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spimentel

  • 3 years ago

F=mv2r ; for v v=±

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  1. .Sam.
    • 3 years ago
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    Is it \[F=\frac{mv^2}{r}\]

  2. spimentel
    • 3 years ago
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    yes

  3. .Sam.
    • 3 years ago
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    \[\left( \begin{array}{c} \text{Divide both sides by }\frac{ m }{r} \\ v^2=\frac{F r}{m} \\ \end{array} \right)\] \[\text{Take the \square \root of both sides}\] \[v= \pm \sqrt{\frac{F r}{m}}\]

  4. spimentel
    • 3 years ago
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    ohhhhh ok yea thats what i got, but it wasnt taking my answer so y typed in rf instead and i got it right thank u!:)

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