A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 one year ago
Determine whether or not the following equation is exact, find the solution. If not, use an integrating factor to convert it into exact and solve it. 2e^(x/2 +y)  y + 2((xe ^(x/2 +y) + 1) )dy/dx = 0 , y(0) = 1
 one year ago
Determine whether or not the following equation is exact, find the solution. If not, use an integrating factor to convert it into exact and solve it. 2e^(x/2 +y)  y + 2((xe ^(x/2 +y) + 1) )dy/dx = 0 , y(0) = 1

This Question is Open

vf321
 one year ago
Best ResponseYou've already chosen the best response.1A DE is exact iff, when in the form \[M dx + Ndy = 0\]that \(\frac{\partial M}{\partial x} = \frac{\partial N}{\partial x}\) because by Young's theorem this implies the existence of a relation \(\Psi(x, y) = C\) which can in turn be solved for \(y\).

UnkleRhaukus
 one year ago
Best ResponseYou've already chosen the best response.0\[2e^{x/2 +y}  y + 2(xe ^{x/2 +y} + 1) \frac{\mathrm dy}{\mathrm dx} = 0\] \[(2e^{x/2 +y}  y )\mathrm dx+ 2(xe ^{x/2 +y} + 1) \mathrm dy= 0\]
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.