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shubhamsrg
 2 years ago
Time pass ques:
Use 5 zeroes with any mathematical functions to arrive at 14.
PS: This has a lame solution. _
shubhamsrg
 2 years ago
Time pass ques: Use 5 zeroes with any mathematical functions to arrive at 14. PS: This has a lame solution. _

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Voidus
 2 years ago
Best ResponseYou've already chosen the best response.0f(x) = x  100000 f(10014) = 14

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.0Let \(f(n) = n + 14\). Then \(f(0 + 0 + 0 + 0 + 0) = 14\)

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.0My solution is lamer!

mathstudent55
 2 years ago
Best ResponseYou've already chosen the best response.0f(x) = 1400000x f(0.00001) = 14 I used 5 zeros twice :)

Meepi
 2 years ago
Best ResponseYou've already chosen the best response.1S(S(S(S(S(S(S(S(S(S(S(S(S(S(0+0+0+0+0)))))))))))))) This one is the lamest :D

shubhamsrg
 2 years ago
Best ResponseYou've already chosen the best response.1what is this anyways ?

Meepi
 2 years ago
Best ResponseYou've already chosen the best response.1or \(p_{0!}p_{0!+0!+0!+0!}\), where \(p_n\) denotes the nth prime?

Meepi
 2 years ago
Best ResponseYou've already chosen the best response.1S(n) = n + 1, succesor function

shubhamsrg
 2 years ago
Best ResponseYou've already chosen the best response.1aha..hmm I won;t say thats more lame, I'd say thats equally lame relative to my soln.! _

shubhamsrg
 2 years ago
Best ResponseYou've already chosen the best response.1but still, its cool.. B

ParthKohli
 2 years ago
Best ResponseYou've already chosen the best response.0So the answer is...\[\left\lfloor \tan\left(\dfrac{0! + 0! + 0!}{0! + 0!}\right)\right\rfloor\]
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