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shubhamsrg

  • 3 years ago

Time pass ques: Use 5 zeroes with any mathematical functions to arrive at 14. PS: This has a lame solution. -_-

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  1. Voidus
    • 3 years ago
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    f(x) = x - 100000 f(10014) = 14

  2. shubhamsrg
    • 3 years ago
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    cool.. B|

  3. shubhamsrg
    • 3 years ago
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    But NO :|

  4. ParthKohli
    • 3 years ago
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    Let \(f(n) = n + 14\). Then \(f(0 + 0 + 0 + 0 + 0) = 14\)

  5. ParthKohli
    • 3 years ago
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    B-)

  6. ParthKohli
    • 3 years ago
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    My solution is lamer!

  7. shubhamsrg
    • 3 years ago
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    -_-

  8. mathstudent55
    • 3 years ago
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    f(x) = 1400000x f(0.00001) = 14 I used 5 zeros twice :-)

  9. shubhamsrg
    • 3 years ago
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    good for you :)

  10. Meepi
    • 3 years ago
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    S(S(S(S(S(S(S(S(S(S(S(S(S(S(0+0+0+0+0)))))))))))))) This one is the lamest :D

  11. shubhamsrg
    • 3 years ago
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    what is this anyways ?

  12. Meepi
    • 3 years ago
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    or \(p_{0!}p_{0!+0!+0!+0!}\), where \(p_n\) denotes the nth prime?

  13. Meepi
    • 3 years ago
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    S(n) = n + 1, succesor function

  14. shubhamsrg
    • 3 years ago
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    aha..hmm I won;t say thats more lame, I'd say thats equally lame relative to my soln.! -_-

  15. shubhamsrg
    • 3 years ago
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    but still, its cool.. B|

  16. Meepi
    • 3 years ago
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    What's your solution? :p

  17. shubhamsrg
    • 3 years ago
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    I'll message you.

  18. ParthKohli
    • 3 years ago
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    So the answer is...\[\left\lfloor \tan\left(\dfrac{0! + 0! + 0!}{0! + 0!}\right)\right\rfloor\]

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