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This is a clarification question Am I doing this right so far? This is Graphing Quadratic Functions First, you find the Axis Symmetry by using x=-b over 2a Second, you put the x back into the original equation Third, put the x and y together to make the vertex Fourth, the C is the y-intercept, and then rewrite the y-intercept as 0 (zero), then the y-intercept Then, graph the axis of symmetry, vertex, y-intercept, and the two other points

Mathematics
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Here is an example of a problem \[y =x ^{2}-2\]
then after the x squared minus 2 there is minus 3

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Other answers:

http://www.mathplanet.com/education/algebra-2/quadratic-functions-and-inequalities/how-to-graph-quadratic-functions This will definatly help u!
Ok then. I will teach you how I was taught to do it. @seiga
I am upload the pages right now @Pologirl19
Thanks again for trying to help me @e.cociuba
y=-4x squared +12x-5
\[x =\frac{ -12}{ 2 (-4) } = \frac{ -12 }{ -8}=\frac{ 3 }{ 2 }=1.5 \]
\[y =-4(1.5^{2})+12(1.5)-5=-4(2.25)+18-5=-10+18-5=8-5=3\]
2 minutes ago I did the first step A few moments ago I did the second step
\[(1.5,3) Vertex y-intercept Rewrite y-intercept as (0,-5)\]
\[Axis of Symmetry is 1.5\]
I will do the graph now
The 5th one where you plugging it in you said it was -10+18-5. It is -9+18-5. So then it would equal 4. not 3
-4*2.25=10.00 is what I got
Thank you
K well everything I see is good so you are good
Thank you. @Pologirl19 Do you have any questions?
No I don't it was a clear to me
np:)

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