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Kagome_gurl8

  • one year ago

Anyone want to check my answers...? Please?

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  1. Kagome_gurl8
    • one year ago
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  2. Kagome_gurl8
    • one year ago
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    @Hero

  3. wio
    • one year ago
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    What? Both answers look funky.

  4. wio
    • one year ago
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    \[ \log_c(a/b) = \log_c(a)-\log_c(b) \]

  5. Kagome_gurl8
    • one year ago
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    OHHH now i see....

  6. wio
    • one year ago
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    \[ \log_c(a^b) = \underbrace{\log_c(a)+\log_c(a) +...+\log_c(a)}_{b\text{ times}} = b\log_c(a) \]

  7. Kagome_gurl8
    • one year ago
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    What about my second answer? I couldn't really log it correctly but i ended up getting that

  8. whpalmer4
    • one year ago
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    As @wio said, \[\log_c(a^b) = b \log_c (a)\] What would that make the correct answer be for the second question?

  9. Kagome_gurl8
    • one year ago
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    Sorry just refreshed the page....

  10. whpalmer4
    • one year ago
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    Answer?

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spraguer (Moderator)
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is replying to Can someone tell me what button the professor is hitting...

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