onegirl
Use the position function to find the velocity at time t = a (HINT: Velocity is the first derivative of the position function). S(t) = t2 - sin√t, a = 0
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onegirl
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@mathsmind can u help?
harsimran_hs4
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v = ds/dt can you find v?
onegirl
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thats the formula?
harsimran_hs4
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yes you need to differentiate displacement once wrt time to get velocity
onegirl
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ok
harsimran_hs4
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find out the derivative and tell
onegirl
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the derivative of t^2 - sin sqrt(t) right?
genius12
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\[V(t)=S'(t)=2t-\cos (\sqrt t)*\frac{ 1 }{ 2 }t^{-\frac{ 1 }{ 2 }} \]\[V(a)=V(0)=2(0)-\cos(\sqrt 0)*\frac{ 1 }{ 2 }(0)^{-\frac{ 1 }{ 2 }}\rightarrow V(0)=0\]
harsimran_hs4
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@genius12 this is not done
you should let @onegirl try out herself
onegirl
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yea i wanna know how i do it
genius12
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Well if you look at the work I did above to get the answer, you should be able to figure it out. If you can't understand any of the steps or how I got to a certain point, ask me.
onegirl
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okay