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onegirl
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Use the position function to find the velocity at time t = a (HINT: Velocity is the first derivative of the position function). S(t) = t2  sin√t, a = 0
 one year ago
 one year ago
onegirl Group Title
Use the position function to find the velocity at time t = a (HINT: Velocity is the first derivative of the position function). S(t) = t2  sin√t, a = 0
 one year ago
 one year ago

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onegirl Group TitleBest ResponseYou've already chosen the best response.0
@mathsmind can u help?
 one year ago

harsimran_hs4 Group TitleBest ResponseYou've already chosen the best response.0
v = ds/dt can you find v?
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
thats the formula?
 one year ago

harsimran_hs4 Group TitleBest ResponseYou've already chosen the best response.0
yes you need to differentiate displacement once wrt time to get velocity
 one year ago

harsimran_hs4 Group TitleBest ResponseYou've already chosen the best response.0
find out the derivative and tell
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
the derivative of t^2  sin sqrt(t) right?
 one year ago

genius12 Group TitleBest ResponseYou've already chosen the best response.0
\[V(t)=S'(t)=2t\cos (\sqrt t)*\frac{ 1 }{ 2 }t^{\frac{ 1 }{ 2 }} \]\[V(a)=V(0)=2(0)\cos(\sqrt 0)*\frac{ 1 }{ 2 }(0)^{\frac{ 1 }{ 2 }}\rightarrow V(0)=0\]
 one year ago

harsimran_hs4 Group TitleBest ResponseYou've already chosen the best response.0
@genius12 this is not done you should let @onegirl try out herself
 one year ago

onegirl Group TitleBest ResponseYou've already chosen the best response.0
yea i wanna know how i do it
 one year ago

genius12 Group TitleBest ResponseYou've already chosen the best response.0
Well if you look at the work I did above to get the answer, you should be able to figure it out. If you can't understand any of the steps or how I got to a certain point, ask me.
 one year ago
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