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 one year ago
Using sigma notation, describe the total length of 7 pictures hung sidebyside. Then find the total length the pictures occupy along the wall if the first picture has a length of 10 inches and the length of each successive picture is 4 inches longer than the previous one.
 one year ago
Using sigma notation, describe the total length of 7 pictures hung sidebyside. Then find the total length the pictures occupy along the wall if the first picture has a length of 10 inches and the length of each successive picture is 4 inches longer than the previous one.

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hartnn
 one year ago
Best ResponseYou've already chosen the best response.0let l1 to l7 be length of pics. from n=1 to 7, l_n and sum notation : \(\sum \limits_{n=1}^7l_n\) is your 1st part.

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1Hint: for the first part, denote the length of the seven pictures by a sequence \(a_1, a_2 \cdots a_7\)

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0l1 =10 and common difference d =4

yummydum
 one year ago
Best ResponseYou've already chosen the best response.2rightI got that but for the equation..?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0you need to find n'th tern l_n with l_1 =10 , d = 4 \(l_n = l_1+(n1)d\)

yummydum
 one year ago
Best ResponseYou've already chosen the best response.210, 14, 18,..\[a_n=(10)(n1)(4)\]\[a_n=104n+4\]\[a_n=144n\]\[\sum_{n=1}^{7}~14n4\]yes?

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0middle sign is + ln = 6+4n

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0now can you solve the summation ?

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1The worst pain, after the famines and diseases, is typing on an iPad. :(

hartnn
 one year ago
Best ResponseYou've already chosen the best response.0know whats \(\sum n=..?\)

yummydum
 one year ago
Best ResponseYou've already chosen the best response.2wow it wrote that weird.. \[\large\sum_{n=1}^{7} ~6+4n~~ \implies~~154\]

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1I don't know, just pointing out that a common mistake students sometimes make is that they do \(\sum 6 = 6\) when it's not.

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1You didn't make that mistake though, nice :)

yummydum
 one year ago
Best ResponseYou've already chosen the best response.2err..what? i did \([6+(4\times1)]+[6+(4\times2)]+[6+(4\times3)]+\)\([6+(4\times4)]+[6+(4\times5)]+[6+(4\times6)]+[6+(4\times7)]\)

yummydum
 one year ago
Best ResponseYou've already chosen the best response.210+14+18+22+26+30+34=154.....yup :)

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1I never said you were wrong lol, just pointing out a common mistake.

yummydum
 one year ago
Best ResponseYou've already chosen the best response.210+14+18+22+26+30+34=154 ....is that not right?
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