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that1chick
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Describe the differences between the graph of y = –3(x + 7)^2 – 10 and the standard position graph of y = x^2.
 one year ago
 one year ago
that1chick Group Title
Describe the differences between the graph of y = –3(x + 7)^2 – 10 and the standard position graph of y = x^2.
 one year ago
 one year ago

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that1chick Group TitleBest ResponseYou've already chosen the best response.0
Nevermind, I figured it out. (:
 one year ago

that1chick Group TitleBest ResponseYou've already chosen the best response.0
y=–3(x+7)^2–10 is in General Form, while y=x^2 is Simplest Form. When finding the points to plot for the one in General Form I got the points: (9,22), (8,13), (7,10) Vertex, (6,13), and (5,22). This graph obviously opens downward, making the vertex at (7,10) the maximum (or highest) point. I then substituted the values 2, 1, 0, 1, 2 into the Simplest Form equation. The points I got were: (2,4), (1,1), (0,0) Vertex, (1,1), (2,4). This graph opens upward with the vertex (0,0) being the lowest point. Therefore, the difference is that y=–3(x+7)^2–10 opens downward with the vertex being the highest point and y=x^2 opens upward with the vertex being the lowest point.
 one year ago

that1chick Group TitleBest ResponseYou've already chosen the best response.0
Sound right?
 one year ago

DarkgasherBeyblade Group TitleBest ResponseYou've already chosen the best response.0
Its FINE
 one year ago

that1chick Group TitleBest ResponseYou've already chosen the best response.0
Fine as in correct?
 one year ago

yrelhan4 Group TitleBest ResponseYou've already chosen the best response.1
looks good.
 one year ago

that1chick Group TitleBest ResponseYou've already chosen the best response.0
Thank you
 one year ago
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