## A community for students. Sign up today

Here's the question you clicked on:

## emworden90 2 years ago Determine whether or not the following equation is exact, find the solution. If not, use an integrating factor to convert it into exact and solve it. 2e^(x/2 +y) - y + 2((xe ^(x/2 +y) + 1) )dy/dx = 0 , y(0) = 1

• This Question is Open
1. vf321

A DE is exact iff, when in the form $M dx + Ndy = 0$that $$\frac{\partial M}{\partial x} = \frac{\partial N}{\partial x}$$ because by Young's theorem this implies the existence of a relation $$\Psi(x, y) = C$$ which can in turn be solved for $$y$$.

2. UnkleRhaukus

$2e^{x/2 +y} - y + 2(xe ^{x/2 +y} + 1) \frac{\mathrm dy}{\mathrm dx} = 0$ $(2e^{x/2 +y} - y )\mathrm dx+ 2(xe ^{x/2 +y} + 1) \mathrm dy= 0$

#### Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy