A community for students.
Here's the question you clicked on:
 0 viewing
Nanoman
 2 years ago
Partial fractions question:
x^3

x^2 + 36x + 324
I used polynomial long division on this, and got: x+ 36 + 972x + 1166

x^2 + 36x + 324
I've gotten to the point where the partial fraction is 972x + 1166 = Ax 18A + B. A = 972, but I can't find out what B is.
Nanoman
 2 years ago
Partial fractions question: x^3  x^2 + 36x + 324 I used polynomial long division on this, and got: x+ 36 + 972x + 1166  x^2 + 36x + 324 I've gotten to the point where the partial fraction is 972x + 1166 = Ax 18A + B. A = 972, but I can't find out what B is.

This Question is Closed

.Sam.
 2 years ago
Best ResponseYou've already chosen the best response.4What I get is\[x36+\frac{972x+11664}{x^2+36x+324}\]

Nanoman
 2 years ago
Best ResponseYou've already chosen the best response.0ohhh....right. I had that down on paper but typed it wrong on here.

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0to find out B, you can put x=0 in 972x + 1166 = Ax 18A + B. and you already know A , so you'll get B

.Sam.
 2 years ago
Best ResponseYou've already chosen the best response.4\[x36+\frac{972x+11664}{x^2+36x+324} \\ \\\frac{972x+11664}{(x+18)^2}=\frac{A}{(x+18)}+\frac{B}{(x+18)^2}\]

.Sam.
 2 years ago
Best ResponseYou've already chosen the best response.4\[972x+11664=A(x+18)+B \\ \\ \] When x=18 B=5832 When x=0 18A5832=11664 A=972 \[x36+\frac{972x+11664}{x^2+36x+324} \\ \\\frac{972x+11664}{(x+18)^2}=\frac{972}{(x+18)}\frac{5832}{(x+18)^2}\]

Nanoman
 2 years ago
Best ResponseYou've already chosen the best response.0Thanks Sam, I really appreciate it. I was trying to move the terms around to get the answer, but just plugging it in works well.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.