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hba

  • 2 years ago

Determine the following functions as even,odd or neither. (a) f(x)=|x| (b) f(x)=x+1 (c) f(x)=x^5-x/1+x

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  1. hartnn
    • 2 years ago
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    if f(x) = f(-x) then function is even

  2. hba
    • 2 years ago
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    Answers: (a)even (b)and (c)Neither

  3. ParthKohli
    • 2 years ago
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    \[f(x) =f(-x) \]Even^^\[f(x) = -f(x)\]Odd^

  4. hba
    • 2 years ago
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    Right or wrong?

  5. hartnn
    • 2 years ago
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    if f(-x)=-f(x) then function is odd

  6. hba
    • 2 years ago
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    I know all that -_-

  7. hba
    • 2 years ago
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    Just check my answers

  8. hartnn
    • 2 years ago
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    whats and ?

  9. ParthKohli
    • 2 years ago
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    Abs value function has \(f(x) = f(-x) \ \ \checkmark \)

  10. hartnn
    • 2 years ago
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    a and c are correct what about b?

  11. ParthKohli
    • 2 years ago
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    For second, \(f(x) \ne f(-x)\) and \(f(x) \ne - f(x)\) for all \(x\). What do you think?

  12. hba
    • 2 years ago
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    f(-x)=-x+1 so,Neither even nor odd

  13. hartnn
    • 2 years ago
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    correct.

  14. ParthKohli
    • 2 years ago
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    Yeah!

  15. hba
    • 2 years ago
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    Thanks for the help guys :)

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