anonymous
  • anonymous
how many numbers between 25 and 400 are divisible by 11? what is their sum?
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
who can answer?
amistre64
  • amistre64
well, it starts with the number 33
anonymous
  • anonymous
can u pls show the equation sir???

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

amistre64
  • amistre64
400-25 = 375 possible results divide that by ll 375/11 = 34.1 so ill assume there is like 34 numbers in that
anonymous
  • anonymous
and the sum sir?
amistre64
  • amistre64
there sum can be determined by the expression 33+11n from n=0 to 34 most likely
anonymous
  • anonymous
wait sir... 33+11n=????
anonymous
  • anonymous
answer is 7480
amistre64
  • amistre64
34 11 -- 34 34 ---- 374 11 ---- 385 11 ---- 396 .... found a few more
amistre64
  • amistre64
pfft, for got to add 33 :) 374 +33 ---- 407 so it looks like 34 is too large and 33 is perfect 0 to 33
anonymous
  • anonymous
this time i am right i double checked it
anonymous
  • anonymous
can i ask for the solution sir??? because the solution is greatly needed
amistre64
  • amistre64
33+11n i s a good expression yes since the first number divisible by 11 is 33
anonymous
  • anonymous
thanks sambhav
anonymous
  • anonymous
how to get the n sir???
amistre64
  • amistre64
\[\sum_{0}^{33}33+11n=\frac{33}{2}(33+374)\]
anonymous
  • anonymous
a=33 l=396 d=11 n=(396-33/11)+1=35 sum=(35)(2(33)+34(11))/2 =7480 use the formula i gave u earlier
amistre64
  • amistre64
http://www.wolframalpha.com/input/?i=table+%2833%2B11n%29%2C+n%3D0..33
anonymous
  • anonymous
thanks to to all of you friends :D
amistre64
  • amistre64
the sum is 7293
anonymous
  • anonymous
why is sambhav answer is different?
amistre64
  • amistre64
he most likely has a small error, or i do. but ive got the wolf to dbl chk me :) http://www.wolframalpha.com/input/?i=sum+%2833%2B11n%29%2C+n%3D0..33
anonymous
  • anonymous
hey @amistre64 ur formu;lla is correctbut ∑03333+11n=332(33+374) =6715.5
amistre64
  • amistre64
yeah, 374 should have been 396 :) but i accounted for that afterwards
anonymous
  • anonymous
you used another website for help i used my mind
amistre64
  • amistre64
at my age, the mind is not so good ;)
anonymous
  • anonymous
whats the correct answer monsieurs???
amistre64
  • amistre64
i have to look at my left foot just to remember what color sock i need to put on the right foot :)
anonymous
  • anonymous
∑03333+11n=(35/2)(33+396)=7507.5
anonymous
  • anonymous
whats ur age @amistre64
amistre64
  • amistre64
.... pretty old
anonymous
  • anonymous
sambhav and amistre what again is the answer???
amistre64
  • amistre64
7293 is what i get
anonymous
  • anonymous
pls wait for a minute pls sorry for the argument between us
anonymous
  • anonymous
its just ok no hard feelings
amistre64
  • amistre64
0 to 33 is 34 numbers entotal 34(33+396)/2 = 7293
anonymous
  • anonymous
its right tnx for all your help ive got 2 numbers to go can u cooperate me or help me sir???
amistre64
  • amistre64
between the both of us, we are sure to work out all the wrinkles ;)
anonymous
  • anonymous
@bienes_joshua the write answer is 7293
anonymous
  • anonymous
much thanks of all your help i just need to finish the 2 problems i will close this question and write a new one :D
amistre64
  • amistre64
starting an index at 1 makes life easier on the count but adds a little bit of complexity to the expression; therefore a modification that is equal is:\[\sum_{1}^{34}33+11(n-1)\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.