This is a clarification question
Am I doing this right so far?
This is Graphing Quadratic Functions
First, you find the Axis Symmetry by using x=-b over 2a
Second, you put the x back into the original equation
Third, put the x and y together to make the vertex
Fourth, the C is the y-intercept, and then rewrite the y-intercept as 0 (zero), then the y-intercept
Then, graph the axis of symmetry, vertex, y-intercept, and the two other points

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Here is an example of a problem \[y =x ^{2}-2\]

then after the x squared minus 2 there is minus 3

@seiga

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