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yaho021
 one year ago
Best ResponseYou've already chosen the best response.0\[x \neq \frac{ \Pi }{ 2 }, \frac{ 3\Pi }{ 2 }, \frac{ 5\Pi }{ 2 }, . . . . . . .\] \[range : y \ge 1 and y \le 1\]

hba
 one year ago
Best ResponseYou've already chosen the best response.0Ahm @yaho021 Domain=R{x=n(pi/2)} Where pi=1,3,5........ Couldn't get the range thing :/

hba
 one year ago
Best ResponseYou've already chosen the best response.0How do we determine the range ?

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.2\[\sec(x) = \dfrac{1}{\cos(x)}\]The range of values is \((\infty , \infty)\).

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.2I may be wrong... let's see

hba
 one year ago
Best ResponseYou've already chosen the best response.0Everyone is confusing me :/

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.2No, I meant when \(\cos(x)\) tends to \(0\) from the right side, then \(\sec(x) \) goes towards \(\infty\). And when it tends to \(0\) from the left, then \(\sec(x)\) goes towards \( \infty\).

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.2So the range is all real numbers.

hba
 one year ago
Best ResponseYou've already chosen the best response.0Okay someone said it would be All real numbers(1,1)

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.2That's the range of \(\cos(x)\), not \(\sec(x)\)

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.2Think about the range of \(\dfrac{1}{x}\). Whenever \(x\) is near zero, \(\dfrac{1}{x}\) is near infinity.

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.2\[\dfrac{1}{0.0000001} = 1000000\]

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.2YAY! I was right! I thought I'd make a fool of myself
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