## anonymous 3 years ago Anyone want to check my answers...? Please?

1. anonymous

2. anonymous

@Hero

3. anonymous

4. anonymous

$\log_c(a/b) = \log_c(a)-\log_c(b)$

5. anonymous

OHHH now i see....

6. anonymous

$\log_c(a^b) = \underbrace{\log_c(a)+\log_c(a) +...+\log_c(a)}_{b\text{ times}} = b\log_c(a)$

7. anonymous

What about my second answer? I couldn't really log it correctly but i ended up getting that

8. whpalmer4

As @wio said, $\log_c(a^b) = b \log_c (a)$ What would that make the correct answer be for the second question?

9. anonymous

Sorry just refreshed the page....

10. whpalmer4