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bienes_joshua

  • 3 years ago

how many numbers between 25 and 400 are divisible by 11? what is their sum?

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  1. bienes_joshua
    • 3 years ago
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    who can answer?

  2. amistre64
    • 3 years ago
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    well, it starts with the number 33

  3. bienes_joshua
    • 3 years ago
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    can u pls show the equation sir???

  4. amistre64
    • 3 years ago
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    400-25 = 375 possible results divide that by ll 375/11 = 34.1 so ill assume there is like 34 numbers in that

  5. bienes_joshua
    • 3 years ago
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    and the sum sir?

  6. amistre64
    • 3 years ago
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    there sum can be determined by the expression 33+11n from n=0 to 34 most likely

  7. bienes_joshua
    • 3 years ago
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    wait sir... 33+11n=????

  8. sambhav__jain
    • 3 years ago
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    answer is 7480

  9. amistre64
    • 3 years ago
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    34 11 -- 34 34 ---- 374 11 ---- 385 11 ---- 396 .... found a few more

  10. amistre64
    • 3 years ago
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    pfft, for got to add 33 :) 374 +33 ---- 407 so it looks like 34 is too large and 33 is perfect 0 to 33

  11. sambhav__jain
    • 3 years ago
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    this time i am right i double checked it

  12. bienes_joshua
    • 3 years ago
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    can i ask for the solution sir??? because the solution is greatly needed

  13. amistre64
    • 3 years ago
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    33+11n i s a good expression yes since the first number divisible by 11 is 33

  14. bienes_joshua
    • 3 years ago
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    thanks sambhav

  15. bienes_joshua
    • 3 years ago
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    how to get the n sir???

  16. amistre64
    • 3 years ago
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    \[\sum_{0}^{33}33+11n=\frac{33}{2}(33+374)\]

  17. sambhav__jain
    • 3 years ago
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    a=33 l=396 d=11 n=(396-33/11)+1=35 sum=(35)(2(33)+34(11))/2 =7480 use the formula i gave u earlier

  18. amistre64
    • 3 years ago
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    http://www.wolframalpha.com/input/?i=table+%2833%2B11n%29%2C+n%3D0..33

  19. bienes_joshua
    • 3 years ago
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    thanks to to all of you friends :D

  20. amistre64
    • 3 years ago
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    the sum is 7293

  21. bienes_joshua
    • 3 years ago
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    why is sambhav answer is different?

  22. amistre64
    • 3 years ago
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    he most likely has a small error, or i do. but ive got the wolf to dbl chk me :) http://www.wolframalpha.com/input/?i=sum+%2833%2B11n%29%2C+n%3D0..33

  23. sambhav__jain
    • 3 years ago
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    hey @amistre64 ur formu;lla is correctbut ∑03333+11n=332(33+374) =6715.5

  24. amistre64
    • 3 years ago
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    yeah, 374 should have been 396 :) but i accounted for that afterwards

  25. sambhav__jain
    • 3 years ago
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    you used another website for help i used my mind

  26. amistre64
    • 3 years ago
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    at my age, the mind is not so good ;)

  27. bienes_joshua
    • 3 years ago
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    whats the correct answer monsieurs???

  28. amistre64
    • 3 years ago
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    i have to look at my left foot just to remember what color sock i need to put on the right foot :)

  29. sambhav__jain
    • 3 years ago
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    ∑03333+11n=(35/2)(33+396)=7507.5

  30. sambhav__jain
    • 3 years ago
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    whats ur age @amistre64

  31. amistre64
    • 3 years ago
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    .... pretty old

  32. bienes_joshua
    • 3 years ago
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    sambhav and amistre what again is the answer???

  33. amistre64
    • 3 years ago
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    7293 is what i get

  34. sambhav__jain
    • 3 years ago
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    pls wait for a minute pls sorry for the argument between us

  35. bienes_joshua
    • 3 years ago
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    its just ok no hard feelings

  36. amistre64
    • 3 years ago
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    0 to 33 is 34 numbers entotal 34(33+396)/2 = 7293

  37. bienes_joshua
    • 3 years ago
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    its right tnx for all your help ive got 2 numbers to go can u cooperate me or help me sir???

  38. amistre64
    • 3 years ago
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    between the both of us, we are sure to work out all the wrinkles ;)

  39. sambhav__jain
    • 3 years ago
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    @bienes_joshua the write answer is 7293

  40. bienes_joshua
    • 3 years ago
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    much thanks of all your help i just need to finish the 2 problems i will close this question and write a new one :D

  41. amistre64
    • 3 years ago
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    starting an index at 1 makes life easier on the count but adds a little bit of complexity to the expression; therefore a modification that is equal is:\[\sum_{1}^{34}33+11(n-1)\]

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