Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Use the position function to find the velocity at time t = a (HINT: Velocity is the first derivative of the position function). S(t) = t2 - sin√t, a = 0

Mathematics
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SIGN UP FOR FREE
@mathsmind can u help?
v = ds/dt can you find v?
thats the formula?

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

yes you need to differentiate displacement once wrt time to get velocity
ok
find out the derivative and tell
the derivative of t^2 - sin sqrt(t) right?
\[V(t)=S'(t)=2t-\cos (\sqrt t)*\frac{ 1 }{ 2 }t^{-\frac{ 1 }{ 2 }} \]\[V(a)=V(0)=2(0)-\cos(\sqrt 0)*\frac{ 1 }{ 2 }(0)^{-\frac{ 1 }{ 2 }}\rightarrow V(0)=0\]
@genius12 this is not done you should let @onegirl try out herself
yea i wanna know how i do it
Well if you look at the work I did above to get the answer, you should be able to figure it out. If you can't understand any of the steps or how I got to a certain point, ask me.
okay

Not the answer you are looking for?

Search for more explanations.

Ask your own question