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onegirl

  • 2 years ago

Use the position function to find the velocity at time t = a (HINT: Velocity is the first derivative of the position function). S(t) = t2 - sin√t, a = 0

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  1. onegirl
    • 2 years ago
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    @mathsmind can u help?

  2. harsimran_hs4
    • 2 years ago
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    v = ds/dt can you find v?

  3. onegirl
    • 2 years ago
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    thats the formula?

  4. harsimran_hs4
    • 2 years ago
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    yes you need to differentiate displacement once wrt time to get velocity

  5. onegirl
    • 2 years ago
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    ok

  6. harsimran_hs4
    • 2 years ago
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    find out the derivative and tell

  7. onegirl
    • 2 years ago
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    the derivative of t^2 - sin sqrt(t) right?

  8. genius12
    • 2 years ago
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    \[V(t)=S'(t)=2t-\cos (\sqrt t)*\frac{ 1 }{ 2 }t^{-\frac{ 1 }{ 2 }} \]\[V(a)=V(0)=2(0)-\cos(\sqrt 0)*\frac{ 1 }{ 2 }(0)^{-\frac{ 1 }{ 2 }}\rightarrow V(0)=0\]

  9. harsimran_hs4
    • 2 years ago
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    @genius12 this is not done you should let @onegirl try out herself

  10. onegirl
    • 2 years ago
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    yea i wanna know how i do it

  11. genius12
    • 2 years ago
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    Well if you look at the work I did above to get the answer, you should be able to figure it out. If you can't understand any of the steps or how I got to a certain point, ask me.

  12. onegirl
    • 2 years ago
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    okay

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