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Nanoman
Group Title
Partial fractions question:
x^3

x^2 + 36x + 324
I used polynomial long division on this, and got: x+ 36 + 972x + 1166

x^2 + 36x + 324
I've gotten to the point where the partial fraction is 972x + 1166 = Ax 18A + B. A = 972, but I can't find out what B is.
 one year ago
 one year ago
Nanoman Group Title
Partial fractions question: x^3  x^2 + 36x + 324 I used polynomial long division on this, and got: x+ 36 + 972x + 1166  x^2 + 36x + 324 I've gotten to the point where the partial fraction is 972x + 1166 = Ax 18A + B. A = 972, but I can't find out what B is.
 one year ago
 one year ago

This Question is Closed

.Sam. Group TitleBest ResponseYou've already chosen the best response.4
What I get is\[x36+\frac{972x+11664}{x^2+36x+324}\]
 one year ago

Nanoman Group TitleBest ResponseYou've already chosen the best response.0
ohhh....right. I had that down on paper but typed it wrong on here.
 one year ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.4
dw:1362057398152:dw
 one year ago

hartnn Group TitleBest ResponseYou've already chosen the best response.0
to find out B, you can put x=0 in 972x + 1166 = Ax 18A + B. and you already know A , so you'll get B
 one year ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.4
\[x36+\frac{972x+11664}{x^2+36x+324} \\ \\\frac{972x+11664}{(x+18)^2}=\frac{A}{(x+18)}+\frac{B}{(x+18)^2}\]
 one year ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.4
\[972x+11664=A(x+18)+B \\ \\ \] When x=18 B=5832 When x=0 18A5832=11664 A=972 \[x36+\frac{972x+11664}{x^2+36x+324} \\ \\\frac{972x+11664}{(x+18)^2}=\frac{972}{(x+18)}\frac{5832}{(x+18)^2}\]
 one year ago

Nanoman Group TitleBest ResponseYou've already chosen the best response.0
Thanks Sam, I really appreciate it. I was trying to move the terms around to get the answer, but just plugging it in works well.
 one year ago
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