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Pologirl19Best ResponseYou've already chosen the best response.0
\[\sum_{x=1}^{10}6(2)^x\]
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
\[6\sum_{x=1}^{10}2^x\] is a start
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
\[\sum_{x=1}^{10}2^x=2^{11}2\]
 one year ago

Pologirl19Best ResponseYou've already chosen the best response.0
where did you get 2^11  2
 one year ago

General_GustavBest ResponseYou've already chosen the best response.0
The sum of this series involves factoring out the 6 into the front of the equation, like satellite73 said. I'm sure there is a shortcut to this, but i would write out each \[2^{x}\] term with n beginning with 1 and ending with 11 and then add them all together. Probably not the answer that you're looking for, but at least its a start.
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.0
\(\sum\limits_{x=1}^{10} 2^{x} = 2 + 2^{2} + 2^{3} + ... + 2^{10}\) Using the usual technique of creating a Sum and multiplying by the common factor, we get \(\dfrac{2  2^{11}}{1  2} = 2^{11}  1\)
 one year ago

General_GustavBest ResponseYou've already chosen the best response.0
^This is the shortcut I was mentioning. :D
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
in general \[\sum_{k=1}^n r^k = \frac{r^{n+1}r}{r1}\]
 one year ago

satellite73Best ResponseYou've already chosen the best response.0
in your case \(r=2\) so you get \[\frac{2^{11}2}{21}=2^{11}2\]
 one year ago

Pologirl19Best ResponseYou've already chosen the best response.0
That is none of my answers the equation for it is \[Sn=a1(\frac{ 1 r^n }{ 1  r })\]
 one year ago

tkhunnyBest ResponseYou've already chosen the best response.0
@Pologirl19 We ran into this problem the other day. 1) The ability to create the formula is worth far more than a list of formulas you don't understand. 2) If you had the formula all along, why didn't you use it? 3) A little flexibility and thought will produce n = 10, a1 = 2, and r = 2 and this is an equivalent expression. Please brush up on your algebra.
 one year ago
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