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Describe the differences between the graph of y = –3(x + 7)^2 – 10 and the standard position graph of y = x^2.
 one year ago
 one year ago
Describe the differences between the graph of y = –3(x + 7)^2 – 10 and the standard position graph of y = x^2.
 one year ago
 one year ago

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that1chickBest ResponseYou've already chosen the best response.0
Nevermind, I figured it out. (:
 one year ago

that1chickBest ResponseYou've already chosen the best response.0
y=–3(x+7)^2–10 is in General Form, while y=x^2 is Simplest Form. When finding the points to plot for the one in General Form I got the points: (9,22), (8,13), (7,10) Vertex, (6,13), and (5,22). This graph obviously opens downward, making the vertex at (7,10) the maximum (or highest) point. I then substituted the values 2, 1, 0, 1, 2 into the Simplest Form equation. The points I got were: (2,4), (1,1), (0,0) Vertex, (1,1), (2,4). This graph opens upward with the vertex (0,0) being the lowest point. Therefore, the difference is that y=–3(x+7)^2–10 opens downward with the vertex being the highest point and y=x^2 opens upward with the vertex being the lowest point.
 one year ago

that1chickBest ResponseYou've already chosen the best response.0
Fine as in correct?
 one year ago
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