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|dw:1362062634477:dw|
let the inner radius be r1 and outer be r2

\[\vec{\mathbf E}=\frac{Q}{4\pi \varepsilon_or^2}\hat{\mathbf r}\]

oh right,

And that the sphere is a Gaussian surface :P

But yes, definitely see your point.

What do you mean by 'and the sphere is a Gaussian surface' ?

oh i see the integral form of gauss's law is only for non symmetrical objects.

Why does the formula no longer hold when the shell tends to a solid sphere?