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AonZ Group Title

Represent the solution sets on the number line for |x+3|>1 and |2x+5| < 3

  • one year ago
  • one year ago

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  1. AonZ Group Title
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    @whpalmer4

    • one year ago
  2. AonZ Group Title
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    |dw:1362125049826:dw|

    • one year ago
  3. AonZ Group Title
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    |dw:1362125068647:dw|

    • one year ago
  4. AonZ Group Title
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    ok now idk how to graph it

    • one year ago
  5. amorfide Group Title
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    to graph it take each side to be y= you have |x+3|>1 draw line y=x+3 then you know that because of the | | signs, your line is reflected so you only have a graph above the x axes. now draw the line y=1 then you want the region which y=|x+3| is greater than y=1

    • one year ago
  6. whpalmer4 Group Title
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    No, we're supposed to show the result on the number line, no y involved here

    • one year ago
  7. Stebie Group Title
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    |dw:1362125192026:dw|

    • one year ago
  8. amorfide Group Title
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    he said graph it I instantly thought of the actual graph my bad

    • one year ago
  9. Stebie Group Title
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    |dw:1362125277366:dw|

    • one year ago
  10. whpalmer4 Group Title
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    Ooh, @stebie that's not correct. Try out x = -2 in the original inequality, does it satisfy it?

    • one year ago
  11. whpalmer4 Group Title
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    I just find the endpoints of the segments, then test a point to see whether the area between two endpoints, or between an endpoint and infinity is part of the solution set. I almost always use x=0 as a test point because the arithmetic is usually pretty trivial

    • one year ago
  12. AonZ Group Title
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    but this has 4 pair of answers

    • one year ago
  13. whpalmer4 Group Title
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    @AonZ do you feel comfortable with this material now?

    • one year ago
  14. AonZ Group Title
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    umm not with this question still

    • one year ago
  15. whpalmer4 Group Title
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    isn't this two questions?

    • one year ago
  16. AonZ Group Title
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    no these 2 question should be solved together i think

    • one year ago
  17. whpalmer4 Group Title
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    it does say "solution sets"

    • one year ago
  18. whpalmer4 Group Title
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    Well, if you think they are combined, plot all of the endpoints (solutions to the equalities), then try test points in each segment, plus between the endpoints and infinity. If the test point satisfies both inequalities, then that portion of the number line should be shaded.

    • one year ago
  19. AonZ Group Title
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    ok thanks

    • one year ago
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