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Using sigma notation, describe the total length of 7 pictures hung sidebyside. Then find the total length the pictures occupy along the wall if the first picture has a length of 10 inches and the length of each successive picture is 4 inches longer than the previous one.
 one year ago
 one year ago
Using sigma notation, describe the total length of 7 pictures hung sidebyside. Then find the total length the pictures occupy along the wall if the first picture has a length of 10 inches and the length of each successive picture is 4 inches longer than the previous one.
 one year ago
 one year ago

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hartnnBest ResponseYou've already chosen the best response.0
let l1 to l7 be length of pics. from n=1 to 7, l_n and sum notation : \(\sum \limits_{n=1}^7l_n\) is your 1st part.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
Hint: for the first part, denote the length of the seven pictures by a sequence \(a_1, a_2 \cdots a_7\)
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
l1 =10 and common difference d =4
 one year ago

yummydumBest ResponseYou've already chosen the best response.2
rightI got that but for the equation..?
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
you need to find n'th tern l_n with l_1 =10 , d = 4 \(l_n = l_1+(n1)d\)
 one year ago

yummydumBest ResponseYou've already chosen the best response.2
10, 14, 18,..\[a_n=(10)(n1)(4)\]\[a_n=104n+4\]\[a_n=144n\]\[\sum_{n=1}^{7}~14n4\]yes?
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
middle sign is + ln = 6+4n
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
now can you solve the summation ?
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
The worst pain, after the famines and diseases, is typing on an iPad. :(
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
know whats \(\sum n=..?\)
 one year ago

yummydumBest ResponseYou've already chosen the best response.2
wow it wrote that weird.. \[\large\sum_{n=1}^{7} ~6+4n~~ \implies~~154\]
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
I don't know, just pointing out that a common mistake students sometimes make is that they do \(\sum 6 = 6\) when it's not.
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
You didn't make that mistake though, nice :)
 one year ago

yummydumBest ResponseYou've already chosen the best response.2
err..what? i did \([6+(4\times1)]+[6+(4\times2)]+[6+(4\times3)]+\)\([6+(4\times4)]+[6+(4\times5)]+[6+(4\times6)]+[6+(4\times7)]\)
 one year ago

yummydumBest ResponseYou've already chosen the best response.2
10+14+18+22+26+30+34=154.....yup :)
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.1
I never said you were wrong lol, just pointing out a common mistake.
 one year ago

yummydumBest ResponseYou've already chosen the best response.2
10+14+18+22+26+30+34=154 ....is that not right?
 one year ago
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