A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 one year ago
a batting machine launches a ball straight up in the air at a velocity of 100 ft/s. the machine is 65 feet tall what is the maximum height the ball can attain how fast will it be moving at this point?
 one year ago
a batting machine launches a ball straight up in the air at a velocity of 100 ft/s. the machine is 65 feet tall what is the maximum height the ball can attain how fast will it be moving at this point?

This Question is Open

vf321
 one year ago
Best ResponseYou've already chosen the best response.1Well, let's start from the top. It's important to be able to derive the equations you need for physics without relying on memorization. Do you know calculus?

vf321
 one year ago
Best ResponseYou've already chosen the best response.1Good. Assume that the ball, at any given moment, has constant acceleration \(a\). First, find a formula for \(v(t)\), the vertical velocity of the ball at any given time.

skeller2
 one year ago
Best ResponseYou've already chosen the best response.0I know that it needs to involve a (which would be negative due to gravity) and x over a certain period of time t. So \[v(t)=a(\int\limits_{0}^{t}xdt)\]?

vf321
 one year ago
Best ResponseYou've already chosen the best response.1Well don't worry about what the value of \(a\) yet (although you are right in that it is negative and the gravitational acceleration constant, which is \(g = 9.8 \text{m}/\text{s}^2\). Solving for \(v(t)\) should be easy. If the derivative (acceleration) is constant, then \(v(t) = a t + C\) right?

skeller2
 one year ago
Best ResponseYou've already chosen the best response.0Ugh! Yes. It has been so long since I have done any word problems like this and it frustrates me that I can't remember how to start them off. I am really trying to help my cousin with her homework :/

vf321
 one year ago
Best ResponseYou've already chosen the best response.1Ok. well, we still have on more timeintegral left. since this isn't for you, I'll just give you the solution: \(y = y_0 + v_0 t + a t^2/2\) I trust you can find approp. values for the constants, right?

skeller2
 one year ago
Best ResponseYou've already chosen the best response.0\[y_{0}=65 ft v _{0}=100ft/s \]

skeller2
 one year ago
Best ResponseYou've already chosen the best response.0Thank you so much for the help. I am clearly too tired after my own exams to be helping anyone else.

vf321
 one year ago
Best ResponseYou've already chosen the best response.1Yes @ your values. Max height can be found using singlederivative optimization (find where \(v(t) = 0\)).
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.