Describe the differences between the graph of y = –3(x + 7)^2 – 10 and the standard position graph of y = x^2.

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Describe the differences between the graph of y = –3(x + 7)^2 – 10 and the standard position graph of y = x^2.

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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Nevermind, I figured it out. (:
y=–3(x+7)^2–10 is in General Form, while y=x^2 is Simplest Form. When finding the points to plot for the one in General Form I got the points: (-9,-22), (-8,-13), (-7,-10) Vertex, (-6,-13), and (-5,-22). This graph obviously opens downward, making the vertex at (-7,-10) the maximum (or highest) point. I then substituted the values -2, -1, 0, 1, 2 into the Simplest Form equation. The points I got were: (2,4), (1,1), (0,0) Vertex, (-1,1), (-2,4). This graph opens upward with the vertex (0,0) being the lowest point. Therefore, the difference is that y=–3(x+7)^2–10 opens downward with the vertex being the highest point and y=x^2 opens upward with the vertex being the lowest point.
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Its FINE
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