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Atkinsoha
Group Title
PreCalc & Trig, picture below, please show your work..
Really frustrated with this homework. :/
 one year ago
 one year ago
Atkinsoha Group Title
PreCalc & Trig, picture below, please show your work.. Really frustrated with this homework. :/
 one year ago
 one year ago

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ghass1978 Group TitleBest ResponseYou've already chosen the best response.0
use sinx=2sin(x/2)cos(x/2) then factorize
 one year ago

Atkinsoha Group TitleBest ResponseYou've already chosen the best response.0
Maybe I should tell you this: I haven't been in class for over a week. I don't know any of this stuff.. so be as simple and thorough as you can, thanks.
 one year ago

getusel Group TitleBest ResponseYou've already chosen the best response.1
\[\cos(\frac{ x }{ 2 })sinx=0\] use the identity sin2x=2sinxcosx \[\cos(x/2)2\sin(x/2)\cos(x/2)=0\] \[\cos(x/2)(1\sin(x/2))=0\] cos(x/2)=0 or 1sin(x/2)=0 \[\cos(x/2)=0 => x/2=\pi/2 \] \[x=\pi\] \[1\sin(\frac{ x }{ 2 })=0\]
 one year ago

getusel Group TitleBest ResponseYou've already chosen the best response.1
\[\sin(\frac{ x }{ 2 })=1 => \frac{ x }{ 2 }=\pi/2\] \[x=\pi\]
 one year ago

getusel Group TitleBest ResponseYou've already chosen the best response.1
the solution is \[\pi\]
 one year ago

Atkinsoha Group TitleBest ResponseYou've already chosen the best response.0
okay, thank you.
 one year ago
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