year ago
  214. mathsmind Group Title
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    \[ f(t)=2t^2+t3^t \space f'(t)?\]

    • one year ago
  215. mathsmind Group Title
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    are u there?

    • one year ago
  216. Dodo1 Group Title
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    t3^t(in3)?

    • one year ago
  217. mathsmind Group Title
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    what happened to the 2t^2 and the product rule, if u look up i solved this for like 23084920384 times

    • one year ago
  218. Dodo1 Group Title
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    4t+2^t+t3^t(In3)

    • one year ago
  219. mathsmind Group Title
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    good now plug the whole thing in the quotient rule

    • one year ago
  220. Dodo1 Group Title
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    Oh I see thank you! i got it~

    • one year ago
  221. Dodo1 Group Title
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    :)

    • one year ago
  222. mathsmind Group Title
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    ya but that is not the end

    • one year ago
  223. mathsmind Group Title
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    u still have more to the problem

    • one year ago
  224. Dodo1 Group Title
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    sorry could you wait for 5 mins? im going back to my room and change to my comp?

    • one year ago
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