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anonymous
 3 years ago
Using sigma notation, describe the total length of 7 pictures hung sidebyside. Then find the total length the pictures occupy along the wall if the first picture has a length of 10 inches and the length of each successive picture is 4 inches longer than the previous one.
anonymous
 3 years ago
Using sigma notation, describe the total length of 7 pictures hung sidebyside. Then find the total length the pictures occupy along the wall if the first picture has a length of 10 inches and the length of each successive picture is 4 inches longer than the previous one.

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hartnn
 3 years ago
Best ResponseYou've already chosen the best response.0let l1 to l7 be length of pics. from n=1 to 7, l_n and sum notation : \(\sum \limits_{n=1}^7l_n\) is your 1st part.

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.1Hint: for the first part, denote the length of the seven pictures by a sequence \(a_1, a_2 \cdots a_7\)

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.0l1 =10 and common difference d =4

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0rightI got that but for the equation..?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.0you need to find n'th tern l_n with l_1 =10 , d = 4 \(l_n = l_1+(n1)d\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.010, 14, 18,..\[a_n=(10)(n1)(4)\]\[a_n=104n+4\]\[a_n=144n\]\[\sum_{n=1}^{7}~14n4\]yes?

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.0middle sign is + ln = 6+4n

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.0now can you solve the summation ?

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.1The worst pain, after the famines and diseases, is typing on an iPad. :(

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.0know whats \(\sum n=..?\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0wow it wrote that weird.. \[\large\sum_{n=1}^{7} ~6+4n~~ \implies~~154\]

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.1I don't know, just pointing out that a common mistake students sometimes make is that they do \(\sum 6 = 6\) when it's not.

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.1You didn't make that mistake though, nice :)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0err..what? i did \([6+(4\times1)]+[6+(4\times2)]+[6+(4\times3)]+\)\([6+(4\times4)]+[6+(4\times5)]+[6+(4\times6)]+[6+(4\times7)]\)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.010+14+18+22+26+30+34=154.....yup :)

ParthKohli
 3 years ago
Best ResponseYou've already chosen the best response.1I never said you were wrong lol, just pointing out a common mistake.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.010+14+18+22+26+30+34=154 ....is that not right?
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