Atkinsoha
PreCalc & Trig Help!
Picture below.
I did one like this already, but for some reason I just can't figure this one out. :/
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Atkinsoha
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Hoa
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B
Atkinsoha
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can you tell me how you found that so i know for the rest of the ones like it ?
Hoa
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let x= o-->sin(o) =0 and 2x=0 ---> sin2x =0 . you can conclude that sinx = sin2x when x =0.
other solutions are not right because there are some pairs not satisfy sinx =sin2x.
Atkinsoha
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Okay, thank you.
Hoa
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for example: in A)if x =pi/2---> sin(pi,2) = 1 but sin 2(pi/2) = sinpi=0
Hoa
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ok, I'm glad you understand
Atkinsoha
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yup thanks!