## Comm.Dan This is a clarification question Am I doing this right so far? This is Graphing Quadratic Functions First, you find the Axis Symmetry by using x=-b over 2a Second, you put the x back into the original equation Third, put the x and y together to make the vertex Fourth, the C is the y-intercept, and then rewrite the y-intercept as 0 (zero), then the y-intercept Then, graph the axis of symmetry, vertex, y-intercept, and the two other points one year ago one year ago

1. Comm.Dan

Here is an example of a problem $y =x ^{2}-2$

2. Comm.Dan

then after the x squared minus 2 there is minus 3

3. Comm.Dan

@seiga

4. e.cociuba
5. Comm.Dan

Ok then. I will teach you how I was taught to do it. @seiga

6. Comm.Dan

I am upload the pages right now @Pologirl19

7. Comm.Dan

Thanks again for trying to help me @e.cociuba

8. Comm.Dan

y=-4x squared +12x-5

9. Comm.Dan

@Pologirl19

10. Comm.Dan

$x =\frac{ -12}{ 2 (-4) } = \frac{ -12 }{ -8}=\frac{ 3 }{ 2 }=1.5$

11. Comm.Dan

$y =-4(1.5^{2})+12(1.5)-5=-4(2.25)+18-5=-10+18-5=8-5=3$

12. Comm.Dan

2 minutes ago I did the first step A few moments ago I did the second step

13. Comm.Dan

$(1.5,3) Vertex y-intercept Rewrite y-intercept as (0,-5)$

14. Comm.Dan

$Axis of Symmetry is 1.5$

15. Comm.Dan

I will do the graph now

16. Pologirl19

The 5th one where you plugging it in you said it was -10+18-5. It is -9+18-5. So then it would equal 4. not 3

17. Comm.Dan

-4*2.25=10.00 is what I got

18. Comm.Dan

19. Comm.Dan

Thank you

20. Pologirl19

K well everything I see is good so you are good

21. Comm.Dan

Thank you. @Pologirl19 Do you have any questions?

22. Pologirl19

No I don't it was a clear to me

23. Comm.Dan

Ok @Pologirl19

24. e.cociuba

np:)