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yaho021Best ResponseYou've already chosen the best response.0
\[x \neq \frac{ \Pi }{ 2 }, \frac{ 3\Pi }{ 2 }, \frac{ 5\Pi }{ 2 }, . . . . . . .\] \[range : y \ge 1 and y \le 1\]
 one year ago

hbaBest ResponseYou've already chosen the best response.0
Ahm @yaho021 Domain=R{x=n(pi/2)} Where pi=1,3,5........ Couldn't get the range thing :/
 one year ago

hbaBest ResponseYou've already chosen the best response.0
How do we determine the range ?
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
\[\sec(x) = \dfrac{1}{\cos(x)}\]The range of values is \((\infty , \infty)\).
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
I may be wrong... let's see
 one year ago

hbaBest ResponseYou've already chosen the best response.0
Everyone is confusing me :/
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
No, I meant when \(\cos(x)\) tends to \(0\) from the right side, then \(\sec(x) \) goes towards \(\infty\). And when it tends to \(0\) from the left, then \(\sec(x)\) goes towards \( \infty\).
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
So the range is all real numbers.
 one year ago

hbaBest ResponseYou've already chosen the best response.0
Okay someone said it would be All real numbers(1,1)
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
That's the range of \(\cos(x)\), not \(\sec(x)\)
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
Think about the range of \(\dfrac{1}{x}\). Whenever \(x\) is near zero, \(\dfrac{1}{x}\) is near infinity.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
\[\dfrac{1}{0.0000001} = 1000000\]
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.2
YAY! I was right! I thought I'd make a fool of myself
 one year ago
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