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What?\[1 + 2\sin(\theta) = 1\]

then?

\[2\sin(\theta) = 0\]Find the solutions to theta.

\[\Theta = 0\]

Yeah, there are many solutions

how to find the intersection of the curve?

Indeed.

But \(2\pi\) is one too.

what are the intersections of the curve?

one of the point of intersection of the curve is (1,0), ?

If we can write the coordinates as \((\theta,r)\) then \((0,1)\) is the intersection.

Wait, do you have polar coordinates?!

@ParthKohli 2pi is just a depiction of one complete cycle
so 2pi coincides with zero itself

how about the other intersections??

\((2n\pi,1)\) where \(n \) is the set of all integers

the other intersection is ( 2\Pi, 1)?

Yeah, you are right. So are we talking about polar coordinates?

\[\theta \le 2\Pi ?\]