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Kagome_gurl8
 2 years ago
Anyone want to check my answers...? Please?
Kagome_gurl8
 2 years ago
Anyone want to check my answers...? Please?

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wio
 2 years ago
Best ResponseYou've already chosen the best response.1What? Both answers look funky.

wio
 2 years ago
Best ResponseYou've already chosen the best response.1\[ \log_c(a/b) = \log_c(a)\log_c(b) \]

Kagome_gurl8
 2 years ago
Best ResponseYou've already chosen the best response.0OHHH now i see....

wio
 2 years ago
Best ResponseYou've already chosen the best response.1\[ \log_c(a^b) = \underbrace{\log_c(a)+\log_c(a) +...+\log_c(a)}_{b\text{ times}} = b\log_c(a) \]

Kagome_gurl8
 2 years ago
Best ResponseYou've already chosen the best response.0What about my second answer? I couldn't really log it correctly but i ended up getting that

whpalmer4
 2 years ago
Best ResponseYou've already chosen the best response.0As @wio said, \[\log_c(a^b) = b \log_c (a)\] What would that make the correct answer be for the second question?

Kagome_gurl8
 2 years ago
Best ResponseYou've already chosen the best response.0Sorry just refreshed the page....
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