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TestTakingLifesaver
Group Title
Which expression represents the area of the triangle? base=2x+12, height x+7
A)
3x + 19
B)
3x2 + 84
C)
x2 + 13x + 42
D)
2x2 + 26x + 84
 one year ago
 one year ago
TestTakingLifesaver Group Title
Which expression represents the area of the triangle? base=2x+12, height x+7 A) 3x + 19 B) 3x2 + 84 C) x2 + 13x + 42 D) 2x2 + 26x + 84
 one year ago
 one year ago

This Question is Closed

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
A = bh/2 So, you would multiply the 2 expression for "b" and "h" (that are in "x") and divide by "2". Hint: It's easier to divide the "base" (or b) expression first by "2" and then simply multiply that by the expression for "h".
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
So, what is the expression for for the base divided by "2"?
 one year ago

TestTakingLifesaver Group TitleBest ResponseYou've already chosen the best response.0
1x+6
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
Very good. So, now, all you have to do is multiply your answer by "x + 7" (x + 6)(x + 7) = ?
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
Are you stuck?
 one year ago

TestTakingLifesaver Group TitleBest ResponseYou've already chosen the best response.0
46
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
When you have an expression like: (x + a)(x + b) It is: x(x + b) + a(x + b) = x^2 + bx + ax + ab = x^2 + (a + b)x + ab So, just substitute a = 6 and b = 7 in that last equation
 one year ago

TestTakingLifesaver Group TitleBest ResponseYou've already chosen the best response.0
thank you this is so confusing
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
Math can be, but if you take it step by step, it won't trick you. IMath is like a friend that speaks a foreign language.
 one year ago

TestTakingLifesaver Group TitleBest ResponseYou've already chosen the best response.0
i'll practice and see if i can learn the langage
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
That's a great attitude! You'll succeed if you stick with it. And you might want to go over that equality expansion a couple of times because it could clear things up for you.
 one year ago

TestTakingLifesaver Group TitleBest ResponseYou've already chosen the best response.0
ok thanks so much
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
You're very welcome and nice working with you!
 one year ago

tcarroll010 Group TitleBest ResponseYou've already chosen the best response.1
And thx for the recognition! @TestTakingLifesaver Good luck in all of your studies.
 one year ago
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