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ok now idk how to graph it
to graph it take each side to be y= you have |x+3|>1 draw line y=x+3 then you know that because of the | | signs, your line is reflected so you only have a graph above the x axes. now draw the line y=1 then you want the region which y=|x+3| is greater than y=1
No, we're supposed to show the result on the number line, no y involved here
he said graph it I instantly thought of the actual graph my bad
Ooh, @stebie that's not correct. Try out x = -2 in the original inequality, does it satisfy it?
I just find the endpoints of the segments, then test a point to see whether the area between two endpoints, or between an endpoint and infinity is part of the solution set. I almost always use x=0 as a test point because the arithmetic is usually pretty trivial
but this has 4 pair of answers
@AonZ do you feel comfortable with this material now?
umm not with this question still
isn't this two questions?
no these 2 question should be solved together i think
it does say "solution sets"
Well, if you think they are combined, plot all of the endpoints (solutions to the equalities), then try test points in each segment, plus between the endpoints and infinity. If the test point satisfies both inequalities, then that portion of the number line should be shaded.