anonymous
  • anonymous
Anyone want to check my answers...? Please?
Mathematics
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
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anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
What? Both answers look funky.

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anonymous
  • anonymous
\[ \log_c(a/b) = \log_c(a)-\log_c(b) \]
anonymous
  • anonymous
OHHH now i see....
anonymous
  • anonymous
\[ \log_c(a^b) = \underbrace{\log_c(a)+\log_c(a) +...+\log_c(a)}_{b\text{ times}} = b\log_c(a) \]
anonymous
  • anonymous
What about my second answer? I couldn't really log it correctly but i ended up getting that
whpalmer4
  • whpalmer4
As @wio said, \[\log_c(a^b) = b \log_c (a)\] What would that make the correct answer be for the second question?
anonymous
  • anonymous
Sorry just refreshed the page....
whpalmer4
  • whpalmer4
Answer?

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