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mathlife

  • 3 years ago

find the Differential Equation of the given Family. Y= Ce^(2x) + e^(-2x)

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  1. abb0t
    • 3 years ago
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    Take the first and second derivative of the given solution.

  2. abb0t
    • 3 years ago
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    Then do a little substitution of y...

  3. vf321
    • 3 years ago
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    @mathlife You should really follow abb0t's advice. Do not expect us to give a solution for you.

  4. vf321
    • 3 years ago
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    If it worked out, close the question. If you are still having trouble, let us know.

  5. TuringTest
    • 3 years ago
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    there is a neat way to do it with matrices :)

  6. abb0t
    • 3 years ago
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    I don't think they should expect ANY answers for any math course above Calculus 1.

  7. abb0t
    • 3 years ago
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    @TuringTest HAHAHA i prefer to stay away from that route. Nope. No way.

  8. TuringTest
    • 3 years ago
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    aw, but it's really pretty cool and fast, plus it works for any set of exponents e^ax, e^bx

  9. vf321
    • 3 years ago
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    @TuringTest No need to make things more complicated... you may have to end up explaining matrix operations to OP.

  10. abb0t
    • 3 years ago
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    Can't you use Wronskian too?

  11. TuringTest
    • 3 years ago
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    Don't worry, I wasn't going to post, you abb0t has described enough no, much easier than the wronskian

  12. TuringTest
    • 3 years ago
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    no, because you don't get a square matrix

  13. vf321
    • 3 years ago
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    BTW guys I think @mathlife is leaving out some info - I can think of a first-order DE that satisfies this as well as the double-root second-order linear DE we're all thinking of...

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